YES
* Step 1: TrivialSCCs YES
    + Considered Problem:
        Rules:
          0. f0(A,B,C,D,E,F,G,H,I,J) -> f5(K,0,0,D,E,F,G,H,I,J)         True                                                         (1,1)
          1. f5(A,B,C,D,E,F,G,H,I,J) -> f5(A,1 + B,1 + C,1,E,F,G,H,I,J) [C >= 0 && B + C >= 0 && -1*B + C >= 0 && B >= 0 && 15 >= C] (?,1)
          2. f5(A,B,C,D,E,F,G,H,I,J) -> f5(A,B,1 + C,0,E,F,G,H,I,J)     [C >= 0 && B + C >= 0 && -1*B + C >= 0 && B >= 0 && 15 >= C] (?,1)
          3. f5(A,B,C,D,E,F,G,H,I,J) -> f27(A,B,C,D,B,B,K,L,L,L)        [C >= 0 && B + C >= 0 && -1*B + C >= 0 && B >= 0 && C >= 16] (?,1)
        Signature:
          {(f0,10);(f27,10);(f5,10)}
        Flow Graph:
          [0->{1,2,3},1->{1,2,3},2->{1,2,3},3->{}]
        
    + Applied Processor:
        TrivialSCCs
    + Details:
        All trivial SCCs of the transition graph admit timebound 1.
* Step 2: UnsatPaths YES
    + Considered Problem:
        Rules:
          0. f0(A,B,C,D,E,F,G,H,I,J) -> f5(K,0,0,D,E,F,G,H,I,J)         True                                                         (1,1)
          1. f5(A,B,C,D,E,F,G,H,I,J) -> f5(A,1 + B,1 + C,1,E,F,G,H,I,J) [C >= 0 && B + C >= 0 && -1*B + C >= 0 && B >= 0 && 15 >= C] (?,1)
          2. f5(A,B,C,D,E,F,G,H,I,J) -> f5(A,B,1 + C,0,E,F,G,H,I,J)     [C >= 0 && B + C >= 0 && -1*B + C >= 0 && B >= 0 && 15 >= C] (?,1)
          3. f5(A,B,C,D,E,F,G,H,I,J) -> f27(A,B,C,D,B,B,K,L,L,L)        [C >= 0 && B + C >= 0 && -1*B + C >= 0 && B >= 0 && C >= 16] (1,1)
        Signature:
          {(f0,10);(f27,10);(f5,10)}
        Flow Graph:
          [0->{1,2,3},1->{1,2,3},2->{1,2,3},3->{}]
        
    + Applied Processor:
        UnsatPaths
    + Details:
        We remove following edges from the transition graph: [(0,3)]
* Step 3: Looptree YES
    + Considered Problem:
        Rules:
          0. f0(A,B,C,D,E,F,G,H,I,J) -> f5(K,0,0,D,E,F,G,H,I,J)         True                                                         (1,1)
          1. f5(A,B,C,D,E,F,G,H,I,J) -> f5(A,1 + B,1 + C,1,E,F,G,H,I,J) [C >= 0 && B + C >= 0 && -1*B + C >= 0 && B >= 0 && 15 >= C] (?,1)
          2. f5(A,B,C,D,E,F,G,H,I,J) -> f5(A,B,1 + C,0,E,F,G,H,I,J)     [C >= 0 && B + C >= 0 && -1*B + C >= 0 && B >= 0 && 15 >= C] (?,1)
          3. f5(A,B,C,D,E,F,G,H,I,J) -> f27(A,B,C,D,B,B,K,L,L,L)        [C >= 0 && B + C >= 0 && -1*B + C >= 0 && B >= 0 && C >= 16] (1,1)
        Signature:
          {(f0,10);(f27,10);(f5,10)}
        Flow Graph:
          [0->{1,2},1->{1,2,3},2->{1,2,3},3->{}]
        
    + Applied Processor:
        Looptree
    + Details:
        We construct a looptree:
          P: [0,1,2,3]
          |
          `- p:[1,2] c: [2]
             |
             `- p:[1] c: [1]

YES