YES
* Step 1: TrivialSCCs YES
    + Considered Problem:
        Rules:
          0. evalfstart(A,B,C,D)    -> evalfentryin(A,B,C,D)   True                                              (1,1)
          1. evalfentryin(A,B,C,D)  -> evalfbb3in(0,0,C,D)     True                                              (?,1)
          2. evalfbb3in(A,B,C,D)    -> evalfbbin(A,B,C,D)      [B >= 0 && A + B >= 0 && A >= 0 && C >= 1 + B]    (?,1)
          3. evalfbb3in(A,B,C,D)    -> evalfreturnin(A,B,C,D)  [B >= 0 && A + B >= 0 && A >= 0 && B >= C]        (?,1)
          4. evalfbbin(A,B,C,D)     -> evalfbb1in(A,B,C,D)     [-1 + C >= 0                                      (?,1)
                                                                && -1 + B + C >= 0                                    
                                                                && -1 + -1*B + C >= 0                                 
                                                                && -1 + A + C >= 0                                    
                                                                && B >= 0                                             
                                                                && A + B >= 0                                         
                                                                && A >= 0                                             
                                                                && D >= 1 + A]                                        
          5. evalfbbin(A,B,C,D)     -> evalfbb2in(A,B,C,D)     [-1 + C >= 0                                      (?,1)
                                                                && -1 + B + C >= 0                                    
                                                                && -1 + -1*B + C >= 0                                 
                                                                && -1 + A + C >= 0                                    
                                                                && B >= 0                                             
                                                                && A + B >= 0                                         
                                                                && A >= 0                                             
                                                                && A >= D]                                            
          6. evalfbb1in(A,B,C,D)    -> evalfbb3in(1 + A,B,C,D) [-1 + D >= 0                                      (?,1)
                                                                && -2 + C + D >= 0                                    
                                                                && -1 + B + D >= 0                                    
                                                                && -1 + A + D >= 0                                    
                                                                && -1 + -1*A + D >= 0                                 
                                                                && -1 + C >= 0                                        
                                                                && -1 + B + C >= 0                                    
                                                                && -1 + -1*B + C >= 0                                 
                                                                && -1 + A + C >= 0                                    
                                                                && B >= 0                                             
                                                                && A + B >= 0                                         
                                                                && A >= 0]                                            
          7. evalfbb2in(A,B,C,D)    -> evalfbb3in(0,1 + B,C,D) [A + -1*D >= 0                                    (?,1)
                                                                && -1 + C >= 0                                        
                                                                && -1 + B + C >= 0                                    
                                                                && -1 + -1*B + C >= 0                                 
                                                                && -1 + A + C >= 0                                    
                                                                && B >= 0                                             
                                                                && A + B >= 0                                         
                                                                && A >= 0]                                            
          8. evalfreturnin(A,B,C,D) -> evalfstop(A,B,C,D)      [B + -1*C >= 0 && B >= 0 && A + B >= 0 && A >= 0] (?,1)
        Signature:
          {(evalfbb1in,4)
          ;(evalfbb2in,4)
          ;(evalfbb3in,4)
          ;(evalfbbin,4)
          ;(evalfentryin,4)
          ;(evalfreturnin,4)
          ;(evalfstart,4)
          ;(evalfstop,4)}
        Flow Graph:
          [0->{1},1->{2,3},2->{4,5},3->{8},4->{6},5->{7},6->{2,3},7->{2,3},8->{}]
        
    + Applied Processor:
        TrivialSCCs
    + Details:
        All trivial SCCs of the transition graph admit timebound 1.
* Step 2: UnsatPaths YES
    + Considered Problem:
        Rules:
          0. evalfstart(A,B,C,D)    -> evalfentryin(A,B,C,D)   True                                              (1,1)
          1. evalfentryin(A,B,C,D)  -> evalfbb3in(0,0,C,D)     True                                              (1,1)
          2. evalfbb3in(A,B,C,D)    -> evalfbbin(A,B,C,D)      [B >= 0 && A + B >= 0 && A >= 0 && C >= 1 + B]    (?,1)
          3. evalfbb3in(A,B,C,D)    -> evalfreturnin(A,B,C,D)  [B >= 0 && A + B >= 0 && A >= 0 && B >= C]        (1,1)
          4. evalfbbin(A,B,C,D)     -> evalfbb1in(A,B,C,D)     [-1 + C >= 0                                      (?,1)
                                                                && -1 + B + C >= 0                                    
                                                                && -1 + -1*B + C >= 0                                 
                                                                && -1 + A + C >= 0                                    
                                                                && B >= 0                                             
                                                                && A + B >= 0                                         
                                                                && A >= 0                                             
                                                                && D >= 1 + A]                                        
          5. evalfbbin(A,B,C,D)     -> evalfbb2in(A,B,C,D)     [-1 + C >= 0                                      (?,1)
                                                                && -1 + B + C >= 0                                    
                                                                && -1 + -1*B + C >= 0                                 
                                                                && -1 + A + C >= 0                                    
                                                                && B >= 0                                             
                                                                && A + B >= 0                                         
                                                                && A >= 0                                             
                                                                && A >= D]                                            
          6. evalfbb1in(A,B,C,D)    -> evalfbb3in(1 + A,B,C,D) [-1 + D >= 0                                      (?,1)
                                                                && -2 + C + D >= 0                                    
                                                                && -1 + B + D >= 0                                    
                                                                && -1 + A + D >= 0                                    
                                                                && -1 + -1*A + D >= 0                                 
                                                                && -1 + C >= 0                                        
                                                                && -1 + B + C >= 0                                    
                                                                && -1 + -1*B + C >= 0                                 
                                                                && -1 + A + C >= 0                                    
                                                                && B >= 0                                             
                                                                && A + B >= 0                                         
                                                                && A >= 0]                                            
          7. evalfbb2in(A,B,C,D)    -> evalfbb3in(0,1 + B,C,D) [A + -1*D >= 0                                    (?,1)
                                                                && -1 + C >= 0                                        
                                                                && -1 + B + C >= 0                                    
                                                                && -1 + -1*B + C >= 0                                 
                                                                && -1 + A + C >= 0                                    
                                                                && B >= 0                                             
                                                                && A + B >= 0                                         
                                                                && A >= 0]                                            
          8. evalfreturnin(A,B,C,D) -> evalfstop(A,B,C,D)      [B + -1*C >= 0 && B >= 0 && A + B >= 0 && A >= 0] (1,1)
        Signature:
          {(evalfbb1in,4)
          ;(evalfbb2in,4)
          ;(evalfbb3in,4)
          ;(evalfbbin,4)
          ;(evalfentryin,4)
          ;(evalfreturnin,4)
          ;(evalfstart,4)
          ;(evalfstop,4)}
        Flow Graph:
          [0->{1},1->{2,3},2->{4,5},3->{8},4->{6},5->{7},6->{2,3},7->{2,3},8->{}]
        
