NO * Step 1: TrivialSCCs NO + Considered Problem: Rules: 0. f2(A,B,C) -> f2(1 + A,B,C) [-1 + C >= 0 && -1 + A + C >= 0 && A >= 0] (?,1) 1. f3(A,B,C) -> f3(A,-1 + B,C) [-1*C >= 0 && A + -1*C >= 0 && -1*A + -1*C >= 0 && -1*A >= 0 && A >= 0 && B >= 1] (?,1) 2. f5(A,B,C) -> f5(A,B,1) [-1*B >= 0 && A + -1*B >= 0 && -1*A + -1*B >= 0 && -1*A >= 0 && A >= 0] (?,1) 3. f0(A,B,C) -> f2(0,B,C) [C >= 1] (1,1) 4. f0(A,B,C) -> f3(0,B,C) [0 >= C] (1,1) 5. f3(A,B,C) -> f5(0,B,C) [-1*C >= 0 && A + -1*C >= 0 && -1*A + -1*C >= 0 && -1*A >= 0 && A >= 0 && 0 >= B] (?,1) Signature: {(f0,3);(f2,3);(f3,3);(f5,3)} Flow Graph: [0->{0},1->{1,5},2->{2},3->{0},4->{1,5},5->{2}] + Applied Processor: TrivialSCCs + Details: All trivial SCCs of the transition graph admit timebound 1. * Step 2: Looptree NO + Considered Problem: Rules: 0. f2(A,B,C) -> f2(1 + A,B,C) [-1 + C >= 0 && -1 + A + C >= 0 && A >= 0] (?,1) 1. f3(A,B,C) -> f3(A,-1 + B,C) [-1*C >= 0 && A + -1*C >= 0 && -1*A + -1*C >= 0 && -1*A >= 0 && A >= 0 && B >= 1] (?,1) 2. f5(A,B,C) -> f5(A,B,1) [-1*B >= 0 && A + -1*B >= 0 && -1*A + -1*B >= 0 && -1*A >= 0 && A >= 0] (?,1) 3. f0(A,B,C) -> f2(0,B,C) [C >= 1] (1,1) 4. f0(A,B,C) -> f3(0,B,C) [0 >= C] (1,1) 5. f3(A,B,C) -> f5(0,B,C) [-1*C >= 0 && A + -1*C >= 0 && -1*A + -1*C >= 0 && -1*A >= 0 && A >= 0 && 0 >= B] (1,1) Signature: {(f0,3);(f2,3);(f3,3);(f5,3)} Flow Graph: [0->{0},1->{1,5},2->{2},3->{0},4->{1,5},5->{2}] + Applied Processor: Looptree + Details: We construct a looptree: P: [0,1,2,3,4,5] | +- p:[1] c: [1] | +- p:[2] c: [] | `- p:[0] c: [] NO