MAYBE Initial complexity problem: 1: T: (Comp: ?, Cost: 1) eval_speedFails1_start(Ar_0, Ar_1, Ar_2, Ar_3) -> Com_1(eval_speedFails1_bb0_in(Ar_0, Ar_1, Ar_2, Ar_3)) (Comp: ?, Cost: 1) eval_speedFails1_bb0_in(Ar_0, Ar_1, Ar_2, Ar_3) -> Com_1(eval_speedFails1_0(Ar_0, Ar_1, Ar_2, Ar_3)) (Comp: ?, Cost: 1) eval_speedFails1_0(Ar_0, Ar_1, Ar_2, Ar_3) -> Com_1(eval_speedFails1_1(Ar_0, Ar_1, Ar_2, Ar_3)) (Comp: ?, Cost: 1) eval_speedFails1_1(Ar_0, Ar_1, Ar_2, Ar_3) -> Com_1(eval_speedFails1_2(Ar_0, Ar_1, Ar_2, Ar_3)) (Comp: ?, Cost: 1) eval_speedFails1_2(Ar_0, Ar_1, Ar_2, Ar_3) -> Com_1(eval_speedFails1_3(Ar_0, Ar_1, Ar_2, Ar_3)) (Comp: ?, Cost: 1) eval_speedFails1_3(Ar_0, Ar_1, Ar_2, Ar_3) -> Com_1(eval_speedFails1_4(Ar_0, Ar_1, Ar_2, Ar_3)) (Comp: ?, Cost: 1) eval_speedFails1_4(Ar_0, Ar_1, Ar_2, Ar_3) -> Com_1(eval_speedFails1_bb1_in(Ar_1, Ar_1, Ar_2, Ar_3)) (Comp: ?, Cost: 1) eval_speedFails1_bb1_in(Ar_0, Ar_1, Ar_2, Ar_3) -> Com_1(eval_speedFails1_bb2_in(Ar_0, Ar_1, Ar_2, Ar_3)) [ Ar_0 <= Ar_3 ] (Comp: ?, Cost: 1) eval_speedFails1_bb1_in(Ar_0, Ar_1, Ar_2, Ar_3) -> Com_1(eval_speedFails1_bb3_in(Ar_0, Ar_1, Ar_2, Ar_3)) [ Ar_0 > Ar_3 ] (Comp: ?, Cost: 1) eval_speedFails1_bb2_in(Ar_0, Ar_1, Ar_2, Ar_3) -> Com_1(eval_speedFails1_bb1_in(Ar_0 + Ar_2, Ar_1, Ar_2, Ar_3)) (Comp: ?, Cost: 1) eval_speedFails1_bb3_in(Ar_0, Ar_1, Ar_2, Ar_3) -> Com_1(eval_speedFails1_stop(Ar_0, Ar_1, Ar_2, Ar_3)) (Comp: 1, Cost: 0) koat_start(Ar_0, Ar_1, Ar_2, Ar_3) -> Com_1(eval_speedFails1_start(Ar_0, Ar_1, Ar_2, Ar_3)) [ 0 <= 0 ] start location: koat_start leaf cost: 0 Repeatedly propagating knowledge in problem 1 produces the following problem: 2: T: (Comp: 1, Cost: 1) eval_speedFails1_start(Ar_0, Ar_1, Ar_2, Ar_3) -> Com_1(eval_speedFails1_bb0_in(Ar_0, Ar_1, Ar_2, Ar_3)) (Comp: 1, Cost: 1) eval_speedFails1_bb0_in(Ar_0, Ar_1, Ar_2, Ar_3) -> Com_1(eval_speedFails1_0(Ar_0, Ar_1, Ar_2, Ar_3)) (Comp: 1, Cost: 1) eval_speedFails1_0(Ar_0, Ar_1, Ar_2, Ar_3) -> Com_1(eval_speedFails1_1(Ar_0, Ar_1, Ar_2, Ar_3)) (Comp: 1, Cost: 1) eval_speedFails1_1(Ar_0, Ar_1, Ar_2, Ar_3) -> Com_1(eval_speedFails1_2(Ar_0, Ar_1, Ar_2, Ar_3)) (Comp: 1, Cost: 1) eval_speedFails1_2(Ar_0, Ar_1, Ar_2, Ar_3) -> Com_1(eval_speedFails1_3(Ar_0, Ar_1, Ar_2, Ar_3)) (Comp: 1, Cost: 1) eval_speedFails1_3(Ar_0, Ar_1, Ar_2, Ar_3) -> Com_1(eval_speedFails1_4(Ar_0, Ar_1, Ar_2, Ar_3)) (Comp: 1, Cost: 