NO
* Step 1: TrivialSCCs NO
    + Considered Problem:
        Rules:
          0. evalspeedFails4start(A,B,C,D)    -> evalspeedFails4entryin(A,B,C,D)      True                                                                                                     (1,1)
          1. evalspeedFails4entryin(A,B,C,D)  -> evalspeedFails4bb6in(1,C,A,B)        [A >= 1]                                                                                                 (?,1)
          2. evalspeedFails4entryin(A,B,C,D)  -> evalspeedFails4bb6in(-1,C,A,B)       [0 >= A]                                                                                                 (?,1)
          3. evalspeedFails4bb6in(A,B,C,D)    -> evalspeedFails4bb3in(A,B,C,D)        [1 + -1*A >= 0 && 1 + A >= 0 && B >= D]                                                                  (?,1)
          4. evalspeedFails4bb6in(A,B,C,D)    -> evalspeedFails4returnin(A,B,C,D)     [1 + -1*A >= 0 && 1 + A >= 0 && D >= 1 + B]                                                              (?,1)
          5. evalspeedFails4bb3in(A,B,C,D)    -> evalspeedFails4bb4in(A,B,C,D)        [B + -1*D >= 0 && 1 + -1*A >= 0 && 1 + A >= 0 && C >= 1]                                                 (?,1)
          6. evalspeedFails4bb3in(A,B,C,D)    -> evalspeedFails4bb5in(A,B,C,D)        [B + -1*D >= 0 && 1 + -1*A >= 0 && 1 + A >= 0 && 0 >= C]                                                 (?,1)
          7. evalspeedFails4bb4in(A,B,C,D)    -> evalspeedFails4bb6in(A,B,C,A + D)    [B + -1*D >= 0 && -1 + C >= 0 && A + C >= 0 && -1*A + C >= 0 && 1 + -1*A >= 0 && 1 + A >= 0]             (?,1)
          8. evalspeedFails4bb5in(A,B,C,D)    -> evalspeedFails4bb6in(A,B,C,-1*A + D) [B + -1*D >= 0 && -1*C >= 0 && 1 + A + -1*C >= 0 && 1 + -1*A + -1*C >= 0 && 1 + -1*A >= 0 && 1 + A >= 0] (?,1)
          9. evalspeedFails4returnin(A,B,C,D) -> evalspeedFails4stop(A,B,C,D)         [-1 + -1*B + D >= 0 && 1 + -1*A >= 0 && 1 + A >= 0]                                                      (?,1)
        Signature:
          {(evalspeedFails4bb3in,4)
          ;(evalspeedFails4bb4in,4)
          ;(evalspeedFails4bb5in,4)
          ;(evalspeedFails4bb6in,4)
          ;(evalspeedFails4entryin,4)
          ;(evalspeedFails4returnin,4)
          ;(evalspeedFails4start,4)
          ;(evalspeedFails4stop,4)}
        Flow Graph:
          [0->{1,2},1->{3,4},2->{3,4},3->{5,6},4->{9},5->{7},6->{8},7->{3,4},8->{3,4},9->{}]
        
    + Applied Processor:
        TrivialSCCs
    + Details:
        All trivial SCCs of the transition graph admit timebound 1.
* Step 2: Looptree NO
    + Considered Problem:
        Rules:
          0. evalspeedFails4start(A,B,C,D)    -> evalspeedFails4entryin(A,B,C,D)      True                                                                                                     (1,1)
          1. evalspeedFails4entryin(A,B,C,D)  -> evalspeedFails4bb6in(1,C,A,B)        [A >= 1]                                                                                                 (1,1)
          2. evalspeedFails4entryin(A,B,C,D)  -> evalspeedFails4bb6in(-1,C,A,B)       [0 >= A]                                                                                                 (1,1)
          3. evalspeedFails4bb6in(A,B,C,D)    -> evalspeedFails4bb3in(A,B,C,D)        [1 + -1*A >= 0 && 1 + A >= 0 && B >= D]                                                                  (?,1)
          4. evalspeedFails4bb6in(A,B,C,D)    -> evalspeedFails4returnin(A,B,C,D)     [1 + -1*A >= 0 && 1 + A >= 0 && D >= 1 + B]                                                              (1,1)
          5. evalspeedFails4bb3in(A,B,C,D)    -> evalspeedFails4bb4in(A,B,C,D)        [B + -1*D >= 0 && 1 + -1*A >= 0 && 1 + A >= 0 && C >= 1]                                                 (?,1)
          6. evalspeedFails4bb3in(A,B,C,D)    -> evalspeedFails4bb5in(A,B,C,D)        [B + -1*D >= 0 && 1 + -1*A >= 0 && 1 + A >= 0 && 0 >= C]                                                 (?,1)
          7. evalspeedFails4bb4in(A,B,C,D)    -> evalspeedFails4bb6in(A,B,C,A + D)    [B + -1*D >= 0 && -1 + C >= 0 && A + C >= 0 && -1*A + C >= 0 && 1 + -1*A >= 0 && 1 + A >= 0]             (?,1)
          8. evalspeedFails4bb5in(A,B,C,D)    -> evalspeedFails4bb6in(A,B,C,-1*A + D) [B + -1*D >= 0 && -1*C >= 0 && 1 + A + -1*C >= 0 && 1 + -1*A + -1*C >= 0 && 1 + -1*A >= 0 && 1 + A >= 0] (?,1)
          9. evalspeedFails4returnin(A,B,C,D) -> evalspeedFails4stop(A,B,C,D)         [-1 + -1*B + D >= 0 && 1 + -1*A >= 0 && 1 + A >= 0]                                                      (1,1)
        Signature:
          {(evalspeedFails4bb3in,4)
          ;(evalspeedFails4bb4in,4)
          ;(evalspeedFails4bb5in,4)
          ;(evalspeedFails4bb6in,4)
          ;(evalspeedFails4entryin,4)
          ;(evalspeedFails4returnin,4)
          ;(evalspeedFails4start,4)
          ;(evalspeedFails4stop,4)}
        Flow Graph:
          [0->{1,2},1->{3,4},2->{3,4},3->{5,6},4->{9},5->{7},6->{8},7->{3,4},8->{3,4},9->{}]
        
    + Applied Processor:
        Looptree
    + Details:
        We construct a looptree:
          P: [0,1,2,3,4,5,6,7,8,9]
          |
          `- p:[3,7,5,8,6] c: []

NO