YES * Step 1: TrivialSCCs YES + Considered Problem: Rules: 0. f0(A,B,C,D) -> f19(A,999,C,1) True (1,1) 1. f19(A,B,C,D) -> f19(A,-1 + B,C,D) [1 + -1*D >= 0 (?,1) && 1000 + -1*B + -1*D >= 0 && -1 + D >= 0 && 998 + -1*B + D >= 0 && 999 + -1*B >= 0 && B >= 0] 2. f19(A,B,C,D) -> f28(A,B,999,D) [1 + -1*D >= 0 (?,1) && 1000 + -1*B + -1*D >= 0 && -1 + D >= 0 && 998 + -1*B + D >= 0 && 999 + -1*B >= 0 && 0 >= 1 + B] 3. f28(A,B,C,D) -> f28(A,B,-1 + C,D) [1 + -1*D >= 0 (?,1) && 1000 + -1*C + -1*D >= 0 && -1*B + -1*D >= 0 && -1 + D >= 0 && 998 + -1*C + D >= 0 && -2 + -1*B + D >= 0 && 999 + -1*C >= 0 && 998 + -1*B + -1*C >= 0 && -1 + -1*B >= 0 && C >= 0] 4. f28(A,B,C,D) -> f36(A,B,C,D) [1 + -1*D >= 0 (?,1) && 1000 + -1*C + -1*D >= 0 && -1*B + -1*D >= 0 && -1 + D >= 0 && 998 + -1*C + D >= 0 && -2 + -1*B + D >= 0 && 999 + -1*C >= 0 && 998 + -1*B + -1*C >= 0 && -1 + -1*B >= 0 && 0 >= 1 + C] Signature: {(f0,4);(f19,4);(f28,4);(f36,4)} Flow Graph: [0->{1,2},1->{1,2},2->{3,4},3->{3,4},4->{}] + Applied Processor: TrivialSCCs + Details: All trivial SCCs of the transition graph admit timebound 1. * Step 2: UnsatPaths YES + Considered Problem: Rules: 0. f0(A,B,C,D) -> f19(A,999,C,1) True (1,1) 1. f19(A,B,C,D) -> f19(A,-1 + B,C,D) [1 + -1*D >= 0 (?,1) && 1000 + -1*B + -1*D >= 0 && -1 + D >= 0 && 998 + -1*B + D >= 0 && 999 + -1*B >= 0 && B >= 0] 2. f19(A,B,C,D) -> f28(A,B,999,D) [1 + -1*D >= 0 (1,1) && 1000 + -1*B + -1*D >= 0 && -1 + D >= 0 && 998 + -1*B + D >= 0 && 999 + -1*B >= 0 && 0 >= 1 + B] 3. f28(A,B,C,D) -> f28(A,B,-1 + C,D) [1 + -1*D >= 0 (?,1) && 1000 + -1*C + -1*D >= 0 && -1*B + -1*D >= 0 && -1 + D >= 0 && 998 + -1*C + D >= 0 && -2 + -1*B + D >= 0 && 999 + -1*C >= 0 && 998 + -1*B + -1*C >= 0 && -1 + -1*B >= 0 && C >= 0] 4. f28(A,B,C,D) -> f36(A,B,C,D) [1 + -1*D >= 0 (1,1) && 1000 + -1*C + -1*D >= 0 && -1*B + -1*D >= 0 && -1 + D >= 0 && 998 + -1*C + D >= 0 && -2 + -1*B + D >= 0 && 999 + -1*C >= 0 && 998 + -1*B + -1*C >= 0 && -1 + -1*B >= 0 && 0 >= 1 + C] Signature: {(f0,4);(f19,4);(f28,4);(f36,4)} Flow Graph: [0->{1,2},1->{1,2},2->{3,4},3->{3,4},4->{}] + Applied Processor: UnsatPaths + Details: We remove following edges from the transition graph: [(0,2),(2,4)] * Step 3: Looptree YES + Considered Problem: Rules: 0. f0(A,B,C,D) -> f19(A,999,C,1) True (1,1) 1. f19(A,B,C,D) -> f19(A,-1 + B,C,D) [1 + -1*D >= 0 (?,1) && 1000 + -1*B + -1*D >= 0 && -1 + D >= 0 && 998 + -1*B + D >= 0 && 999 + -1*B >= 0 && B >= 0] 2. f19(A,B,C,D) -> f28(A,B,999,D) [1 + -1*D >= 0 (1,1) && 1000 + -1*B + -1*D >= 0 && -1 + D >= 0 && 998 + -1*B + D >= 0 && 999 + -1*B >= 0 && 0 >= 1 + B] 3. f28(A,B,C,D) -> f28(A,B,-1 + C,D) [1 + -1*D >= 0 (?,1) && 1000 + -1*C + -1*D >= 0 && -1*B + -1*D >= 0 && -1 + D >= 0 && 998 + -1*C + D >= 0 && -2 + -1*B + D >= 0 && 999 + -1*C >= 0 && 998 + -1*B + -1*C >= 0 && -1 + -1*B >= 0 && C >= 0] 4. f28(A,B,C,D) -> f36(A,B,C,D) [1 + -1*D >= 0 (1,1) && 1000 + -1*C + -1*D >= 0 && -1*B + -1*D >= 0 && -1 + D >= 0 && 998 + -1*C + D >= 0 && -2 + -1*B + D >= 0 && 999 + -1*C >= 0 && 998 + -1*B + -1*C >= 0 && -1 + -1*B >= 0 && 0 >= 1 + C] Signature: {(f0,4);(f19,4);(f28,4);(f36,4)} Flow Graph: [0->{1},1->{1,2},2->{3},3->{3,4},4->{}] + Applied Processor: Looptree + Details: We construct a looptree: P: [0,1,2,3,4] | +- p:[1] c: [1] | `- p:[3] c: [3] YES