MAYBE
* Step 1: TrivialSCCs MAYBE
    + Considered Problem:
        Rules:
          0. f2(A,B,C,D,E,F) -> f2(1 + A,G,G,D,E,F) [G >= 1 && A >= 1]     (?,1)
          1. f2(A,B,C,D,E,F) -> f2(1 + A,G,G,D,E,F) [0 >= 1 + G && A >= 1] (?,1)
          2. f2(A,B,C,D,E,F) -> f0(A,0,0,G,E,F)     True                   (?,1)
          3. f3(A,B,C,D,E,F) -> f2(1 + A,G,G,D,E,F) [G >= 1 && A >= 1]     (?,1)
          4. f3(A,B,C,D,E,F) -> f2(1 + A,G,G,D,E,F) [0 >= 1 + G && A >= 1] (?,1)
          5. f3(A,B,C,D,E,F) -> f0(A,0,0,G,E,F)     True                   (?,1)
          6. f4(A,B,C,D,E,F) -> f2(1 + H,G,G,D,H,H) [G >= 1 && H >= 1]     (1,1)
          7. f4(A,B,C,D,E,F) -> f2(1 + H,G,G,D,H,H) [0 >= 1 + G && H >= 1] (1,1)
          8. f4(A,B,C,D,E,F) -> f0(G,0,0,H,G,G)     True                   (1,1)
        Signature:
          {(f0,6);(f2,6);(f3,6);(f4,6)}
        Flow Graph:
          [0->{0,1,2},1->{0,1,2},2->{},3->{0,1,2},4->{0,1,2},5->{},6->{0,1,2},7->{0,1,2},8->{}]
        
    + Applied Processor:
        TrivialSCCs
    + Details:
        All trivial SCCs of the transition graph admit timebound 1.
* Step 2: UnreachableRules MAYBE
    + Considered Problem:
        Rules:
          0. f2(A,B,C,D,E,F) -> f2(1 + A,G,G,D,E,F) [G >= 1 && A >= 1]     (?,1)
          1. f2(A,B,C,D,E,F) -> f2(1 + A,G,G,D,E,F) [0 >= 1 + G && A >= 1] (?,1)
          2. f2(A,B,C,D,E,F) -> f0(A,0,0,G,E,F)     True                   (1,1)
          3. f3(A,B,C,D,E,F) -> f2(1 + A,G,G,D,E,F) [G >= 1 && A >= 1]     (1,1)
          4. f3(A,B,C,D,E,F) -> f2(1 + A,G,G,D,E,F) [0 >= 1 + G && A >= 1] (1,1)
          5. f3(A,B,C,D,E,F) -> f0(A,0,0,G,E,F)     True                   (1,1)
          6. f4(A,B,C,D,E,F) -> f2(1 + H,G,G,D,H,H) [G >= 1 && H >= 1]     (1,1)
          7. f4(A,B,C,D,E,F) -> f2(1 + H,G,G,D,H,H) [0 >= 1 + G && H >= 1] (1,1)
          8. f4(A,B,C,D,E,F) -> f0(G,0,0,H,G,G)     True                   (1,1)
        Signature:
          {(f0,6);(f2,6);(f3,6);(f4,6)}
        Flow Graph:
          [0->{0,1,2},1->{0,1,2},2->{},3->{0,1,2},4->{0,1,2},5->{},6->{0,1,2},7->{0,1,2},8->{}]
        
    + Applied Processor:
        UnreachableRules
    + Details:
        Following transitions are not reachable from the starting states and are revomed: [3,4,5]
* Step 3: AddSinks MAYBE
    + Considered Problem:
        Rules:
          0. f2(A,B,C,D,E,F) -> f2(1 + A,G,G,D,E,F) [G >= 1 && A >= 1]     (?,1)
          1. f2(A,B,C,D,E,F) -> f2(1 + A,G,G,D,E,F) [0 >= 1 + G && A >= 1] (?,1)
          2. f2(A,B,C,D,E,F) -> f0(A,0,0,G,E,F)     True                   (1,1)
          6. f4(A,B,C,D,E,F) -> f2(1 + H,G,G,D,H,H) [G >= 1 && H >= 1]     (1,1)
          7. f4(A,B,C,D,E,F) -> f2(1 + H,G,G,D,H,H) [0 >= 1 + G && H >= 1] (1,1)
          8. f4(A,B,C,D,E,F) -> f0(G,0,0,H,G,G)     True                   (1,1)
        Signature:
          {(f0,6);(f2,6);(f3,6);(f4,6)}
        Flow Graph:
          [0->{0,1,2},1->{0,1,2},2->{},6->{0,1,2},7->{0,1,2},8->{}]
        
    + Applied Processor:
        AddSinks
    + Details:
        ()
* Step 4: Failure MAYBE
  + Considered Problem:
      Rules:
        0.  f2(A,B,C,D,E,F) -> f2(1 + A,G,G,D,E,F)    [G >= 1 && A >= 1]     (?,1)
        1.  f2(A,B,C,D,E,F) -> f2(1 + A,G,G,D,E,F)    [0 >= 1 + G && A >= 1] (?,1)
        2.  f2(A,B,C,D,E,F) -> f0(A,0,0,G,E,F)        True                   (?,1)
        6.  f4(A,B,C,D,E,F) -> f2(1 + H,G,G,D,H,H)    [G >= 1 && H >= 1]     (1,1)
        7.  f4(A,B,C,D,E,F) -> f2(1 + H,G,G,D,H,H)    [0 >= 1 + G && H >= 1] (1,1)
        8.  f4(A,B,C,D,E,F) -> f0(G,0,0,H,G,G)        True                   (1,1)
        9.  f4(A,B,C,D,E,F) -> exitus616(A,B,C,D,E,F) True                   (1,1)
        10. f2(A,B,C,D,E,F) -> exitus616(A,B,C,D,E,F) True                   (?,1)
      Signature:
        {(exitus616,6);(f0,6);(f2,6);(f3,6);(f4,6)}
      Flow Graph:
        [0->{0,1,2,10},1->{0,1,2,10},2->{},6->{0,1,2,10},7->{0,1,2,10},8->{},9->{},10->{}]
      
  + Applied Processor:
      LooptreeTransformer
  + Details:
      We construct a looptree:
        P: [0,1,2,6,7,8,9,10]
        |
        `- p:[0,1] c: []
MAYBE