YES
* Step 1: TrivialSCCs YES
    + Considered Problem:
        Rules:
          0. evalspeedpldi2start(A,B,C)    -> evalspeedpldi2entryin(A,B,C)        True                                                                                                      (1,1)
          1. evalspeedpldi2entryin(A,B,C)  -> evalspeedpldi2bb5in(B,0,A)          [A >= 0 && B >= 1]                                                                                        (?,1)
          2. evalspeedpldi2entryin(A,B,C)  -> evalspeedpldi2returnin(A,B,C)       [0 >= 1 + A]                                                                                              (?,1)
          3. evalspeedpldi2entryin(A,B,C)  -> evalspeedpldi2returnin(A,B,C)       [0 >= B]                                                                                                  (?,1)
          4. evalspeedpldi2bb5in(A,B,C)    -> evalspeedpldi2bb2in(A,B,C)          [C >= 0 && B + C >= 0 && -1 + A + C >= 0 && B >= 0 && -1 + A + B >= 0 && -1 + A >= 0 && C >= 1]           (?,1)
          5. evalspeedpldi2bb5in(A,B,C)    -> evalspeedpldi2returnin(A,B,C)       [C >= 0 && B + C >= 0 && -1 + A + C >= 0 && B >= 0 && -1 + A + B >= 0 && -1 + A >= 0 && 0 >= C]           (?,1)
          6. evalspeedpldi2bb2in(A,B,C)    -> evalspeedpldi2bb3in(A,B,C)          [-1 + C >= 0                                                                                              (?,1)
                                                                                   && -1 + B + C >= 0                                                                                            
                                                                                   && -2 + A + C >= 0                                                                                            
                                                                                   && B >= 0                                                                                                     
                                                                                   && -1 + A + B >= 0                                                                                            
                                                                                   && -1 + A >= 0                                                                                                
                                                                                   && A >= 1 + B]                                                                                                
          7. evalspeedpldi2bb2in(A,B,C)    -> evalspeedpldi2bb5in(A,0,C)          [-1 + C >= 0 && -1 + B + C >= 0 && -2 + A + C >= 0 && B >= 0 && -1 + A + B >= 0 && -1 + A >= 0 && B >= A] (?,1)
          8. evalspeedpldi2bb3in(A,B,C)    -> evalspeedpldi2bb5in(A,1 + B,-1 + C) [-1 + C >= 0                                                                                              (?,1)
                                                                                   && -1 + B + C >= 0                                                                                            
                                                                                   && -2 + A + C >= 0                                                                                            
                                                                                   && -1 + A + -1*B >= 0                                                                                         
                                                                                   && B >= 0                                                                                                     
                                                                                   && -1 + A + B >= 0                                                                                            
                                                                                   && -1 + A >= 0]                                                                                               
          9. evalspeedpldi2returnin(A,B,C) -> evalspeedpldi2stop(A,B,C)           True                                                                                                      (?,1)
        Signature:
          {(evalspeedpldi2bb2in,3)
          ;(evalspeedpldi2bb3in,3)
          ;(evalspeedpldi2bb5in,3)
          ;(evalspeedpldi2entryin,3)
          ;(evalspeedpldi2returnin,3)
          ;(evalspeedpldi2start,3)
          ;(evalspeedpldi2stop,3)}
        Flow Graph:
          [0->{1,2,3},1->{4,5},2->{9},3->{9},4->{6,7},5->{9},6->{8},7->{4,5},8->{4,5},9->{}]
        
    + Applied Processor:
        TrivialSCCs
    + Details:
        All trivial SCCs of the transition graph admit timebound 1.
* Step 2: UnsatPaths YES
    + Considered Problem:
        Rules:
          0. evalspeedpldi2start(A,B,C)    -> evalspeedpldi2entryin(A,B,C)        True                                                                                                      (1,1)
          1. evalspeedpldi2entryin(A,B,C)  -> evalspeedpldi2bb5in(B,0,A)          [A >= 0 && B >= 1]                                                                                        (1,1)
          2. evalspeedpldi2entryin(A,B,C)  -> evalspeedpldi2returnin(A,B,C)       [0 >= 1 + A]                                                                                              (1,1)
          3. evalspeedpldi2entryin(A,B,C)  -> evalspeedpldi2returnin(A,B,C)       [0 >= B]                                                                                                  (1,1)
          4. evalspeedpldi2bb5in(A,B,C)    -> evalspeedpldi2bb2in(A,B,C)          [C >= 0 && B + C >= 0 && -1 + A + C >= 0 && B >= 0 && -1 + A + B >= 0 && -1 + A >= 0 && C >= 1]           (?,1)
          5. evalspeedpldi2bb5in(A,B,C)    -> evalspeedpldi2returnin(A,B,C)       [C >= 0 && B + C >= 0 && -1 + A + C >= 0 && B >= 0 && -1 + A + B >= 0 && -1 + A >= 0 && 0 >= C]           (1,1)
          6. evalspeedpldi2bb2in(A,B,C)    -> evalspeedpldi2bb3in(A,B,C)          [-1 + C >= 0                                                                                              (?,1)
                                                                                   && -1 + B + C >= 0                                                                                            
                                                                                   && -2 + A + C >= 0                                                                                            
                                                                                   && B >= 0                                                                                                     
                                                                                   && -1 + A + B >= 0                                                                                            
                                                                                   && -1 + A >= 0                                                                                                
                                                                                   && A >= 1 + B]                                                                                                
          7. evalspeedpldi2bb2in(A,B,C)    -> evalspeedpldi2bb5in(A,0,C)          [-1 + C >= 0 && -1 + B + C >= 0 && -2 + A + C >= 0 && B >= 0 && -1 + A + B >= 0 && -1 + A >= 0 && B >= A] (?,1)
          8. evalspeedpldi2bb3in(A,B,C)    -> evalspeedpldi2bb5in(A,1 + B,-1 + C) [-1 + C >= 0                                                                                              (?,1)
                                                                                   && -1 + B + C >= 0                                                                                            
                                                                                   && -2 + A + C >= 0                                                                                            
                                                                                   && -1 + A + -1*B >= 0                                                                                         
                                                                                   && B >= 0                                                                                                     
                                                                                   && -1 + A + B >= 0                                                                                            
                                                                                   && -1 + A >= 0]                                                                                               
          9. evalspeedpldi2returnin(A,B,C) -> evalspeedpldi2stop(A,B,C)           True                                                                                                      (1,1)
        Signature:
          {(evalspeedpldi2bb2in,3)
          ;(evalspeedpldi2bb3in,3)
          ;(evalspeedpldi2bb5in,3)
          ;(evalspeedpldi2entryin,3)
          ;(evalspeedpldi2returnin,3)
          ;(evalspeedpldi2start,3)
          ;(evalspeedpldi2stop,3)}
        Flow Graph:
          [0->{1,2,3},1->{4,5},2->{9},3->{9},4->{6,7},5->{9},6->{8},7->{4,5},8->{4,5},9->{}]
        
