MAYBE * Step 1: TrivialSCCs MAYBE + Considered Problem: Rules: 0. f2(A,B,C,D,E,F,G,H,I,J,K) -> f2(A,B,M,N,L,O,G,H,I,J,K) [L >= 1 && B >= 1 + A] (?,1) 1. f2(A,B,C,D,E,F,G,H,I,J,K) -> f2(A,B,M,N,L,O,G,H,I,J,K) [0 >= 1 + L && B >= 1 + A] (?,1) 2. f2(A,B,C,D,E,F,G,H,I,J,K) -> f2(A,B,M,N,0,F,G,H,I,J,K) [B >= 1 + A] (?,1) 3. f2(A,B,C,D,E,F,G,H,I,J,K) -> f300(A,B,M,N,E,F,L,H,I,J,K) [A >= B] (?,1) 4. f1(A,B,C,D,E,F,G,H,I,J,K) -> f2(A,B,C,D,E,F,G,M,N,N,M) True (1,1) Signature: {(f1,11);(f2,11);(f300,11)} Flow Graph: [0->{0,1,2,3},1->{0,1,2,3},2->{0,1,2,3},3->{},4->{0,1,2,3}] + Applied Processor: TrivialSCCs + Details: All trivial SCCs of the transition graph admit timebound 1. * Step 2: UnsatPaths MAYBE + Considered Problem: Rules: 0. f2(A,B,C,D,E,F,G,H,I,J,K) -> f2(A,B,M,N,L,O,G,H,I,J,K) [L >= 1 && B >= 1 + A] (?,1) 1. f2(A,B,C,D,E,F,G,H,I,J,K) -> f2(A,B,M,N,L,O,G,H,I,J,K) [0 >= 1 + L && B >= 1 + A] (?,1) 2. f2(A,B,C,D,E,F,G,H,I,J,K) -> f2(A,B,M,N,0,F,G,H,I,J,K) [B >= 1 + A] (?,1) 3. f2(A,B,C,D,E,F,G,H,I,J,K) -> f300(A,B,M,N,E,F,L,H,I,J,K) [A >= B] (1,1) 4. f1(A,B,C,D,E,F,G,H,I,J,K) -> f2(A,B,C,D,E,F,G,M,N,N,M) True (1,1) Signature: {(f1,11);(f2,11);(f300,11)} Flow Graph: [0->{0,1,2,3},1->{0,1,2,3},2->{0,1,2,3},3->{},4->{0,1,2,3}] + Applied Processor: UnsatPaths + Details: We remove following edges from the transition graph: [(0,3),(1,3),(2,3)] * Step 3: AddSinks MAYBE + Considered Problem: Rules: 0. f2(A,B,C,D,E,F,G,H,I,J,K) -> f2(A,B,M,N,L,O,G,H,I,J,K) [L >= 1 && B >= 1 + A] (?,1) 1. f2(A,B,C,D,E,F,G,H,I,J,K) -> f2(A,B,M,N,L,O,G,H,I,J,K) [0 >= 1 + L && B >= 1 + A] (?,1) 2. f2(A,B,C,D,E,F,G,H,I,J,K) -> f2(A,B,M,N,0,F,G,H,I,J,K) [B >= 1 + A] (?,1) 3. f2(A,B,C,D,E,F,G,H,I,J,K) -> f300(A,B,M,N,E,F,L,H,I,J,K) [A >= B] (1,1) 4. f1(A,B,C,D,E,F,G,H,I,J,K) -> f2(A,B,C,D,E,F,G,M,N,N,M) True (1,1) Signature: {(f1,11);(f2,11);(f300,11)} Flow Graph: [0->{0,1,2},1->{0,1,2},2->{0,1,2},3->{},4->{0,1,2,3}] + Applied Processor: AddSinks + Details: () * Step 4: UnsatPaths MAYBE + Considered Problem: Rules: 0. f2(A,B,C,D,E,F,G,H,I,J,K) -> f2(A,B,M,N,L,O,G,H,I,J,K) [L >= 1 && B >= 1 + A] (?,1) 1. f2(A,B,C,D,E,F,G,H,I,J,K) -> f2(A,B,M,N,L,O,G,H,I,J,K) [0 >= 1 + L && B >= 1 + A] (?,1) 2. f2(A,B,C,D,E,F,G,H,I,J,K) -> f2(A,B,M,N,0,F,G,H,I,J,K) [B >= 1 + A] (?,1) 3. f2(A,B,C,D,E,F,G,H,I,J,K) -> f300(A,B,M,N,E,F,L,H,I,J,K) [A >= B] (?,1) 4. f1(A,B,C,D,E,F,G,H,I,J,K) -> f2(A,B,C,D,E,F,G,M,N,N,M) True (1,1) 5. f2(A,B,C,D,E,F,G,H,I,J,K) -> exitus616(A,B,C,D,E,F,G,H,I,J,K) True (?,1) Signature: {(exitus616,11);(f1,11);(f2,11);(f300,11)} Flow Graph: [0->{0,1,2,3,5},1->{0,1,2,3,5},2->{0,1,2,3,5},3->{},4->{0,1,2,3,5},5->{}] + Applied Processor: UnsatPaths + Details: We remove following edges from the transition graph: [(0,3),(1,3),(2,3)] * Step 5: Failure MAYBE + Considered Problem: Rules: 0. f2(A,B,C,D,E,F,G,H,I,J,K) -> f2(A,B,M,N,L,O,G,H,I,J,K) [L >= 1 && B >= 1 + A] (?,1) 1. f2(A,B,C,D,E,F,G,H,I,J,K) -> f2(A,B,M,N,L,O,G,H,I,J,K) [0 >= 1 + L && B >= 1 + A] (?,1) 2. f2(A,B,C,D,E,F,G,H,I,J,K) -> f2(A,B,M,N,0,F,G,H,I,J,K) [B >= 1 + A] (?,1) 3. f2(A,B,C,D,E,F,G,H,I,J,K) -> f300(A,B,M,N,E,F,L,H,I,J,K) [A >= B] (?,1) 4. f1(A,B,C,D,E,F,G,H,I,J,K) -> f2(A,B,C,D,E,F,G,M,N,N,M) True (1,1) 5. f2(A,B,C,D,E,F,G,H,I,J,K) -> exitus616(A,B,C,D,E,F,G,H,I,J,K) True (?,1) Signature: {(exitus616,11);(f1,11);(f2,11);(f300,11)} Flow Graph: [0->{0,1,2,5},1->{0,1,2,5},2->{0,1,2,5},3->{},4->{0,1,2,3,5},5->{}] + Applied Processor: LooptreeTransformer + Details: We construct a looptree: P: [0,1,2,3,4,5] | `- p:[0,1,2] c: [] MAYBE