YES
* Step 1: TrivialSCCs YES
    + Considered Problem:
        Rules:
          0.  evalNestedMultiplestart(A,B,C,D,E)    -> evalNestedMultipleentryin(A,B,C,D,E)   True                                                                                            (1,1)
          1.  evalNestedMultipleentryin(A,B,C,D,E)  -> evalNestedMultiplebb5in(B,A,D,C,E)     True                                                                                            (?,1)
          2.  evalNestedMultiplebb5in(A,B,C,D,E)    -> evalNestedMultiplebb2in(A,B,C,D,D)     [A >= 1 + B]                                                                                    (?,1)
          3.  evalNestedMultiplebb5in(A,B,C,D,E)    -> evalNestedMultiplereturnin(A,B,C,D,E)  [B >= A]                                                                                        (?,1)
          4.  evalNestedMultiplebb2in(A,B,C,D,E)    -> evalNestedMultiplebb4in(A,B,C,D,E)     [-1*D + E >= 0 && -1 + A + -1*B >= 0 && E >= C]                                                 (?,1)
          5.  evalNestedMultiplebb2in(A,B,C,D,E)    -> evalNestedMultiplebb3in(A,B,C,D,E)     [-1*D + E >= 0 && -1 + A + -1*B >= 0 && C >= 1 + E]                                             (?,1)
          6.  evalNestedMultiplebb3in(A,B,C,D,E)    -> evalNestedMultiplebb1in(A,B,C,D,E)     [-1 + C + -1*E >= 0 && -1*D + E >= 0 && -1 + C + -1*D >= 0 && -1 + A + -1*B >= 0 && 0 >= 1 + F] (?,1)
          7.  evalNestedMultiplebb3in(A,B,C,D,E)    -> evalNestedMultiplebb1in(A,B,C,D,E)     [-1 + C + -1*E >= 0 && -1*D + E >= 0 && -1 + C + -1*D >= 0 && -1 + A + -1*B >= 0 && F >= 1]     (?,1)
          8.  evalNestedMultiplebb3in(A,B,C,D,E)    -> evalNestedMultiplebb4in(A,B,C,D,E)     [-1 + C + -1*E >= 0 && -1*D + E >= 0 && -1 + C + -1*D >= 0 && -1 + A + -1*B >= 0]               (?,1)
          9.  evalNestedMultiplebb1in(A,B,C,D,E)    -> evalNestedMultiplebb2in(A,B,C,D,1 + E) [-1 + C + -1*E >= 0 && -1*D + E >= 0 && -1 + C + -1*D >= 0 && -1 + A + -1*B >= 0]               (?,1)
          10. evalNestedMultiplebb4in(A,B,C,D,E)    -> evalNestedMultiplebb5in(A,1 + B,C,E,E) [-1*D + E >= 0 && -1 + A + -1*B >= 0]                                                           (?,1)
          11. evalNestedMultiplereturnin(A,B,C,D,E) -> evalNestedMultiplestop(A,B,C,D,E)      [-1*A + B >= 0]                                                                                 (?,1)
        Signature:
          {(evalNestedMultiplebb1in,5)
          ;(evalNestedMultiplebb2in,5)
          ;(evalNestedMultiplebb3in,5)
          ;(evalNestedMultiplebb4in,5)
          ;(evalNestedMultiplebb5in,5)
          ;(evalNestedMultipleentryin,5)
          ;(evalNestedMultiplereturnin,5)
          ;(evalNestedMultiplestart,5)
          ;(evalNestedMultiplestop,5)}
        Flow Graph:
          [0->{1},1->{2,3},2->{4,5},3->{11},4->{10},5->{6,7,8},6->{9},7->{9},8->{10},9->{4,5},10->{2,3},11->{}]
        
