YES(?,O(n^1)) * Step 1: AddSinks WORST_CASE(?,O(n^1)) + Considered Problem: Rules: 0. start(A,B,C) -> eval(A,B,C) True (1,1) 1. eval(A,B,C) -> eval(-1 + A,B,-1 + C) [A >= 1 + B && C >= 1 + B] (?,1) Signature: {(eval,3);(start,3)} Flow Graph: [0->{1},1->{1}] + Applied Processor: AddSinks + Details: () * Step 2: LooptreeTransformer WORST_CASE(?,O(n^1)) + Considered Problem: Rules: 0. start(A,B,C) -> eval(A,B,C) True (1,1) 1. eval(A,B,C) -> eval(-1 + A,B,-1 + C) [A >= 1 + B && C >= 1 + B] (?,1) 2. eval(A,B,C) -> exitus616(A,B,C) True (?,1) Signature: {(eval,3);(exitus616,3);(start,3)} Flow Graph: [0->{1,2},1->{1,2},2->{}] + Applied Processor: LooptreeTransformer + Details: We construct a looptree: P: [0,1,2] | `- p:[1] c: [1] * Step 3: SizeAbstraction WORST_CASE(?,O(n^1)) + Considered Problem: (Rules: 0. start(A,B,C) -> eval(A,B,C) True (1,1) 1. eval(A,B,C) -> eval(-1 + A,B,-1 + C) [A >= 1 + B && C >= 1 + B] (?,1) 2. eval(A,B,C) -> exitus616(A,B,C) True (?,1) Signature: {(eval,3);(exitus616,3);(start,3)} Flow Graph: [0->{1,2},1->{1,2},2->{}] ,We construct a looptree: P: [0,1,2] | `- p:[1] c: [1]) + Applied Processor: SizeAbstraction UseCFG Minimize + Details: () * Step 4: FlowAbstraction WORST_CASE(?,O(n^1)) + Considered Problem: Program: Domain: [A,B,C,0.0] start ~> eval [A <= A, B <= B, C <= C] eval ~> eval [A <= A + B, B <= B, C <= B + C] eval ~> exitus616 [A <= A, B <= B, C <= C] + Loop: [0.0 <= A + B] eval ~> eval [A <= A + B, B <= B, C <= B + C] + Applied Processor: FlowAbstraction + Details: () * Step 5: LareProcessor WORST_CASE(?,O(n^1)) + Considered Problem: Program: Domain: [tick,huge,K,A,B,C,0.0] start ~> eval [] eval ~> eval [A ~+> A,B ~+> A,B ~+> C,C ~+> C] eval ~> exitus616 [] + Loop: [A ~+> 0.0,B ~+> 0.0] eval ~> eval [A ~+> A,B ~+> A,B ~+> C,C ~+> C] + Applied Processor: LareProcessor + Details: start ~> exitus616 [A ~+> A ,A ~+> 0.0 ,A ~+> tick ,B ~+> A ,B ~+> C ,B ~+> 0.0 ,B ~+> tick ,C ~+> C ,tick ~+> tick ,A ~*> A ,A ~*> C ,B ~*> A ,B ~*> C] + eval> [A ~+> A ,A ~+> 0.0 ,A ~+> tick ,B ~+> A ,B ~+> C ,B ~+> 0.0 ,B ~+> tick ,C ~+> C ,tick ~+> tick ,A ~*> A ,A ~*> C ,B ~*> A ,B ~*> C] YES(?,O(n^1))