MAYBE
* Step 1: PolyRank MAYBE
    + Considered Problem:
        Rules:
          0. f0(A,B,C) -> f2(A,B,C)               [A >= 0 && B >= C]                                (1,1)
          1. f2(A,B,C) -> f2(-1 + A,B,-1 + C)     [B + -1*C >= 0 && A >= 0 && A >= 1 && 1 + B >= C] (?,1)
          2. f2(A,B,C) -> f2(A,-1 + B + C,-1 + C) [B + -1*C >= 0 && A >= 0 && B >= 0]               (?,1)
        Signature:
          {(f0,3);(f2,3)}
        Flow Graph:
          [0->{1,2},1->{1,2},2->{1,2}]
        
    + Applied Processor:
        PolyRank {useFarkas = True, withSizebounds = [], shape = Linear}
    + Details:
        We apply a polynomial interpretation of shape linear:
          p(f0) = 1 + x1
          p(f2) = 1 + x1
        
        Following rules are strictly oriented:
        [B + -1*C >= 0 && A >= 0 && A >= 1 && 1 + B >= C] ==>                    
                                                f2(A,B,C)   = 1 + A              
                                                            > A                  
                                                            = f2(-1 + A,B,-1 + C)
        
        
        Following rules are weakly oriented:
                         [A >= 0 && B >= C] ==>                        
                                  f0(A,B,C)   = 1 + A                  
                                             >= 1 + A                  
                                              = f2(A,B,C)              
        
        [B + -1*C >= 0 && A >= 0 && B >= 0] ==>                        
                                  f2(A,B,C)   = 1 + A                  
                                             >= 1 + A                  
                                              = f2(A,-1 + B + C,-1 + C)
        
        
* Step 2: Failure MAYBE
  + Considered Problem:
      Rules:
        0. f0(A,B,C) -> f2(A,B,C)               [A >= 0 && B >= C]                                (1,1)    
        1. f2(A,B,C) -> f2(-1 + A,B,-1 + C)     [B + -1*C >= 0 && A >= 0 && A >= 1 && 1 + B >= C] (1 + A,1)
        2. f2(A,B,C) -> f2(A,-1 + B + C,-1 + C) [B + -1*C >= 0 && A >= 0 && B >= 0]               (?,1)    
      Signature:
        {(f0,3);(f2,3)}
      Flow Graph:
        [0->{1,2},1->{1,2},2->{1,2}]
      
  + Applied Processor:
      Failing "Open problems left."
  + Details:
      Open problems left.
MAYBE