    + Applied Processor:
        TrivialSCCs
    + Details:
        All trivial SCCs of the transition graph admit timebound 1.
* Step 2: Looptree YES
    + Considered Problem:
        Rules:
          0.  evalNestedMultiplestart(A,B,C,D,E)    -> evalNestedMultipleentryin(A,B,C,D,E)   True                                                                                            (1,1)
          1.  evalNestedMultipleentryin(A,B,C,D,E)  -> evalNestedMultiplebb5in(B,A,D,C,E)     True                                                                                            (1,1)
          2.  evalNestedMultiplebb5in(A,B,C,D,E)    -> evalNestedMultiplebb2in(A,B,C,D,D)     [A >= 1 + B]                                                                                    (?,1)
          3.  evalNestedMultiplebb5in(A,B,C,D,E)    -> evalNestedMultiplereturnin(A,B,C,D,E)  [B >= A]                                                                                        (1,1)
          4.  evalNestedMultiplebb2in(A,B,C,D,E)    -> evalNestedMultiplebb4in(A,B,C,D,E)     [-1*D + E >= 0 && -1 + A + -1*B >= 0 && E >= C]                                                 (?,1)
          5.  evalNestedMultiplebb2in(A,B,C,D,E)    -> evalNestedMultiplebb3in(A,B,C,D,E)     [-1*D + E >= 0 && -1 + A + -1*B >= 0 && C >= 1 + E]                                             (?,1)
          6.  evalNestedMultiplebb3in(A,B,C,D,E)    -> evalNestedMultiplebb1in(A,B,C,D,E)     [-1 + C + -1*E >= 0 && -1*D + E >= 0 && -1 + C + -1*D >= 0 && -1 + A + -1*B >= 0 && 0 >= 1 + F] (?,1)
          7.  evalNestedMultiplebb3in(A,B,C,D,E)    -> evalNestedMultiplebb1in(A,B,C,D,E)     [-1 + C + -1*E >= 0 && -1*D + E >= 0 && -1 + C + -1*D >= 0 && -1 + A + -1*B >= 0 && F >= 1]     (?,1)
          8.  evalNestedMultiplebb3in(A,B,C,D,E)    -> evalNestedMultiplebb4in(A,B,C,D,E)     [-1 + C + -1*E >= 0 && -1*D + E >= 0 && -1 + C + -1*D >= 0 && -1 + A + -1*B >= 0]               (?,1)
          9.  evalNestedMultiplebb1in(A,B,C,D,E)    -> evalNestedMultiplebb2in(A,B,C,D,1 + E) [-1 + C + -1*E >= 0 && -1*D + E >= 0 && -1 + C + -1*D >= 0 && -1 + A + -1*B >= 0]               (?,1)
          10. evalNestedMultiplebb4in(A,B,C,D,E)    -> evalNestedMultiplebb5in(A,1 + B,C,E,E) [-1*D + E >= 0 && -1 + A + -1*B >= 0]                                                           (?,1)
          11. evalNestedMultiplereturnin(A,B,C,D,E) -> evalNestedMultiplestop(A,B,C,D,E)      [-1*A + B >= 0]                                                                                 (1,1)
        Signature:
          {(evalNestedMultiplebb1in,5)
          ;(evalNestedMultiplebb2in,5)
          ;(evalNestedMultiplebb3in,5)
          ;(evalNestedMultiplebb4in,5)
          ;(evalNestedMultiplebb5in,5)
          ;(evalNestedMultipleentryin,5)
          ;(evalNestedMultiplereturnin,5)
          ;(evalNestedMultiplestart,5)
          ;(evalNestedMultiplestop,5)}
        Flow Graph:
          [0->{1},1->{2,3},2->{4,5},3->{11},4->{10},5->{6,7,8},6->{9},7->{9},8->{10},9->{4,5},10->{2,3},11->{}]
        
    + Applied Processor:
        Looptree
    + Details:
        We construct a looptree:
          P: [0,1,2,3,4,5,6,7,8,9,10,11]
          |
          `- p:[2,10,4,9,6,5,7,8] c: [10]
             |
             `- p:[5,9,6,7] c: [9]

YES