MAYBE * Step 1: TrivialSCCs MAYBE + Considered Problem: Rules: 0. f1(A,B,C,D,E,F,G,H) -> f1(A,B,I,J,K,F,G,H) [A >= 1 + B] (?,1) 1. f1(A,B,C,D,E,F,G,H) -> f1(A,B,I,J,K,F,G,H) [B >= 1 + A] (?,1) 2. f1(A,B,C,D,E,F,G,H) -> f300(A,A,I,J,E,K,G,H) [A = B] (?,1) 3. f2(A,B,C,D,E,F,G,H) -> f1(A,B,C,D,E,F,I,J) True (1,1) Signature: {(f1,8);(f2,8);(f300,8)} Flow Graph: [0->{0,1,2},1->{0,1,2},2->{},3->{0,1,2}] + Applied Processor: TrivialSCCs + Details: All trivial SCCs of the transition graph admit timebound 1. * Step 2: UnsatPaths MAYBE + Considered Problem: Rules: 0. f1(A,B,C,D,E,F,G,H) -> f1(A,B,I,J,K,F,G,H) [A >= 1 + B] (?,1) 1. f1(A,B,C,D,E,F,G,H) -> f1(A,B,I,J,K,F,G,H) [B >= 1 + A] (?,1) 2. f1(A,B,C,D,E,F,G,H) -> f300(A,A,I,J,E,K,G,H) [A = B] (1,1) 3. f2(A,B,C,D,E,F,G,H) -> f1(A,B,C,D,E,F,I,J) True (1,1) Signature: {(f1,8);(f2,8);(f300,8)} Flow Graph: [0->{0,1,2},1->{0,1,2},2->{},3->{0,1,2}] + Applied Processor: UnsatPaths + Details: We remove following edges from the transition graph: [(0,1),(0,2),(1,0),(1,2)] * Step 3: AddSinks MAYBE + Considered Problem: Rules: 0. f1(A,B,C,D,E,F,G,H) -> f1(A,B,I,J,K,F,G,H) [A >= 1 + B] (?,1) 1. f1(A,B,C,D,E,F,G,H) -> f1(A,B,I,J,K,F,G,H) [B >= 1 + A] (?,1) 2. f1(A,B,C,D,E,F,G,H) -> f300(A,A,I,J,E,K,G,H) [A = B] (1,1) 3. f2(A,B,C,D,E,F,G,H) -> f1(A,B,C,D,E,F,I,J) True (1,1) Signature: {(f1,8);(f2,8);(f300,8)} Flow Graph: [0->{0},1->{1},2->{},3->{0,1,2}] + Applied Processor: AddSinks + Details: () * Step 4: UnsatPaths MAYBE + Considered Problem: Rules: 0. f1(A,B,C,D,E,F,G,H) -> f1(A,B,I,J,K,F,G,H) [A >= 1 + B] (?,1) 1. f1(A,B,C,D,E,F,G,H) -> f1(A,B,I,J,K,F,G,H) [B >= 1 + A] (?,1) 2. f1(A,B,C,D,E,F,G,H) -> f300(A,A,I,J,E,K,G,H) [A = B] (?,1) 3. f2(A,B,C,D,E,F,G,H) -> f1(A,B,C,D,E,F,I,J) True (1,1) 4. f1(A,B,C,D,E,F,G,H) -> exitus616(A,B,C,D,E,F,G,H) True (?,1) Signature: {(exitus616,8);(f1,8);(f2,8);(f300,8)} Flow Graph: [0->{0,1,2,4},1->{0,1,2,4},2->{},3->{0,1,2,4},4->{}] + Applied Processor: UnsatPaths + Details: We remove following edges from the transition graph: [(0,1),(0,2),(1,0),(1,2)] * Step 5: Failure MAYBE + Considered Problem: Rules: 0. f1(A,B,C,D,E,F,G,H) -> f1(A,B,I,J,K,F,G,H) [A >= 1 + B] (?,1) 1. f1(A,B,C,D,E,F,G,H) -> f1(A,B,I,J,K,F,G,H) [B >= 1 + A] (?,1) 2. f1(A,B,C,D,E,F,G,H) -> f300(A,A,I,J,E,K,G,H) [A = B] (?,1) 3. f2(A,B,C,D,E,F,G,H) -> f1(A,B,C,D,E,F,I,J) True (1,1) 4. f1(A,B,C,D,E,F,G,H) -> exitus616(A,B,C,D,E,F,G,H) True (?,1) Signature: {(exitus616,8);(f1,8);(f2,8);(f300,8)} Flow Graph: [0->{0,4},1->{1,4},2->{},3->{0,1,2,4},4->{}] + Applied Processor: LooptreeTransformer + Details: We construct a looptree: P: [0,1,2,3,4] | +- p:[1] c: [] | `- p:[0] c: [] MAYBE