YES
* Step 1: TrivialSCCs YES
    + Considered Problem:
        Rules:
          0. evalwcet2start(A,B)    -> evalwcet2entryin(A,B)   True                                                               (1,1)
          1. evalwcet2entryin(A,B)  -> evalwcet2bb5in(A,B)     True                                                               (?,1)
          2. evalwcet2bb5in(A,B)    -> evalwcet2bb2in(A,0)     [4 >= A]                                                           (?,1)
          3. evalwcet2bb5in(A,B)    -> evalwcet2returnin(A,B)  [A >= 5]                                                           (?,1)
          4. evalwcet2bb2in(A,B)    -> evalwcet2bb1in(A,B)     [B >= 0 && 4 + -1*A + B >= 0 && 4 + -1*A >= 0 && A >= 3 && 9 >= B] (?,1)
          5. evalwcet2bb2in(A,B)    -> evalwcet2bb4in(A,B)     [B >= 0 && 4 + -1*A + B >= 0 && 4 + -1*A >= 0 && 2 >= A]           (?,1)
          6. evalwcet2bb2in(A,B)    -> evalwcet2bb4in(A,B)     [B >= 0 && 4 + -1*A + B >= 0 && 4 + -1*A >= 0 && B >= 10]          (?,1)
          7. evalwcet2bb1in(A,B)    -> evalwcet2bb2in(A,1 + B) [9 + -1*B >= 0                                                     (?,1)
                                                                && 6 + A + -1*B >= 0                                                   
                                                                && 13 + -1*A + -1*B >= 0                                               
                                                                && B >= 0                                                              
                                                                && -3 + A + B >= 0                                                     
                                                                && 4 + -1*A + B >= 0                                                   
                                                                && 4 + -1*A >= 0                                                       
                                                                && -3 + A >= 0]                                                        
          8. evalwcet2bb4in(A,B)    -> evalwcet2bb5in(1 + A,B) [B >= 0 && 2 + -1*A + B >= 0 && 4 + -1*A >= 0]                     (?,1)
          9. evalwcet2returnin(A,B) -> evalwcet2stop(A,B)      [-5 + A >= 0]                                                      (?,1)
        Signature:
          {(evalwcet2bb1in,2)
          ;(evalwcet2bb2in,2)
          ;(evalwcet2bb4in,2)
          ;(evalwcet2bb5in,2)
          ;(evalwcet2entryin,2)
          ;(evalwcet2returnin,2)
          ;(evalwcet2start,2)
          ;(evalwcet2stop,2)}
        Flow Graph:
          [0->{1},1->{2,3},2->{4,5,6},3->{9},4->{7},5->{8},6->{8},7->{4,5,6},8->{2,3},9->{}]
        
    + Applied Processor:
        TrivialSCCs
    + Details:
        All trivial SCCs of the transition graph admit timebound 1.
* Step 2: UnsatPaths YES
    + Considered Problem:
        Rules:
          0. evalwcet2start(A,B)    -> evalwcet2entryin(A,B)   True                                                               (1,1)
          1. evalwcet2entryin(A,B)  -> evalwcet2bb5in(A,B)     True                                                               (1,1)
          2. evalwcet2bb5in(A,B)    -> evalwcet2bb2in(A,0)     [4 >= A]                                                           (?,1)
          3. evalwcet2bb5in(A,B)    -> evalwcet2returnin(A,B)  [A >= 5]                                                           (1,1)
          4. evalwcet2bb2in(A,B)    -> evalwcet2bb1in(A,B)     [B >= 0 && 4 + -1*A + B >= 0 && 4 + -1*A >= 0 && A >= 3 && 9 >= B] (?,1)
          5. evalwcet2bb2in(A,B)    -> evalwcet2bb4in(A,B)     [B >= 0 && 4 + -1*A + B >= 0 && 4 + -1*A >= 0 && 2 >= A]           (?,1)
          6. evalwcet2bb2in(A,B)    -> evalwcet2bb4in(A,B)     [B >= 0 && 4 + -1*A + B >= 0 && 4 + -1*A >= 0 && B >= 10]          (?,1)
          7. evalwcet2bb1in(A,B)    -> evalwcet2bb2in(A,1 + B) [9 + -1*B >= 0                                                     (?,1)
                                                                && 6 + A + -1*B >= 0                                                   
                                                                && 13 + -1*A + -1*B >= 0                                               
                                                                && B >= 0                                                              
                                                                && -3 + A + B >= 0                                                     
                                                                && 4 + -1*A + B >= 0                                                   
                                                                && 4 + -1*A >= 0                                                       
                                                                && -3 + A >= 0]                                                        
          8. evalwcet2bb4in(A,B)    -> evalwcet2bb5in(1 + A,B) [B >= 0 && 2 + -1*A + B >= 0 && 4 + -1*A >= 0]                     (?,1)
          9. evalwcet2returnin(A,B) -> evalwcet2stop(A,B)      [-5 + A >= 0]                                                      (1,1)
        Signature:
          {(evalwcet2bb1in,2)
          ;(evalwcet2bb2in,2)
          ;(evalwcet2bb4in,2)
          ;(evalwcet2bb5in,2)
          ;(evalwcet2entryin,2)
          ;(evalwcet2returnin,2)
          ;(evalwcet2start,2)
          ;(evalwcet2stop,2)}
        Flow Graph:
          [0->{1},1->{2,3},2->{4,5,6},3->{9},4->{7},5->{8},6->{8},7->{4,5,6},8->{2,3},9->{}]
        
