YES * Step 1: UnsatPaths YES + Considered Problem: Rules: 0. f0(A,B,C) -> f1(A,B,2) [A >= 0 && 3 >= A && 3 >= B && B >= 0] (1,1) 1. f1(A,B,C) -> f1(A,1 + B,C) [2 + -1*C >= 0 (?,1) && 2 + B + -1*C >= 0 && 5 + -1*B + -1*C >= 0 && 2 + A + -1*C >= 0 && 5 + -1*A + -1*C >= 0 && -2 + C >= 0 && -2 + B + C >= 0 && 1 + -1*B + C >= 0 && -2 + A + C >= 0 && 1 + -1*A + C >= 0 && 3 + -1*B >= 0 && 3 + A + -1*B >= 0 && 6 + -1*A + -1*B >= 0 && B >= 0 && A + B >= 0 && 3 + -1*A + B >= 0 && 3 + -1*A >= 0 && A >= 0 && A + C >= 1 + 2*B] 2. f1(A,B,C) -> f1(A,-1 + B,C) [2 + -1*C >= 0 (?,1) && 2 + B + -1*C >= 0 && 5 + -1*B + -1*C >= 0 && 2 + A + -1*C >= 0 && 5 + -1*A + -1*C >= 0 && -2 + C >= 0 && -2 + B + C >= 0 && 1 + -1*B + C >= 0 && -2 + A + C >= 0 && 1 + -1*A + C >= 0 && 3 + -1*B >= 0 && 3 + A + -1*B >= 0 && 6 + -1*A + -1*B >= 0 && B >= 0 && A + B >= 0 && 3 + -1*A + B >= 0 && 3 + -1*A >= 0 && A >= 0 && 2*B >= 2 + A + C] Signature: {(f0,3);(f1,3)} Flow Graph: [0->{1,2},1->{1,2},2->{1,2}] + Applied Processor: UnsatPaths + Details: We remove following edges from the transition graph: [(1,2),(2,1)] * Step 2: Looptree YES + Considered Problem: Rules: 0. f0(A,B,C) -> f1(A,B,2) [A >= 0 && 3 >= A && 3 >= B && B >= 0] (1,1) 1. f1(A,B,C) -> f1(A,1 + B,C) [2 + -1*C >= 0 (?,1) && 2 + B + -1*C >= 0 && 5 + -1*B + -1*C >= 0 && 2 + A + -1*C >= 0 && 5 + -1*A + -1*C >= 0 && -2 + C >= 0 && -2 + B + C >= 0 && 1 + -1*B + C >= 0 && -2 + A + C >= 0 && 1 + -1*A + C >= 0 && 3 + -1*B >= 0 && 3 + A + -1*B >= 0 && 6 + -1*A + -1*B >= 0 && B >= 0 && A + B >= 0 && 3 + -1*A + B >= 0 && 3 + -1*A >= 0 && A >= 0 && A + C >= 1 + 2*B] 2. f1(A,B,C) -> f1(A,-1 + B,C) [2 + -1*C >= 0 (?,1) && 2 + B + -1*C >= 0 && 5 + -1*B + -1*C >= 0 && 2 + A + -1*C >= 0 && 5 + -1*A + -1*C >= 0 && -2 + C >= 0 && -2 + B + C >= 0 && 1 + -1*B + C >= 0 && -2 + A + C >= 0 && 1 + -1*A + C >= 0 && 3 + -1*B >= 0 && 3 + A + -1*B >= 0 && 6 + -1*A + -1*B >= 0 && B >= 0 && A + B >= 0 && 3 + -1*A + B >= 0 && 3 + -1*A >= 0 && A >= 0 && 2*B >= 2 + A + C] Signature: {(f0,3);(f1,3)} Flow Graph: [0->{1,2},1->{1},2->{2}] + Applied Processor: Looptree + Details: We construct a looptree: P: [0,1,2] | +- p:[2] c: [2] | `- p:[1] c: [1] YES