    + Applied Processor:
        UnsatPaths
    + Details:
        We remove following edges from the transition graph: [(7,5)]
* Step 3: Looptree YES
    + Considered Problem:
        Rules:
          0. evalspeedpldi2start(A,B,C)    -> evalspeedpldi2entryin(A,B,C)        True                                                                                                      (1,1)
          1. evalspeedpldi2entryin(A,B,C)  -> evalspeedpldi2bb5in(B,0,A)          [A >= 0 && B >= 1]                                                                                        (1,1)
          2. evalspeedpldi2entryin(A,B,C)  -> evalspeedpldi2returnin(A,B,C)       [0 >= 1 + A]                                                                                              (1,1)
          3. evalspeedpldi2entryin(A,B,C)  -> evalspeedpldi2returnin(A,B,C)       [0 >= B]                                                                                                  (1,1)
          4. evalspeedpldi2bb5in(A,B,C)    -> evalspeedpldi2bb2in(A,B,C)          [C >= 0 && B + C >= 0 && -1 + A + C >= 0 && B >= 0 && -1 + A + B >= 0 && -1 + A >= 0 && C >= 1]           (?,1)
          5. evalspeedpldi2bb5in(A,B,C)    -> evalspeedpldi2returnin(A,B,C)       [C >= 0 && B + C >= 0 && -1 + A + C >= 0 && B >= 0 && -1 + A + B >= 0 && -1 + A >= 0 && 0 >= C]           (1,1)
          6. evalspeedpldi2bb2in(A,B,C)    -> evalspeedpldi2bb3in(A,B,C)          [-1 + C >= 0                                                                                              (?,1)
                                                                                   && -1 + B + C >= 0                                                                                            
                                                                                   && -2 + A + C >= 0                                                                                            
                                                                                   && B >= 0                                                                                                     
                                                                                   && -1 + A + B >= 0                                                                                            
                                                                                   && -1 + A >= 0                                                                                                
                                                                                   && A >= 1 + B]                                                                                                
          7. evalspeedpldi2bb2in(A,B,C)    -> evalspeedpldi2bb5in(A,0,C)          [-1 + C >= 0 && -1 + B + C >= 0 && -2 + A + C >= 0 && B >= 0 && -1 + A + B >= 0 && -1 + A >= 0 && B >= A] (?,1)
          8. evalspeedpldi2bb3in(A,B,C)    -> evalspeedpldi2bb5in(A,1 + B,-1 + C) [-1 + C >= 0                                                                                              (?,1)
                                                                                   && -1 + B + C >= 0                                                                                            
                                                                                   && -2 + A + C >= 0                                                                                            
                                                                                   && -1 + A + -1*B >= 0                                                                                         
                                                                                   && B >= 0                                                                                                     
                                                                                   && -1 + A + B >= 0                                                                                            
                                                                                   && -1 + A >= 0]                                                                                               
          9. evalspeedpldi2returnin(A,B,C) -> evalspeedpldi2stop(A,B,C)           True                                                                                                      (1,1)
        Signature:
          {(evalspeedpldi2bb2in,3)
          ;(evalspeedpldi2bb3in,3)
          ;(evalspeedpldi2bb5in,3)
          ;(evalspeedpldi2entryin,3)
          ;(evalspeedpldi2returnin,3)
          ;(evalspeedpldi2start,3)
          ;(evalspeedpldi2stop,3)}
        Flow Graph:
          [0->{1,2,3},1->{4,5},2->{9},3->{9},4->{6,7},5->{9},6->{8},7->{4},8->{4,5},9->{}]
        
    + Applied Processor:
        Looptree
    + Details:
        We construct a looptree:
          P: [0,1,2,3,4,5,6,7,8,9]
          |
          `- p:[4,7,8,6] c: [8]
             |
             `- p:[4,7] c: [7]

YES