MAYBE
* Step 1: Failure MAYBE
  + Considered Problem:
      Rules:
        0. f1(A) -> f1(B) [1 >= B && 1 + B >= 0 && C >= 2] (?,1)
        1. f0(A) -> f1(B) [B >= 2]                         (1,1)
      Signature:
        {(f0,1);(f1,1)}
      Flow Graph:
        [0->{0},1->{0}]
      
  + Applied Processor:
      Failing "Open problems left."
  + Details:
      Open problems left.
MAYBE