YES
* Step 1: TrivialSCCs YES
    + Considered Problem:
        Rules:
          0. evalndecrstart(A)    -> evalndecrentryin(A)    True            (1,1)
          1. evalndecrentryin(A)  -> evalndecrbb1in(-1 + A) True            (?,1)
          2. evalndecrbb1in(A)    -> evalndecrbbin(A)       [A >= 2]        (?,1)
          3. evalndecrbb1in(A)    -> evalndecrreturnin(A)   [1 >= A]        (?,1)
          4. evalndecrbbin(A)     -> evalndecrbb1in(-1 + A) [-2 + A >= 0]   (?,1)
          5. evalndecrreturnin(A) -> evalndecrstop(A)       [1 + -1*A >= 0] (?,1)
        Signature:
          {(evalndecrbb1in,1)
          ;(evalndecrbbin,1)
          ;(evalndecrentryin,1)
          ;(evalndecrreturnin,1)
          ;(evalndecrstart,1)
          ;(evalndecrstop,1)}
        Flow Graph:
          [0->{1},1->{2,3},2->{4},3->{5},4->{2,3},5->{}]
        
    + Applied Processor:
        TrivialSCCs
    + Details:
        All trivial SCCs of the transition graph admit timebound 1.
* Step 2: Looptree YES
    + Considered Problem:
        Rules:
          0. evalndecrstart(A)    -> evalndecrentryin(A)    True            (1,1)
          1. evalndecrentryin(A)  -> evalndecrbb1in(-1 + A) True            (1,1)
          2. evalndecrbb1in(A)    -> evalndecrbbin(A)       [A >= 2]        (?,1)
          3. evalndecrbb1in(A)    -> evalndecrreturnin(A)   [1 >= A]        (1,1)
          4. evalndecrbbin(A)     -> evalndecrbb1in(-1 + A) [-2 + A >= 0]   (?,1)
          5. evalndecrreturnin(A) -> evalndecrstop(A)       [1 + -1*A >= 0] (1,1)
        Signature:
          {(evalndecrbb1in,1)
          ;(evalndecrbbin,1)
          ;(evalndecrentryin,1)
          ;(evalndecrreturnin,1)
          ;(evalndecrstart,1)
          ;(evalndecrstop,1)}
        Flow Graph:
          [0->{1},1->{2,3},2->{4},3->{5},4->{2,3},5->{}]
        
    + Applied Processor:
        Looptree
    + Details:
        We construct a looptree:
          P: [0,1,2,3,4,5]
          |
          `- p:[2,4] c: [4]

YES