    + Applied Processor:
        UnsatPaths
    + Details:
        We remove following edges from the transition graph: [(6,3)]
* Step 3: Looptree YES
    + Considered Problem:
        Rules:
          0. evalfstart(A,B,C,D)    -> evalfentryin(A,B,C,D)   True                                              (1,1)
          1. evalfentryin(A,B,C,D)  -> evalfbb3in(0,0,C,D)     True                                              (1,1)
          2. evalfbb3in(A,B,C,D)    -> evalfbbin(A,B,C,D)      [B >= 0 && A + B >= 0 && A >= 0 && C >= 1 + B]    (?,1)
          3. evalfbb3in(A,B,C,D)    -> evalfreturnin(A,B,C,D)  [B >= 0 && A + B >= 0 && A >= 0 && B >= C]        (1,1)
          4. evalfbbin(A,B,C,D)     -> evalfbb1in(A,B,C,D)     [-1 + C >= 0                                      (?,1)
                                                                && -1 + B + C >= 0                                    
                                                                && -1 + -1*B + C >= 0                                 
                                                                && -1 + A + C >= 0                                    
                                                                && B >= 0                                             
                                                                && A + B >= 0                                         
                                                                && A >= 0                                             
                                                                && D >= 1 + A]                                        
          5. evalfbbin(A,B,C,D)     -> evalfbb2in(A,B,C,D)     [-1 + C >= 0                                      (?,1)
                                                                && -1 + B + C >= 0                                    
                                                                && -1 + -1*B + C >= 0                                 
                                                                && -1 + A + C >= 0                                    
                                                                && B >= 0                                             
                                                                && A + B >= 0                                         
                                                                && A >= 0                                             
                                                                && A >= D]                                            
          6. evalfbb1in(A,B,C,D)    -> evalfbb3in(1 + A,B,C,D) [-1 + D >= 0                                      (?,1)
                                                                && -2 + C + D >= 0                                    
                                                                && -1 + B + D >= 0                                    
                                                                && -1 + A + D >= 0                                    
                                                                && -1 + -1*A + D >= 0                                 
                                                                && -1 + C >= 0                                        
                                                                && -1 + B + C >= 0                                    
                                                                && -1 + -1*B + C >= 0                                 
                                                                && -1 + A + C >= 0                                    
                                                                && B >= 0                                             
                                                                && A + B >= 0                                         
                                                                && A >= 0]                                            
          7. evalfbb2in(A,B,C,D)    -> evalfbb3in(0,1 + B,C,D) [A + -1*D >= 0                                    (?,1)
                                                                && -1 + C >= 0                                        
                                                                && -1 + B + C >= 0                                    
                                                                && -1 + -1*B + C >= 0                                 
                                                                && -1 + A + C >= 0                                    
                                                                && B >= 0                                             
                                                                && A + B >= 0                                         
                                                                && A >= 0]                                            
          8. evalfreturnin(A,B,C,D) -> evalfstop(A,B,C,D)      [B + -1*C >= 0 && B >= 0 && A + B >= 0 && A >= 0] (1,1)
        Signature:
          {(evalfbb1in,4)
          ;(evalfbb2in,4)
          ;(evalfbb3in,4)
          ;(evalfbbin,4)
          ;(evalfentryin,4)
          ;(evalfreturnin,4)
          ;(evalfstart,4)
          ;(evalfstop,4)}
        Flow Graph:
          [0->{1},1->{2,3},2->{4,5},3->{8},4->{6},5->{7},6->{2},7->{2,3},8->{}]
        
    + Applied Processor:
        Looptree
    + Details:
        We construct a looptree:
          P: [0,1,2,3,4,5,6,7,8]
          |
          `- p:[2,6,4,7,5] c: [7]
             |
             `- p:[2,6,4] c: [6]

YES