YES * Step 1: TrivialSCCs YES + Considered Problem: Rules: 0. f12(A,B,C,D,E,F) -> f5(400,0,0,D,E,F) True (1,1) 1. f5(A,B,C,D,E,F) -> f5(A,1 + B,G,H,E,G) [B >= 0 (?,1) && -400 + A + B >= 0 && 400 + -1*A + B >= 0 && 400 + -1*A >= 0 && -400 + A >= 0 && A >= 1 + B && C = 0] 2. f5(A,B,C,D,E,F) -> f10(A,B,C,C,C,F) [B >= 0 && -400 + A + B >= 0 && 400 + -1*A + B >= 0 && 400 + -1*A >= 0 && -400 + A >= 0 && 0 >= 1 + C] (?,1) 3. f5(A,B,C,D,E,F) -> f10(A,B,C,C,C,F) [B >= 0 && -400 + A + B >= 0 && 400 + -1*A + B >= 0 && 400 + -1*A >= 0 && -400 + A >= 0 && C >= 1] (?,1) 4. f5(A,B,C,D,E,F) -> f11(A,B,0,0,0,F) [B >= 0 && -400 + A + B >= 0 && 400 + -1*A + B >= 0 && 400 + -1*A >= 0 && -400 + A >= 0 && B >= A && C = 0] (?,1) Signature: {(f10,6);(f11,6);(f12,6);(f5,6)} Flow Graph: [0->{1,2,3,4},1->{1,2,3,4},2->{},3->{},4->{}] + Applied Processor: TrivialSCCs + Details: All trivial SCCs of the transition graph admit timebound 1. * Step 2: UnsatPaths YES + Considered Problem: Rules: 0. f12(A,B,C,D,E,F) -> f5(400,0,0,D,E,F) True (1,1) 1. f5(A,B,C,D,E,F) -> f5(A,1 + B,G,H,E,G) [B >= 0 (?,1) && -400 + A + B >= 0 && 400 + -1*A + B >= 0 && 400 + -1*A >= 0 && -400 + A >= 0 && A >= 1 + B && C = 0] 2. f5(A,B,C,D,E,F) -> f10(A,B,C,C,C,F) [B >= 0 && -400 + A + B >= 0 && 400 + -1*A + B >= 0 && 400 + -1*A >= 0 && -400 + A >= 0 && 0 >= 1 + C] (1,1) 3. f5(A,B,C,D,E,F) -> f10(A,B,C,C,C,F) [B >= 0 && -400 + A + B >= 0 && 400 + -1*A + B >= 0 && 400 + -1*A >= 0 && -400 + A >= 0 && C >= 1] (1,1) 4. f5(A,B,C,D,E,F) -> f11(A,B,0,0,0,F) [B >= 0 && -400 + A + B >= 0 && 400 + -1*A + B >= 0 && 400 + -1*A >= 0 && -400 + A >= 0 && B >= A && C = 0] (1,1) Signature: {(f10,6);(f11,6);(f12,6);(f5,6)} Flow Graph: [0->{1,2,3,4},1->{1,2,3,4},2->{},3->{},4->{}] + Applied Processor: UnsatPaths + Details: We remove following edges from the transition graph: [(0,2),(0,3),(0,4)] * Step 3: Looptree YES + Considered Problem: Rules: 0. f12(A,B,C,D,E,F) -> f5(400,0,0,D,E,F) True (1,1) 1. f5(A,B,C,D,E,F) -> f5(A,1 + B,G,H,E,G) [B >= 0 (?,1) && -400 + A + B >= 0 && 400 + -1*A + B >= 0 && 400 + -1*A >= 0 && -400 + A >= 0 && A >= 1 + B && C = 0] 2. f5(A,B,C,D,E,F) -> f10(A,B,C,C,C,F) [B >= 0 && -400 + A + B >= 0 && 400 + -1*A + B >= 0 && 400 + -1*A >= 0 && -400 + A >= 0 && 0 >= 1 + C] (1,1) 3. f5(A,B,C,D,E,F) -> f10(A,B,C,C,C,F) [B >= 0 && -400 + A + B >= 0 && 400 + -1*A + B >= 0 && 400 + -1*A >= 0 && -400 + A >= 0 && C >= 1] (1,1) 4. f5(A,B,C,D,E,F) -> f11(A,B,0,0,0,F) [B >= 0 && -400 + A + B >= 0 && 400 + -1*A + B >= 0 && 400 + -1*A >= 0 && -400 + A >= 0 && B >= A && C = 0] (1,1) Signature: {(f10,6);(f11,6);(f12,6);(f5,6)} Flow Graph: [0->{1},1->{1,2,3,4},2->{},3->{},4->{}] + Applied Processor: Looptree + Details: We construct a looptree: P: [0,1,2,3,4] | `- p:[1] c: [1] YES