YES(?,O(1))
* Step 1: TrivialSCCs WORST_CASE(?,O(1))
    + Considered Problem:
        Rules:
          0. evalndloopstart(A)    -> evalndloopentryin(A)  True                                           (1,1)
          1. evalndloopentryin(A)  -> evalndloopbbin(0)     True                                           (?,1)
          2. evalndloopbbin(A)     -> evalndloopbbin(B)     [A >= 0 && 2 + A >= B && B >= 1 + A && 9 >= B] (?,1)
          3. evalndloopbbin(A)     -> evalndloopreturnin(A) [A >= 0 && B >= 3 + A]                         (?,1)
          4. evalndloopbbin(A)     -> evalndloopreturnin(A) [A >= 0 && A >= B]                             (?,1)
          5. evalndloopbbin(A)     -> evalndloopreturnin(A) [A >= 0 && B >= 10]                            (?,1)
          6. evalndloopreturnin(A) -> evalndloopstop(A)     [A >= 0]                                       (?,1)
        Signature:
          {(evalndloopbbin,1);(evalndloopentryin,1);(evalndloopreturnin,1);(evalndloopstart,1);(evalndloopstop,1)}
        Flow Graph:
          [0->{1},1->{2,3,4,5},2->{2,3,4,5},3->{6},4->{6},5->{6},6->{}]
        
    + Applied Processor:
        TrivialSCCs
    + Details:
        All trivial SCCs of the transition graph admit timebound 1.
* Step 2: AddSinks WORST_CASE(?,O(1))
    + Considered Problem:
        Rules:
          0. evalndloopstart(A)    -> evalndloopentryin(A)  True                                           (1,1)
          1. evalndloopentryin(A)  -> evalndloopbbin(0)     True                                           (1,1)
          2. evalndloopbbin(A)     -> evalndloopbbin(B)     [A >= 0 && 2 + A >= B && B >= 1 + A && 9 >= B] (?,1)
          3. evalndloopbbin(A)     -> evalndloopreturnin(A) [A >= 0 && B >= 3 + A]                         (1,1)
          4. evalndloopbbin(A)     -> evalndloopreturnin(A) [A >= 0 && A >= B]                             (1,1)
          5. evalndloopbbin(A)     -> evalndloopreturnin(A) [A >= 0 && B >= 10]                            (1,1)
          6. evalndloopreturnin(A) -> evalndloopstop(A)     [A >= 0]                                       (1,1)
        Signature:
          {(evalndloopbbin,1);(evalndloopentryin,1);(evalndloopreturnin,1);(evalndloopstart,1);(evalndloopstop,1)}
        Flow Graph:
          [0->{1},1->{2,3,4,5},2->{2,3,4,5},3->{6},4->{6},5->{6},6->{}]
        
    + Applied Processor:
        AddSinks
    + Details:
        ()
* Step 3: LooptreeTransformer WORST_CASE(?,O(1))
    + Considered Problem:
        Rules:
          0. evalndloopstart(A)    -> evalndloopentryin(A)  True                                           (1,1)
          1. evalndloopentryin(A)  -> evalndloopbbin(0)     True                                           (?,1)
          2. evalndloopbbin(A)     -> evalndloopbbin(B)     [A >= 0 && 2 + A >= B && B >= 1 + A && 9 >= B] (?,1)
          3. evalndloopbbin(A)     -> evalndloopreturnin(A) [A >= 0 && B >= 3 + A]                         (?,1)
          4. evalndloopbbin(A)     -> evalndloopreturnin(A) [A >= 0 && A >= B]                             (?,1)
          5. evalndloopbbin(A)     -> evalndloopreturnin(A) [A >= 0 && B >= 10]                            (?,1)
          6. evalndloopreturnin(A) -> evalndloopstop(A)     [A >= 0]                                       (?,1)
          7. evalndloopreturnin(A) -> exitus616(A)          True                                           (?,1)
        Signature:
          {(evalndloopbbin,1)
          ;(evalndloopentryin,1)
          ;(evalndloopreturnin,1)
          ;(evalndloopstart,1)
          ;(evalndloopstop,1)
          ;(exitus616,1)}
        Flow Graph:
          [0->{1},1->{2,3,4,5},2->{2,3,4,5},3->{6,7},4->{6,7},5->{6,7},6->{},7->{}]
        
