MAYBE * Step 1: TrivialSCCs MAYBE + Considered Problem: Rules: 0. f20(A,B,C,D,E,F,G,H,I,J,K,L,M,N,O) -> f28(A,B,C,D,E,F,G,H,I,J,K,L,M,N,O) [0 >= A] (?,1) 1. f40(A,B,C,D,E,F,G,H,I,J,K,L,M,N,O) -> f40(A,B,C,D,E,F,G,H,I,J,K,L,M,N,O) True (?,1) 2. f42(A,B,C,D,E,F,G,H,I,J,K,L,M,N,O) -> f45(A,B,C,D,E,F,G,H,I,J,K,L,M,N,O) True (?,1) 3. f28(A,B,C,D,E,F,G,H,I,J,K,L,M,N,O) -> f40(A,B,C,D,E,F,G,H,I,J,K,L,M,N,O) [A >= 1] (?,1) 4. f28(A,B,C,D,E,F,G,H,I,J,K,L,M,N,O) -> f40(A,B,0,P,P,P,G,H,I,J,K,L,M,N,O) [0 >= A && 999 + B >= P] (?,1) 5. f28(A,B,C,D,E,F,G,H,I,J,K,L,M,N,O) -> f40(1,B,0,P,P,P,G,H,I,J,K,L,M,N,O) [0 >= A && P >= 1000 + B] (?,1) 6. f20(A,B,C,D,E,F,G,H,I,J,K,L,M,N,O) -> f28(0,P,C,D,E,F,0,P,P,J,K,L,M,N,O) [A >= 1] (?,1) 7. f0(A,B,C,D,E,F,G,H,I,J,K,L,M,N,O) -> f20(1,B,C,D,E,F,G,H,I,P,K,L,M,N,O) [0 >= P] (1,1) 8. f0(A,B,C,D,E,F,G,H,I,J,K,L,M,N,O) -> f20(1,B,C,D,E,F,G,H,I,0,1,P,P,P,P) [P >= 1 && Q >= 1] (1,1) 9. f0(A,B,C,D,E,F,G,H,I,J,K,L,M,N,O) -> f40(1,B,C,D,E,F,G,H,I,0,1,P,P,P,P) [0 >= P && Q >= 1] (1,1) Signature: {(f0,15);(f20,15);(f28,15);(f40,15);(f42,15);(f45,15)} Flow Graph: [0->{3,4,5},1->{1},2->{},3->{1},4->{1},5->{1},6->{3,4,5},7->{0,6},8->{0,6},9->{1}] + Applied Processor: TrivialSCCs + Details: All trivial SCCs of the transition graph admit timebound 1. * Step 2: UnsatPaths MAYBE + Considered Problem: Rules: 0. f20(A,B,C,D,E,F,G,H,I,J,K,L,M,N,O) -> f28(A,B,C,D,E,F,G,H,I,J,K,L,M,N,O) [0 >= A] (1,1) 1. f40(A,B,C,D,E,F,G,H,I,J,K,L,M,N,O) -> f40(A,B,C,D,E,F,G,H,I,J,K,L,M,N,O) True (?,1) 2. f42(A,B,C,D,E,F,G,H,I,J,K,L,M,N,O) -> f45(A,B,C,D,E,F,G,H,I,J,K,L,M,N,O) True (1,1) 3. f28(A,B,C,D,E,F,G,H,I,J,K,L,M,N,O) -> f40(A,B,C,D,E,F,G,H,I,J,K,L,M,N,O) [A >= 1] (1,1) 4. f28(A,B,C,D,E,F,G,H,I,J,K,L,M,N,O) -> f40(A,B,0,P,P,P,G,H,I,J,K,L,M,N,O) [0 >= A && 999 + B >= P] (1,1) 5. f28(A,B,C,D,E,F,G,H,I,J,K,L,M,N,O) -> f40(1,B,0,P,P,P,G,H,I,J,K,L,M,N,O) [0 >= A && P >= 1000 + B] (1,1) 6. f20(A,B,C,D,E,F,G,H,I,J,K,L,M,N,O) -> f28(0,P,C,D,E,F,0,P,P,J,K,L,M,N,O) [A >= 1] (1,1) 7. f0(A,B,C,D,E,F,G,H,I,J,K,L,M,N,O) -> f20(1,B,C,D,E,F,G,H,I,P,K,L,M,N,O) [0 >= P] (1,1) 8. f0(A,B,C,D,E,F,G,H,I,J,K,L,M,N,O) -> f20(1,B,C,D,E,F,G,H,I,0,1,P,P,P,P) [P >= 1 && Q >= 1] (1,1) 9. f0(A,B,C,D,E,F,G,H,I,J,K,L,M,N,O) -> f40(1,B,C,D,E,F,G,H,I,0,1,P,P,P,P) [0 >= P && Q >= 1] (1,1) Signature: {(f0,15);(f20,15);(f28,15);(f40,15);(f42,15);(f45,15)} Flow Graph: [0->{3,4,5},1->{1},2->{},3->{1},4->{1},5->{1},6->{3,4,5},7->{0,6},8->{0,6},9->{1}] + Applied Processor: UnsatPaths + Details: We remove following edges from the transition graph: [(0,3),(6,3),(7,0),(8,0)] * Step 3: UnreachableRules MAYBE + Considered Problem: Rules: 0. f20(A,B,C,D,E,F,G,H,I,J,K,L,M,N,O) -> f28(A,B,C,D,E,F,G,H,I,J,K,L,M,N,O) [0 >= A] (1,1) 1. f40(A,B,C,D,E,F,G,H,I,J,K,L,M,N,O) -> f40(A,B,C,D,E,F,G,H,I,J,K,L,M,N,O) True (?,1) 2. f42(A,B,C,D,E,F,G,H,I,J,K,L,M,N,O) -> f45(A,B,C,D,E,F,G,H,I,J,K,L,M,N,O) True (1,1) 3. f28(A,B,C,D,E,F,G,H,I,J,K,L,M,N,O) -> f40(A,B,C,D,E,F,G,H,I,J,K,L,M,N,O) [A >= 1] (1,1) 4. f28(A,B,C,D,E,F,G,H,I,J,K,L,M,N,O) -> f40(A,B,0,P,P,P,G,H,I,J,K,L,M,N,O) [0 >= A && 999 + B >= P] (1,1) 5. f28(A,B,C,D,E,F,G,H,I,J,K,L,M,N,O) -> f40(1,B,0,P,P,P,G,H,I,J,K,L,M,N,O) [0 >= A && P >= 1000 + B] (1,1) 6. f20(A,B,C,D,E,F,G,H,I,J,K,L,M,N,O) -> f28(0,P,C,D,E,F,0,P,P,J,K,L,M,N,O) [A >= 1] (1,1) 7. f0(A,B,C,D,E,F,G,H,I,J,K,L,M,N,O) -> f20(1,B,C,D,E,F,G,H,I,P,K,L,M,N,O) [0 >= P] (1,1) 8. f0(A,B,C,D,E,F,G,H,I,J,K,L,M,N,O) -> f20(1,B,C,D,E,F,G,H,I,0,1,P,P,P,P) [P >= 1 && Q >= 1] (1,1) 9. f0(A,B,C,D,E,F,G,H,I,J,K,L,M,N,O) -> f40(1,B,C,D,E,F,G,H,I,0,1,P,P,P,P) [0 >= P && Q >= 1] (1,1) Signature: {(f0,15);(f20,15);(f28,15);(f40,15);(f42,15);(f45,15)} Flow Graph: [0->{4,5},1->{1},2->{},3->{1},4->{1},5->{1},6->{4,5},7->{6},8->{6},9->{1}] + Applied Processor: UnreachableRules + Details: Following transitions are not reachable from the starting states and are revomed: [0,2,3] * Step 4: AddSinks MAYBE + Considered Problem: Rules: 