YES
* Step 1: TrivialSCCs YES
    + Considered Problem:
        Rules:
          0. start(A,B) -> div(A,B)        True                   (1,1)
          1. div(A,B)   -> div(A,-1*A + B) [B >= 1 + A && A >= 1] (?,1)
          2. div(A,B)   -> end(A,B)        [A >= B]               (?,1)
          3. div(A,B)   -> end(A,B)        [0 >= A]               (?,1)
        Signature:
          {(div,2);(end,2);(start,2)}
        Flow Graph:
          [0->{1,2,3},1->{1,2,3},2->{},3->{}]
        
    + Applied Processor:
        TrivialSCCs
    + Details:
        All trivial SCCs of the transition graph admit timebound 1.
* Step 2: UnsatPaths YES
    + Considered Problem:
        Rules:
          0. start(A,B) -> div(A,B)        True                   (1,1)
          1. div(A,B)   -> div(A,-1*A + B) [B >= 1 + A && A >= 1] (?,1)
          2. div(A,B)   -> end(A,B)        [A >= B]               (1,1)
          3. div(A,B)   -> end(A,B)        [0 >= A]               (1,1)
        Signature:
          {(div,2);(end,2);(start,2)}
        Flow Graph:
          [0->{1,2,3},1->{1,2,3},2->{},3->{}]
        
    + Applied Processor:
        UnsatPaths
    + Details:
        We remove following edges from the transition graph: [(1,3)]
* Step 3: Looptree YES
    + Considered Problem:
        Rules:
          0. start(A,B) -> div(A,B)        True                   (1,1)
          1. div(A,B)   -> div(A,-1*A + B) [B >= 1 + A && A >= 1] (?,1)
          2. div(A,B)   -> end(A,B)        [A >= B]               (1,1)
          3. div(A,B)   -> end(A,B)        [0 >= A]               (1,1)
        Signature:
          {(div,2);(end,2);(start,2)}
        Flow Graph:
          [0->{1,2,3},1->{1,2},2->{},3->{}]
        
    + Applied Processor:
        Looptree
    + Details:
        We construct a looptree:
          P: [0,1,2,3]
          |
          `- p:[1] c: [1]

YES