YES
* Step 1: TrivialSCCs YES
    + Considered Problem:
        Rules:
          0. f0(A,B,C,D,E,F,G)  -> f12(H,I,J,0,E,F,G)     True                                                                                              (1,1)
          1. f12(A,B,C,D,E,F,G) -> f12(A,B,C,1 + D,E,F,G) [D >= 0 && C >= 1 + D]                                                                            (?,1)
          2. f25(A,B,C,D,E,F,G) -> f25(A,B,C,D,E,1 + F,G) [F >= 0 && D + F >= 0 && A + -1*E >= 0 && -1*A + E >= 0 && D >= 0 && -1*C + D >= 0 && E >= 1 + F] (?,1)
          3. f25(A,B,C,D,E,F,G) -> f34(A,B,C,D,E,F,G)     [F >= 0 && D + F >= 0 && A + -1*E >= 0 && -1*A + E >= 0 && D >= 0 && -1*C + D >= 0 && F >= E]     (?,1)
          4. f12(A,B,C,D,E,F,G) -> f25(A,B,C,D,A,0,H)     [D >= 0 && D >= C]                                                                                (?,1)
        Signature:
          {(f0,7);(f12,7);(f25,7);(f34,7)}
        Flow Graph:
          [0->{1,4},1->{1,4},2->{2,3},3->{},4->{2,3}]
        
    + Applied Processor:
        TrivialSCCs
    + Details:
        All trivial SCCs of the transition graph admit timebound 1.
* Step 2: Looptree YES
    + Considered Problem:
        Rules:
          0. f0(A,B,C,D,E,F,G)  -> f12(H,I,J,0,E,F,G)     True                                                                                              (1,1)
          1. f12(A,B,C,D,E,F,G) -> f12(A,B,C,1 + D,E,F,G) [D >= 0 && C >= 1 + D]                                                                            (?,1)
          2. f25(A,B,C,D,E,F,G) -> f25(A,B,C,D,E,1 + F,G) [F >= 0 && D + F >= 0 && A + -1*E >= 0 && -1*A + E >= 0 && D >= 0 && -1*C + D >= 0 && E >= 1 + F] (?,1)
          3. f25(A,B,C,D,E,F,G) -> f34(A,B,C,D,E,F,G)     [F >= 0 && D + F >= 0 && A + -1*E >= 0 && -1*A + E >= 0 && D >= 0 && -1*C + D >= 0 && F >= E]     (1,1)
          4. f12(A,B,C,D,E,F,G) -> f25(A,B,C,D,A,0,H)     [D >= 0 && D >= C]                                                                                (1,1)
        Signature:
          {(f0,7);(f12,7);(f25,7);(f34,7)}
        Flow Graph:
          [0->{1,4},1->{1,4},2->{2,3},3->{},4->{2,3}]
        
    + Applied Processor:
        Looptree
    + Details:
        We construct a looptree:
          P: [0,1,2,3,4]
          |
          +- p:[1] c: [1]
          |
          `- p:[2] c: [2]

YES