MAYBE * Step 1: TrivialSCCs MAYBE + Considered Problem: Rules: 0. f4(A,B,C,D,E) -> f5(A,1,C,D,E) [A >= 2] (?,1) 1. f4(A,B,C,D,E) -> f5(A,0,C,D,E) [1 >= A] (?,1) 2. f30(A,B,C,D,E) -> f4(2,B,2,F,E) True (1,1) 3. f5(A,B,C,D,E) -> f4(-1 + A,B,C,F,E) [0 >= F && F >= 1] (?,1) 4. f5(A,B,C,D,E) -> f4(1 + A,B,C,F,E) [F >= 1] (?,1) 5. f5(A,B,C,D,E) -> f3(A,B,C,D,0) [0 >= B] (?,1) Signature: {(f3,5);(f30,5);(f4,5);(f5,5)} Flow Graph: [0->{3,4,5},1->{3,4,5},2->{0,1},3->{0,1},4->{0,1},5->{}] + Applied Processor: TrivialSCCs + Details: All trivial SCCs of the transition graph admit timebound 1. * Step 2: UnsatRules MAYBE + Considered Problem: Rules: 0. f4(A,B,C,D,E) -> f5(A,1,C,D,E) [A >= 2] (?,1) 1. f4(A,B,C,D,E) -> f5(A,0,C,D,E) [1 >= A] (?,1) 2. f30(A,B,C,D,E) -> f4(2,B,2,F,E) True (1,1) 3. f5(A,B,C,D,E) -> f4(-1 + A,B,C,F,E) [0 >= F && F >= 1] (?,1) 4. f5(A,B,C,D,E) -> f4(1 + A,B,C,F,E) [F >= 1] (?,1) 5. f5(A,B,C,D,E) -> f3(A,B,C,D,0) [0 >= B] (1,1) Signature: {(f3,5);(f30,5);(f4,5);(f5,5)} Flow Graph: [0->{3,4,5},1->{3,4,5},2->{0,1},3->{0,1},4->{0,1},5->{}] + Applied Processor: UnsatRules + Details: Following transitions have unsatisfiable constraints and are removed: [3] * Step 3: UnsatPaths MAYBE + Considered Problem: Rules: 0. f4(A,B,C,D,E) -> f5(A,1,C,D,E) [A >= 2] (?,1) 1. f4(A,B,C,D,E) -> f5(A,0,C,D,E) [1 >= A] (?,1) 2. f30(A,B,C,D,E) -> f4(2,B,2,F,E) True (1,1) 4. f5(A,B,C,D,E) -> f4(1 + A,B,C,F,E) [F >= 1] (?,1) 5. f5(A,B,C,D,E) -> f3(A,B,C,D,0) [0 >= B] (1,1) Signature: {(f3,5);(f30,5);(f4,5);(f5,5)} Flow Graph: [0->{4,5},1->{4,5},2->{0,1},4->{0,1},5->{}] + Applied Processor: UnsatPaths + Details: We remove following edges from the transition graph: [(0,5),(2,1)] * Step 4: AddSinks MAYBE + Considered Problem: Rules: 0. f4(A,B,C,D,E) -> f5(A,1,C,D,E) [A >= 2] (?,1) 1. f4(A,B,C,D,E) -> f5(A,0,C,D,E) [1 >= A] (?,1) 2. f30(A,B,C,D,E) -> f4(2,B,2,F,E) True (1,1) 4. f5(A,B,C,D,E) -> f4(1 + A,B,C,F,E) [F >= 1] (?,1) 5. f5(A,B,C,D,E) -> f3(A,B,C,D,0) [0 >= B] (1,1) Signature: {(f3,5);(f30,5);(f4,5);(f5,5)} Flow Graph: [0->{4},1->{4,5},2->{0},4->{0,1},5->{}] + Applied Processor: AddSinks + Details: () * Step 5: UnsatPaths MAYBE + Considered Problem: Rules: 0. f4(A,B,C,D,E) -> f5(A,1,C,D,E) [A >= 2] (?,1) 1. f4(A,B,C,D,E) -> f5(A,0,C,D,E) [1 >= A] (?,1) 2. f30(A,B,C,D,E) -> f4(2,B,2,F,E) True (1,1) 4. f5(A,B,C,D,E) -> f4(1 + A,B,C,F,E) [F >= 1] (?,1) 5. f5(A,B,C,D,E) -> f3(A,B,C,D,0) [0 >= B] (?,1) 6. f5(A,B,C,D,E) -> exitus616(A,B,C,D,E) True (?,1) Signature: {(exitus616,5);(f3,5);(f30,5);(f4,5);(f5,5)} Flow Graph: [0->{4,5,6},1->{4,5,6},2->{0,1},4->{0,1},5->{},6->{}] + Applied Processor: UnsatPaths + Details: We remove following edges from the transition graph: [(0,5),(2,1)] * Step 6: Failure MAYBE + Considered Problem: Rules: 0. f4(A,B,C,D,E) -> f5(A,1,C,D,E) [A >= 2] (?,1) 1. f4(A,B,C,D,E) -> f5(A,0,C,D,E) [1 >= A] (?,1) 2. f30(A,B,C,D,E) -> f4(2,B,2,F,E) True (1,1) 4. f5(A,B,C,D,E) -> f4(1 + A,B,C,F,E) [F >= 1] (?,1) 5. f5(A,B,C,D,E) -> f3(A,B,C,D,0) [0 >= B] (?,1) 6. f5(A,B,C,D,E) -> exitus616(A,B,C,D,E) True (?,1) Signature: {(exitus616,5);(f3,5);(f30,5);(f4,5);(f5,5)} Flow Graph: [0->{4,6},1->{4,5,6},2->{0},4->{0,1},5->{},6->{}] + Applied Processor: LooptreeTransformer + Details: We construct a looptree: P: [0,1,2,4,5,6] | `- p:[0,4,1] c: [1] | `- p:[0,4] c: [] MAYBE