YES
* Step 1: TrivialSCCs YES
    + Considered Problem:
        Rules:
          0. evalfstart(A,B)    -> evalfentryin(A,B)   True                 (1,1)
          1. evalfentryin(A,B)  -> evalfbb1in(B,A)     True                 (?,1)
          2. evalfbb1in(A,B)    -> evalfbbin(A,B)      [A >= B]             (?,1)
          3. evalfbb1in(A,B)    -> evalfreturnin(A,B)  [B >= 1 + A]         (?,1)
          4. evalfbbin(A,B)     -> evalfbb1in(A,1 + B) [A + -1*B >= 0]      (?,1)
          5. evalfreturnin(A,B) -> evalfstop(A,B)      [-1 + -1*A + B >= 0] (?,1)
        Signature:
          {(evalfbb1in,2);(evalfbbin,2);(evalfentryin,2);(evalfreturnin,2);(evalfstart,2);(evalfstop,2)}
        Flow Graph:
          [0->{1},1->{2,3},2->{4},3->{5},4->{2,3},5->{}]
        
    + Applied Processor:
        TrivialSCCs
    + Details:
        All trivial SCCs of the transition graph admit timebound 1.
* Step 2: Looptree YES
    + Considered Problem:
        Rules:
          0. evalfstart(A,B)    -> evalfentryin(A,B)   True                 (1,1)
          1. evalfentryin(A,B)  -> evalfbb1in(B,A)     True                 (1,1)
          2. evalfbb1in(A,B)    -> evalfbbin(A,B)      [A >= B]             (?,1)
          3. evalfbb1in(A,B)    -> evalfreturnin(A,B)  [B >= 1 + A]         (1,1)
          4. evalfbbin(A,B)     -> evalfbb1in(A,1 + B) [A + -1*B >= 0]      (?,1)
          5. evalfreturnin(A,B) -> evalfstop(A,B)      [-1 + -1*A + B >= 0] (1,1)
        Signature:
          {(evalfbb1in,2);(evalfbbin,2);(evalfentryin,2);(evalfreturnin,2);(evalfstart,2);(evalfstop,2)}
        Flow Graph:
          [0->{1},1->{2,3},2->{4},3->{5},4->{2,3},5->{}]
        
    + Applied Processor:
        Looptree
    + Details:
        We construct a looptree:
          P: [0,1,2,3,4,5]
          |
          `- p:[2,4] c: [4]

YES