YES
* Step 1: TrivialSCCs YES
    + Considered Problem:
        Rules:
          0.  evalsipmabubblestart(A,B)    -> evalsipmabubbleentryin(A,B)    True                                                                           (1,1)
          1.  evalsipmabubbleentryin(A,B)  -> evalsipmabubblebb6in(A,B)      True                                                                           (?,1)
          2.  evalsipmabubblebb6in(A,B)    -> evalsipmabubblebb4in(A,0)      [A >= 0]                                                                       (?,1)
          3.  evalsipmabubblebb6in(A,B)    -> evalsipmabubblereturnin(A,B)   [0 >= 1 + A]                                                                   (?,1)
          4.  evalsipmabubblebb4in(A,B)    -> evalsipmabubblebb1in(A,B)      [A + -1*B >= 0 && B >= 0 && A + B >= 0 && A >= 0 && A >= 1 + B]                (?,1)
          5.  evalsipmabubblebb4in(A,B)    -> evalsipmabubblebb5in(A,B)      [A + -1*B >= 0 && B >= 0 && A + B >= 0 && A >= 0 && B >= A]                    (?,1)
          6.  evalsipmabubblebb1in(A,B)    -> evalsipmabubblebb2in(A,B)      [-1 + A + -1*B >= 0 && B >= 0 && -1 + A + B >= 0 && -1 + A >= 0 && C >= 1 + D] (?,1)
          7.  evalsipmabubblebb1in(A,B)    -> evalsipmabubblebb3in(A,B)      [-1 + A + -1*B >= 0 && B >= 0 && -1 + A + B >= 0 && -1 + A >= 0 && D >= C]     (?,1)
          8.  evalsipmabubblebb2in(A,B)    -> evalsipmabubblebb3in(A,B)      [-1 + A + -1*B >= 0 && B >= 0 && -1 + A + B >= 0 && -1 + A >= 0]               (?,1)
          9.  evalsipmabubblebb3in(A,B)    -> evalsipmabubblebb4in(A,1 + B)  [-1 + A + -1*B >= 0 && B >= 0 && -1 + A + B >= 0 && -1 + A >= 0]               (?,1)
          10. evalsipmabubblebb5in(A,B)    -> evalsipmabubblebb6in(-1 + A,B) [A + -1*B >= 0 && B >= 0 && A + B >= 0 && -1*A + B >= 0 && A >= 0]             (?,1)
          11. evalsipmabubblereturnin(A,B) -> evalsipmabubblestop(A,B)       [-1 + -1*A >= 0]                                                               (?,1)
        Signature:
          {(evalsipmabubblebb1in,2)
          ;(evalsipmabubblebb2in,2)
          ;(evalsipmabubblebb3in,2)
          ;(evalsipmabubblebb4in,2)
          ;(evalsipmabubblebb5in,2)
          ;(evalsipmabubblebb6in,2)
          ;(evalsipmabubbleentryin,2)
          ;(evalsipmabubblereturnin,2)
          ;(evalsipmabubblestart,2)
          ;(evalsipmabubblestop,2)}
        Flow Graph:
          [0->{1},1->{2,3},2->{4,5},3->{11},4->{6,7},5->{10},6->{8},7->{9},8->{9},9->{4,5},10->{2,3},11->{}]
        
    + Applied Processor:
        TrivialSCCs
    + Details:
        All trivial SCCs of the transition graph admit timebound 1.
* Step 2: Looptree YES
    + Considered Problem:
        Rules:
          0.  evalsipmabubblestart(A,B)    -> evalsipmabubbleentryin(A,B)    True                                                                           (1,1)
          1.  evalsipmabubbleentryin(A,B)  -> evalsipmabubblebb6in(A,B)      True                                                                           (1,1)
          2.  evalsipmabubblebb6in(A,B)    -> evalsipmabubblebb4in(A,0)      [A >= 0]                                                                       (?,1)
          3.  evalsipmabubblebb6in(A,B)    -> evalsipmabubblereturnin(A,B)   [0 >= 1 + A]                                                                   (1,1)
          4.  evalsipmabubblebb4in(A,B)    -> evalsipmabubblebb1in(A,B)      [A + -1*B >= 0 && B >= 0 && A + B >= 0 && A >= 0 && A >= 1 + B]                (?,1)
          5.  evalsipmabubblebb4in(A,B)    -> evalsipmabubblebb5in(A,B)      [A + -1*B >= 0 && B >= 0 && A + B >= 0 && A >= 0 && B >= A]                    (?,1)
          6.  evalsipmabubblebb1in(A,B)    -> evalsipmabubblebb2in(A,B)      [-1 + A + -1*B >= 0 && B >= 0 && -1 + A + B >= 0 && -1 + A >= 0 && C >= 1 + D] (?,1)
          7.  evalsipmabubblebb1in(A,B)    -> evalsipmabubblebb3in(A,B)      [-1 + A + -1*B >= 0 && B >= 0 && -1 + A + B >= 0 && -1 + A >= 0 && D >= C]     (?,1)
          8.  evalsipmabubblebb2in(A,B)    -> evalsipmabubblebb3in(A,B)      [-1 + A + -1*B >= 0 && B >= 0 && -1 + A + B >= 0 && -1 + A >= 0]               (?,1)
          9.  evalsipmabubblebb3in(A,B)    -> evalsipmabubblebb4in(A,1 + B)  [-1 + A + -1*B >= 0 && B >= 0 && -1 + A + B >= 0 && -1 + A >= 0]               (?,1)
          10. evalsipmabubblebb5in(A,B)    -> evalsipmabubblebb6in(-1 + A,B) [A + -1*B >= 0 && B >= 0 && A + B >= 0 && -1*A + B >= 0 && A >= 0]             (?,1)
          11. evalsipmabubblereturnin(A,B) -> evalsipmabubblestop(A,B)       [-1 + -1*A >= 0]                                                               (1,1)
        Signature:
          {(evalsipmabubblebb1in,2)
          ;(evalsipmabubblebb2in,2)
          ;(evalsipmabubblebb3in,2)
          ;(evalsipmabubblebb4in,2)
          ;(evalsipmabubblebb5in,2)
          ;(evalsipmabubblebb6in,2)
          ;(evalsipmabubbleentryin,2)
          ;(evalsipmabubblereturnin,2)
          ;(evalsipmabubblestart,2)
          ;(evalsipmabubblestop,2)}
        Flow Graph:
          [0->{1},1->{2,3},2->{4,5},3->{11},4->{6,7},5->{10},6->{8},7->{9},8->{9},9->{4,5},10->{2,3},11->{}]
        
    + Applied Processor:
        Looptree
    + Details:
        We construct a looptree:
          P: [0,1,2,3,4,5,6,7,8,9,10,11]
          |
          `- p:[2,10,5,9,7,4,8,6] c: [10]
             |
             `- p:[4,9,7,8,6] c: [9]

YES