YES
* Step 1: Looptree YES
    + Considered Problem:
        Rules:
          0. start(A,B,C) -> eval(A,B,C)         True                       (1,1)
          1. eval(A,B,C)  -> eval(A,1 + B,1 + C) [A >= 1 + B && A >= 1 + C] (?,1)
        Signature:
          {(eval,3);(start,3)}
        Flow Graph:
          [0->{1},1->{1}]
        
    + Applied Processor:
        Looptree
    + Details:
        We construct a looptree:
          P: [0,1]
          |
          `- p:[1] c: [1]

YES