1. f40(A,B,C,D,E,F,G,H,I,J,K,L,M,N,O) -> f40(A,B,C,D,E,F,G,H,I,J,K,L,M,N,O) True (?,1) 4. f28(A,B,C,D,E,F,G,H,I,J,K,L,M,N,O) -> f40(A,B,0,P,P,P,G,H,I,J,K,L,M,N,O) [0 >= A && 999 + B >= P] (1,1) 5. f28(A,B,C,D,E,F,G,H,I,J,K,L,M,N,O) -> f40(1,B,0,P,P,P,G,H,I,J,K,L,M,N,O) [0 >= A && P >= 1000 + B] (1,1) 6. f20(A,B,C,D,E,F,G,H,I,J,K,L,M,N,O) -> f28(0,P,C,D,E,F,0,P,P,J,K,L,M,N,O) [A >= 1] (1,1) 7. f0(A,B,C,D,E,F,G,H,I,J,K,L,M,N,O) -> f20(1,B,C,D,E,F,G,H,I,P,K,L,M,N,O) [0 >= P] (1,1) 8. f0(A,B,C,D,E,F,G,H,I,J,K,L,M,N,O) -> f20(1,B,C,D,E,F,G,H,I,0,1,P,P,P,P) [P >= 1 && Q >= 1] (1,1) 9. f0(A,B,C,D,E,F,G,H,I,J,K,L,M,N,O) -> f40(1,B,C,D,E,F,G,H,I,0,1,P,P,P,P) [0 >= P && Q >= 1] (1,1) Signature: {(f0,15);(f20,15);(f28,15);(f40,15);(f42,15);(f45,15)} Flow Graph: [1->{1},4->{1},5->{1},6->{4,5},7->{6},8->{6},9->{1}] + Applied Processor: AddSinks + Details: () * Step 5: Failure MAYBE + Considered Problem: Rules: 1. f40(A,B,C,D,E,F,G,H,I,J,K,L,M,N,O) -> f40(A,B,C,D,E,F,G,H,I,J,K,L,M,N,O) True (?,1) 4. f28(A,B,C,D,E,F,G,H,I,J,K,L,M,N,O) -> f40(A,B,0,P,P,P,G,H,I,J,K,L,M,N,O) [0 >= A && 999 + B >= P] (?,1) 5. f28(A,B,C,D,E,F,G,H,I,J,K,L,M,N,O) -> f40(1,B,0,P,P,P,G,H,I,J,K,L,M,N,O) [0 >= A && P >= 1000 + B] (?,1) 6. f20(A,B,C,D,E,F,G,H,I,J,K,L,M,N,O) -> f28(0,P,C,D,E,F,0,P,P,J,K,L,M,N,O) [A >= 1] (?,1) 7. f0(A,B,C,D,E,F,G,H,I,J,K,L,M,N,O) -> f20(1,B,C,D,E,F,G,H,I,P,K,L,M,N,O) [0 >= P] (1,1) 8. f0(A,B,C,D,E,F,G,H,I,J,K,L,M,N,O) -> f20(1,B,C,D,E,F,G,H,I,0,1,P,P,P,P) [P >= 1 && Q >= 1] (1,1) 9. f0(A,B,C,D,E,F,G,H,I,J,K,L,M,N,O) -> f40(1,B,C,D,E,F,G,H,I,0,1,P,P,P,P) [0 >= P && Q >= 1] (1,1) 10. f40(A,B,C,D,E,F,G,H,I,J,K,L,M,N,O) -> exitus616(A,B,C,D,E,F,G,H,I,J,K,L,M,N,O) True (?,1) Signature: {(exitus616,15);(f0,15);(f20,15);(f28,15);(f40,15);(f42,15);(f45,15)} Flow Graph: [1->{1,10},4->{1,10},5->{1,10},6->{4,5},7->{6},8->{6},9->{1,10},10->{}] + Applied Processor: LooptreeTransformer + Details: We construct a looptree: P: [1,4,5,6,7,8,9,10] | `- p:[1] c: [] MAYBE