NO
* Step 1: TrivialSCCs NO
    + Considered Problem:
        Rules:
          0. f10(A,B,C,D,E,F) -> f4(4,0,0,D,E,F)     True                                                                             (1,1)
          1. f4(A,B,C,D,E,F)  -> f4(A,1 + B,G,H,E,G) [B >= 0 && -4 + A + B >= 0 && 4 + -1*A + B >= 0 && 4 + -1*A >= 0 && -4 + A >= 0] (?,1)
          2. f4(A,B,C,D,E,F)  -> f9(A,B,C,C,C,F)     [B >= 0 && -4 + A + B >= 0 && 4 + -1*A + B >= 0 && 4 + -1*A >= 0 && -4 + A >= 0] (?,1)
        Signature:
          {(f10,6);(f4,6);(f9,6)}
        Flow Graph:
          [0->{1,2},1->{1,2},2->{}]
        
    + Applied Processor:
        TrivialSCCs
    + Details:
        All trivial SCCs of the transition graph admit timebound 1.
* Step 2: Looptree NO
    + Considered Problem:
        Rules:
          0. f10(A,B,C,D,E,F) -> f4(4,0,0,D,E,F)     True                                                                             (1,1)
          1. f4(A,B,C,D,E,F)  -> f4(A,1 + B,G,H,E,G) [B >= 0 && -4 + A + B >= 0 && 4 + -1*A + B >= 0 && 4 + -1*A >= 0 && -4 + A >= 0] (?,1)
          2. f4(A,B,C,D,E,F)  -> f9(A,B,C,C,C,F)     [B >= 0 && -4 + A + B >= 0 && 4 + -1*A + B >= 0 && 4 + -1*A >= 0 && -4 + A >= 0] (1,1)
        Signature:
          {(f10,6);(f4,6);(f9,6)}
        Flow Graph:
          [0->{1,2},1->{1,2},2->{}]
        
    + Applied Processor:
        Looptree
    + Details:
        We construct a looptree:
          P: [0,1,2]
          |
          `- p:[1] c: []

NO