MAYBE * Step 1: TrivialSCCs MAYBE + Considered Problem: Rules: 0. f0(A,B,C,D,E,F,G) -> f2(H,B,I,D,E,F,G) [A >= B] (?,1) 1. f0(A,B,C,D,E,F,G) -> f0(H,B,C,I,0,F,G) [B >= 1 + A] (?,1) 2. f0(A,B,C,D,E,F,G) -> f0(H,B,C,I,J,K,G) [0 >= 1 + J && B >= 1 + A] (?,1) 3. f0(A,B,C,D,E,F,G) -> f0(H,B,C,I,J,K,G) [J >= 1 && B >= 1 + A] (?,1) 4. f1(A,B,C,D,E,F,G) -> f0(A,B,C,D,E,F,H) True (1,1) Signature: {(f0,7);(f1,7);(f2,7)} Flow Graph: [0->{},1->{0,1,2,3},2->{0,1,2,3},3->{0,1,2,3},4->{0,1,2,3}] + Applied Processor: TrivialSCCs + Details: All trivial SCCs of the transition graph admit timebound 1. * Step 2: AddSinks MAYBE + Considered Problem: Rules: 0. f0(A,B,C,D,E,F,G) -> f2(H,B,I,D,E,F,G) [A >= B] (1,1) 1. f0(A,B,C,D,E,F,G) -> f0(H,B,C,I,0,F,G) [B >= 1 + A] (?,1) 2. f0(A,B,C,D,E,F,G) -> f0(H,B,C,I,J,K,G) [0 >= 1 + J && B >= 1 + A] (?,1) 3. f0(A,B,C,D,E,F,G) -> f0(H,B,C,I,J,K,G) [J >= 1 && B >= 1 + A] (?,1) 4. f1(A,B,C,D,E,F,G) -> f0(A,B,C,D,E,F,H) True (1,1) Signature: {(f0,7);(f1,7);(f2,7)} Flow Graph: [0->{},1->{0,1,2,3},2->{0,1,2,3},3->{0,1,2,3},4->{0,1,2,3}] + Applied Processor: AddSinks + Details: () * Step 3: Failure MAYBE + Considered Problem: Rules: 0. f0(A,B,C,D,E,F,G) -> f2(H,B,I,D,E,F,G) [A >= B] (?,1) 1. f0(A,B,C,D,E,F,G) -> f0(H,B,C,I,0,F,G) [B >= 1 + A] (?,1) 2. f0(A,B,C,D,E,F,G) -> f0(H,B,C,I,J,K,G) [0 >= 1 + J && B >= 1 + A] (?,1) 3. f0(A,B,C,D,E,F,G) -> f0(H,B,C,I,J,K,G) [J >= 1 && B >= 1 + A] (?,1) 4. f1(A,B,C,D,E,F,G) -> f0(A,B,C,D,E,F,H) True (1,1) 5. f0(A,B,C,D,E,F,G) -> exitus616(A,B,C,D,E,F,G) True (?,1) Signature: {(exitus616,7);(f0,7);(f1,7);(f2,7)} Flow Graph: [0->{},1->{0,1,2,3,5},2->{0,1,2,3,5},3->{0,1,2,3,5},4->{0,1,2,3,5},5->{}] + Applied Processor: LooptreeTransformer + Details: We construct a looptree: P: [0,1,2,3,4,5] | `- p:[1,2,3] c: [] MAYBE