1) eval_speedFails1_4(Ar_0, Ar_1, Ar_2, Ar_3) -> Com_1(eval_speedFails1_bb1_in(Ar_1, Ar_1, Ar_2, Ar_3)) (Comp: ?, Cost: 1) eval_speedFails1_bb1_in(Ar_0, Ar_1, Ar_2, Ar_3) -> Com_1(eval_speedFails1_bb2_in(Ar_0, Ar_1, Ar_2, Ar_3)) [ Ar_0 <= Ar_3 ] (Comp: ?, Cost: 1) eval_speedFails1_bb1_in(Ar_0, Ar_1, Ar_2, Ar_3) -> Com_1(eval_speedFails1_bb3_in(Ar_0, Ar_1, Ar_2, Ar_3)) [ Ar_0 > Ar_3 ] (Comp: ?, Cost: 1) eval_speedFails1_bb2_in(Ar_0, Ar_1, Ar_2, Ar_3) -> Com_1(eval_speedFails1_bb1_in(Ar_0 + Ar_2, Ar_1, Ar_2, Ar_3)) (Comp: ?, Cost: 1) eval_speedFails1_bb3_in(Ar_0, Ar_1, Ar_2, Ar_3) -> Com_1(eval_speedFails1_stop(Ar_0, Ar_1, Ar_2, Ar_3)) (Comp: 1, Cost: 0) koat_start(Ar_0, Ar_1, Ar_2, Ar_3) -> Com_1(eval_speedFails1_start(Ar_0, Ar_1, Ar_2, Ar_3)) [ 0 <= 0 ] start location: koat_start leaf cost: 0 A polynomial rank function with Pol(eval_speedFails1_start) = 2 Pol(eval_speedFails1_bb0_in) = 2 Pol(eval_speedFails1_0) = 2 Pol(eval_speedFails1_1) = 2 Pol(eval_speedFails1_2) = 2 Pol(eval_speedFails1_3) = 2 Pol(eval_speedFails1_4) = 2 Pol(eval_speedFails1_bb1_in) = 2 Pol(eval_speedFails1_bb2_in) = 2 Pol(eval_speedFails1_bb3_in) = 1 Pol(eval_speedFails1_stop) = 0 Pol(koat_start) = 2 orients all transitions weakly and the transitions eval_speedFails1_bb3_in(Ar_0, Ar_1, Ar_2, Ar_3) -> Com_1(eval_speedFails1_stop(Ar_0, Ar_1, Ar_2, Ar_3)) eval_speedFails1_bb1_in(Ar_0, Ar_1, Ar_2, Ar_3) -> Com_1(eval_speedFails1_bb3_in(Ar_0, Ar_1, Ar_2, Ar_3)) [ Ar_0 > Ar_3 ] strictly and produces the following problem: 3: T: (Comp: 1, Cost: 1) eval_speedFails1_start(Ar_0, Ar_1, Ar_2, Ar_3) -> Com_1(eval_speedFails1_bb0_in(Ar_0, Ar_1, Ar_2, Ar_3)) (Comp: 1, Cost: 1) eval_speedFails1_bb0_in(Ar_0, Ar_1, Ar_2, Ar_3) -> Com_1(eval_speedFails1_0(Ar_0, Ar_1, Ar_2, Ar_3)) (Comp: 1, Cost: 1) eval_speedFails1_0(Ar_0, Ar_1, Ar_2, Ar_3) -> Com_1(eval_speedFails1_1(Ar_0, Ar_1, Ar_2, Ar_3)) (Comp: 1, Cost: 1) eval_speedFails1_1(Ar_0, Ar_1, Ar_2, Ar_3) -> Com_1(eval_speedFails1_2(Ar_0, Ar_1, Ar_2, Ar_3)) (Comp: 1, Cost: 1) eval_speedFails1_2(Ar_0, Ar_1, Ar_2, Ar_3) -> Com_1(eval_speedFails1_3(Ar_0, Ar_1, Ar_2, Ar_3)) (Comp: 1, Cost: 1) eval_speedFails1_3(Ar_0, Ar_1, Ar_2, Ar_3) -> Com_1(eval_speedFails1_4(Ar_0, Ar_1, Ar_2, Ar_3)) (Comp: 1, Cost: 1) eval_speedFails1_4(Ar_0, Ar_1, Ar_2, Ar_3) -> Com_1(eval_speedFails1_bb1_in(Ar_1, Ar_1, Ar_2, Ar_3)) (Comp: ?, Cost: 1) eval_speedFails1_bb1_in(Ar_0, Ar_1, Ar_2, Ar_3) -> Com_1(eval_speedFails1_bb2_in(Ar_0, Ar_1, Ar_2, Ar_3)) [ Ar_0 <= Ar_3 ] (Comp: 2, Cost: 1) eval_speedFails1_bb1_in(Ar_0, Ar_1, Ar_2, Ar_3) -> Com_1(eval_speedFails1_bb3_in(Ar_0, Ar_1, Ar_2, Ar_3)) [ Ar_0 > Ar_3 ] (Comp: ?, Cost: 1) eval_speedFails1_bb2_in(Ar_0, Ar_1, Ar_2, Ar_3) -> Com_1(eval_speedFails1_bb1_in(Ar_0 + Ar_2, Ar_1, Ar_2, Ar_3)) (Comp: 2, Cost: 1) eval_speedFails1_bb3_in(Ar_0, Ar_1, Ar_2, Ar_3) -> Com_1(eval_speedFails1_stop(Ar_0, Ar_1, Ar_2, Ar_3)) (Comp: 1, Cost: 0) koat_start(Ar_0, Ar_1, Ar_2, Ar_3) -> Com_1(eval_speedFails1_start(Ar_0, Ar_1, Ar_2, Ar_3)) [ 0 <= 0 ] start location: koat_start leaf cost: 0 Applied AI with 'oct' on problem 3 to obtain the following invariants: For symbol eval_speedFails1_bb2_in: -X_1 + X_4 >= 0 For symbol eval_speedFails1_bb3_in: X_1 - X_4 - 1 >= 0 This yielded the following problem: 4: T: (Comp: 1, Cost: 0) koat_start(Ar_0, Ar_1, Ar_2, Ar_3) -> Com_1(eval_speedFails1_start(Ar_0, Ar_1, Ar_2, Ar_3)) [ 0 <= 0 ] (Comp: 2, Cost: 1) eval_speedFails1_bb3_in(Ar_0, Ar_1, Ar_2, Ar_3) -> Com_1(eval_speedFails1_stop(Ar_0, Ar_1, Ar_2, Ar_3)) [ Ar_0 - Ar_3 - 1 >= 0 ] (Comp: ?, Cost: 1) eval_speedFails1_bb2_in(Ar_0, Ar_1, Ar_2, Ar_3) -> Com_1(eval_speedFails1_bb1_in(Ar_0 + Ar_2, Ar_1, Ar_2, Ar_3)) [ -Ar_0 + Ar_3 >= 0 ] (Comp: 2, Cost: 1) eval_speedFails1_bb1_in(Ar_0, Ar_1, Ar_2, Ar_3) -> Com_1(eval_speedFails1_bb3_in(Ar_0, Ar_1, Ar_2, Ar_3)) [ Ar_0 > Ar_3 ] (Comp: ?, Cost: 1) eval_speedFails1_bb1_in(Ar_0, Ar_1, Ar_2, Ar_3) -> Com_1(eval_speedFails1_bb2_in(Ar_0, Ar_1, Ar_2, Ar_3)) [ Ar_0 <= Ar_3 ] (Comp: 1, Cost: 1) eval_speedFails1_4(Ar_0, Ar_1, Ar_2, Ar_3) -> Com_1(eval_speedFails1_bb1_in(Ar_1, Ar_1, Ar_2, Ar_3)) (Comp: 1, Cost: 1) eval_speedFails1_3(Ar_0, Ar_1, Ar_2, Ar_3) -> Com_1(eval_speedFails1_4(Ar_0, Ar_1, Ar_2, Ar_3)) (Comp: 1, Cost: 1) eval_speedFails1_2(Ar_0, Ar_1, Ar_2, Ar_3) -> Com_1(eval_speedFails1_3(Ar_0, Ar_1, Ar_2, Ar_3)) (Comp: 1, Cost: 1) eval_speedFails1_1(Ar_0, Ar_1, Ar_2, Ar_3) -> Com_1(eval_speedFails1_2(Ar_0, Ar_1, Ar_2, Ar_3)) (Comp: 1, Cost: 1) eval_speedFails1_0(Ar_0, Ar_1, Ar_2, Ar_3) -> Com_1(eval_speedFails1_1(Ar_0, Ar_1, Ar_2, Ar_3)) (Comp: 1, Cost: 1) eval_speedFails1_bb0_in(Ar_0, Ar_1, Ar_2, Ar_3) -> Com_1(eval_speedFails1_0(Ar_0, Ar_1, Ar_2, Ar_3)) (Comp: 1, Cost: 1) eval_speedFails1_start(Ar_0, Ar_1, Ar_2, Ar_3) -> Com_1(eval_speedFails1_bb0_in(Ar_0, Ar_1, Ar_2, Ar_3)) start location: koat_start leaf cost: 0 Complexity upper bound ? Time: 2.381 sec (SMT: 2.304 sec)