YES
* Step 1: TrivialSCCs YES
    + Considered Problem:
        Rules:
          0. evalrandom1dstart(A,B)    -> evalrandom1dentryin(A,B)   True                                                                           (1,1)
          1. evalrandom1dentryin(A,B)  -> evalrandom1dbb5in(A,1)     [A >= 1]                                                                       (?,1)
          2. evalrandom1dentryin(A,B)  -> evalrandom1dreturnin(A,B)  [0 >= A]                                                                       (?,1)
          3. evalrandom1dbb5in(A,B)    -> evalrandom1dbb1in(A,B)     [-1 + B >= 0 && -2 + A + B >= 0 && -1 + A >= 0 && A >= B]                      (?,1)
          4. evalrandom1dbb5in(A,B)    -> evalrandom1dreturnin(A,B)  [-1 + B >= 0 && -2 + A + B >= 0 && -1 + A >= 0 && B >= 1 + A]                  (?,1)
          5. evalrandom1dbb1in(A,B)    -> evalrandom1dbb5in(A,1 + B) [A + -1*B >= 0 && -1 + B >= 0 && -2 + A + B >= 0 && -1 + A >= 0 && 0 >= 1 + C] (?,1)
          6. evalrandom1dbb1in(A,B)    -> evalrandom1dbb5in(A,1 + B) [A + -1*B >= 0 && -1 + B >= 0 && -2 + A + B >= 0 && -1 + A >= 0 && C >= 1]     (?,1)
          7. evalrandom1dbb1in(A,B)    -> evalrandom1dbb5in(A,1 + B) [A + -1*B >= 0 && -1 + B >= 0 && -2 + A + B >= 0 && -1 + A >= 0]               (?,1)
          8. evalrandom1dreturnin(A,B) -> evalrandom1dstop(A,B)      True                                                                           (?,1)
        Signature:
          {(evalrandom1dbb1in,2)
          ;(evalrandom1dbb5in,2)
          ;(evalrandom1dentryin,2)
          ;(evalrandom1dreturnin,2)
          ;(evalrandom1dstart,2)
          ;(evalrandom1dstop,2)}
        Flow Graph:
          [0->{1,2},1->{3,4},2->{8},3->{5,6,7},4->{8},5->{3,4},6->{3,4},7->{3,4},8->{}]
        
    + Applied Processor:
        TrivialSCCs
    + Details:
        All trivial SCCs of the transition graph admit timebound 1.
* Step 2: UnsatPaths YES
    + Considered Problem:
        Rules:
          0. evalrandom1dstart(A,B)    -> evalrandom1dentryin(A,B)   True                                                                           (1,1)
          1. evalrandom1dentryin(A,B)  -> evalrandom1dbb5in(A,1)     [A >= 1]                                                                       (1,1)
          2. evalrandom1dentryin(A,B)  -> evalrandom1dreturnin(A,B)  [0 >= A]                                                                       (1,1)
          3. evalrandom1dbb5in(A,B)    -> evalrandom1dbb1in(A,B)     [-1 + B >= 0 && -2 + A + B >= 0 && -1 + A >= 0 && A >= B]                      (?,1)
          4. evalrandom1dbb5in(A,B)    -> evalrandom1dreturnin(A,B)  [-1 + B >= 0 && -2 + A + B >= 0 && -1 + A >= 0 && B >= 1 + A]                  (1,1)
          5. evalrandom1dbb1in(A,B)    -> evalrandom1dbb5in(A,1 + B) [A + -1*B >= 0 && -1 + B >= 0 && -2 + A + B >= 0 && -1 + A >= 0 && 0 >= 1 + C] (?,1)
          6. evalrandom1dbb1in(A,B)    -> evalrandom1dbb5in(A,1 + B) [A + -1*B >= 0 && -1 + B >= 0 && -2 + A + B >= 0 && -1 + A >= 0 && C >= 1]     (?,1)
          7. evalrandom1dbb1in(A,B)    -> evalrandom1dbb5in(A,1 + B) [A + -1*B >= 0 && -1 + B >= 0 && -2 + A + B >= 0 && -1 + A >= 0]               (?,1)
          8. evalrandom1dreturnin(A,B) -> evalrandom1dstop(A,B)      True                                                                           (1,1)
        Signature:
          {(evalrandom1dbb1in,2)
          ;(evalrandom1dbb5in,2)
          ;(evalrandom1dentryin,2)
          ;(evalrandom1dreturnin,2)
          ;(evalrandom1dstart,2)
          ;(evalrandom1dstop,2)}
        Flow Graph:
          [0->{1,2},1->{3,4},2->{8},3->{5,6,7},4->{8},5->{3,4},6->{3,4},7->{3,4},8->{}]
        
    + Applied Processor:
        UnsatPaths
    + Details:
        We remove following edges from the transition graph: [(1,4)]
* Step 3: Looptree YES
    + Considered Problem:
        Rules:
          0. evalrandom1dstart(A,B)    -> evalrandom1dentryin(A,B)   True                                                                           (1,1)
          1. evalrandom1dentryin(A,B)  -> evalrandom1dbb5in(A,1)     [A >= 1]                                                                       (1,1)
          2. evalrandom1dentryin(A,B)  -> evalrandom1dreturnin(A,B)  [0 >= A]                                                                       (1,1)
          3. evalrandom1dbb5in(A,B)    -> evalrandom1dbb1in(A,B)     [-1 + B >= 0 && -2 + A + B >= 0 && -1 + A >= 0 && A >= B]                      (?,1)
          4. evalrandom1dbb5in(A,B)    -> evalrandom1dreturnin(A,B)  [-1 + B >= 0 && -2 + A + B >= 0 && -1 + A >= 0 && B >= 1 + A]                  (1,1)
          5. evalrandom1dbb1in(A,B)    -> evalrandom1dbb5in(A,1 + B) [A + -1*B >= 0 && -1 + B >= 0 && -2 + A + B >= 0 && -1 + A >= 0 && 0 >= 1 + C] (?,1)
          6. evalrandom1dbb1in(A,B)    -> evalrandom1dbb5in(A,1 + B) [A + -1*B >= 0 && -1 + B >= 0 && -2 + A + B >= 0 && -1 + A >= 0 && C >= 1]     (?,1)
          7. evalrandom1dbb1in(A,B)    -> evalrandom1dbb5in(A,1 + B) [A + -1*B >= 0 && -1 + B >= 0 && -2 + A + B >= 0 && -1 + A >= 0]               (?,1)
          8. evalrandom1dreturnin(A,B) -> evalrandom1dstop(A,B)      True                                                                           (1,1)
        Signature:
          {(evalrandom1dbb1in,2)
          ;(evalrandom1dbb5in,2)
          ;(evalrandom1dentryin,2)
          ;(evalrandom1dreturnin,2)
          ;(evalrandom1dstart,2)
          ;(evalrandom1dstop,2)}
        Flow Graph:
          [0->{1,2},1->{3},2->{8},3->{5,6,7},4->{8},5->{3,4},6->{3,4},7->{3,4},8->{}]
        
    + Applied Processor:
        Looptree
    + Details:
        We construct a looptree:
          P: [0,1,2,3,4,5,6,7,8]
          |
          `- p:[3,5,6,7] c: [7]
             |
             `- p:[3,5,6] c: [6]
                |
                `- p:[3,5] c: [5]

YES