    + Applied Processor:
        LooptreeTransformer
    + Details:
        We construct a looptree:
          P: [0,1,2,3,4,5,6,7]
          |
          `- p:[2] c: [2]
* Step 4: SizeAbstraction WORST_CASE(?,O(1))
    + Considered Problem:
        (Rules:
          0. evalndloopstart(A)    -> evalndloopentryin(A)  True                                           (1,1)
          1. evalndloopentryin(A)  -> evalndloopbbin(0)     True                                           (?,1)
          2. evalndloopbbin(A)     -> evalndloopbbin(B)     [A >= 0 && 2 + A >= B && B >= 1 + A && 9 >= B] (?,1)
          3. evalndloopbbin(A)     -> evalndloopreturnin(A) [A >= 0 && B >= 3 + A]                         (?,1)
          4. evalndloopbbin(A)     -> evalndloopreturnin(A) [A >= 0 && A >= B]                             (?,1)
          5. evalndloopbbin(A)     -> evalndloopreturnin(A) [A >= 0 && B >= 10]                            (?,1)
          6. evalndloopreturnin(A) -> evalndloopstop(A)     [A >= 0]                                       (?,1)
          7. evalndloopreturnin(A) -> exitus616(A)          True                                           (?,1)
        Signature:
          {(evalndloopbbin,1)
          ;(evalndloopentryin,1)
          ;(evalndloopreturnin,1)
          ;(evalndloopstart,1)
          ;(evalndloopstop,1)
          ;(exitus616,1)}
        Flow Graph:
          [0->{1},1->{2,3,4,5},2->{2,3,4,5},3->{6,7},4->{6,7},5->{6,7},6->{},7->{}]
        
        ,We construct a looptree:
          P: [0,1,2,3,4,5,6,7]
          |
          `- p:[2] c: [2])
    + Applied Processor:
        SizeAbstraction UseCFG Minimize
    + Details:
        ()
* Step 5: FlowAbstraction WORST_CASE(?,O(1))
    + Considered Problem:
        Program:
          Domain: [A,0.0]
           evalndloopstart     ~>  evalndloopentryin    [A <= A]
           evalndloopentryin   ~>  evalndloopbbin       [A <= 0*K]
           evalndloopbbin      ~>  evalndloopbbin       [A <= 9*K]
           evalndloopbbin      ~>  evalndloopreturnin   [A <= A]
           evalndloopbbin      ~>  evalndloopreturnin   [A <= A]
           evalndloopbbin      ~>  evalndloopreturnin   [A <= A]
           evalndloopreturnin  ~>  evalndloopstop       [A <= A]
           evalndloopreturnin  ~>  exitus616            [A <= A]
          + Loop: [0.0 <= 9*K + A]
               evalndloopbbin  ~>  evalndloopbbin   [A <= 9*K]
    + Applied Processor:
        FlowAbstraction
    + Details:
        ()
* Step 6: LareProcessor WORST_CASE(?,O(1))
    + Considered Problem:
        Program:
          Domain: [tick,huge,K,A,0.0]
           evalndloopstart     ~>  evalndloopentryin    []
           evalndloopentryin   ~>  evalndloopbbin       [K ~=> A]
           evalndloopbbin      ~>  evalndloopbbin       [K ~=> A]
           evalndloopbbin      ~>  evalndloopreturnin   []
           evalndloopbbin      ~>  evalndloopreturnin   []
           evalndloopbbin      ~>  evalndloopreturnin   []
           evalndloopreturnin  ~>  evalndloopstop       []
           evalndloopreturnin  ~>  exitus616            []
          + Loop: [A ~+> 0.0,K ~*> 0.0]
               evalndloopbbin  ~>  evalndloopbbin   [K ~=> A]
    + Applied Processor:
        LareProcessor
    + Details:
         evalndloopstart  ~>  exitus616        [K ~=> A,tick ~+> tick,K ~+> 0.0,K ~+> tick,K ~*> 0.0,K ~*> tick]
         evalndloopstart  ~>  evalndloopstop   [K ~=> A,tick ~+> tick,K ~+> 0.0,K ~+> tick,K ~*> 0.0,K ~*> tick]
        + <evalndloopbbin  ~>  evalndloopbbin>  [K ~=> A,A ~+> 0.0,A ~+> tick,tick ~+> tick,K ~*> 0.0,K ~*> tick]

YES(?,O(1))