    + Applied Processor:
        UnsatPaths
    + Details:
        We remove following edges from the transition graph: [(2,6),(7,5)]
* Step 3: Looptree YES
    + Considered Problem:
        Rules:
          0. evalwcet2start(A,B)    -> evalwcet2entryin(A,B)   True                                                               (1,1)
          1. evalwcet2entryin(A,B)  -> evalwcet2bb5in(A,B)     True                                                               (1,1)
          2. evalwcet2bb5in(A,B)    -> evalwcet2bb2in(A,0)     [4 >= A]                                                           (?,1)
          3. evalwcet2bb5in(A,B)    -> evalwcet2returnin(A,B)  [A >= 5]                                                           (1,1)
          4. evalwcet2bb2in(A,B)    -> evalwcet2bb1in(A,B)     [B >= 0 && 4 + -1*A + B >= 0 && 4 + -1*A >= 0 && A >= 3 && 9 >= B] (?,1)
          5. evalwcet2bb2in(A,B)    -> evalwcet2bb4in(A,B)     [B >= 0 && 4 + -1*A + B >= 0 && 4 + -1*A >= 0 && 2 >= A]           (?,1)
          6. evalwcet2bb2in(A,B)    -> evalwcet2bb4in(A,B)     [B >= 0 && 4 + -1*A + B >= 0 && 4 + -1*A >= 0 && B >= 10]          (?,1)
          7. evalwcet2bb1in(A,B)    -> evalwcet2bb2in(A,1 + B) [9 + -1*B >= 0                                                     (?,1)
                                                                && 6 + A + -1*B >= 0                                                   
                                                                && 13 + -1*A + -1*B >= 0                                               
                                                                && B >= 0                                                              
                                                                && -3 + A + B >= 0                                                     
                                                                && 4 + -1*A + B >= 0                                                   
                                                                && 4 + -1*A >= 0                                                       
                                                                && -3 + A >= 0]                                                        
          8. evalwcet2bb4in(A,B)    -> evalwcet2bb5in(1 + A,B) [B >= 0 && 2 + -1*A + B >= 0 && 4 + -1*A >= 0]                     (?,1)
          9. evalwcet2returnin(A,B) -> evalwcet2stop(A,B)      [-5 + A >= 0]                                                      (1,1)
        Signature:
          {(evalwcet2bb1in,2)
          ;(evalwcet2bb2in,2)
          ;(evalwcet2bb4in,2)
          ;(evalwcet2bb5in,2)
          ;(evalwcet2entryin,2)
          ;(evalwcet2returnin,2)
          ;(evalwcet2start,2)
          ;(evalwcet2stop,2)}
        Flow Graph:
          [0->{1},1->{2,3},2->{4,5},3->{9},4->{7},5->{8},6->{8},7->{4,6},8->{2,3},9->{}]
        
    + Applied Processor:
        Looptree
    + Details:
        We construct a looptree:
          P: [0,1,2,3,4,5,6,7,8,9]
          |
          `- p:[2,8,5,6,7,4] c: [8]
             |
             `- p:[4,7] c: [7]

YES