MAYBE
* Step 1: UnsatPaths MAYBE
    + Considered Problem:
        Rules:
          0. f0(A,B) -> f4(C,0)     True                                           (1,1)
          1. f4(A,B) -> f4(A,1 + B) [B >= 0 && 0 >= 1 + C]                         (?,1)
          2. f4(A,B) -> f4(A,1 + B) [B >= 0]                                       (?,1)
          3. f4(A,B) -> f14(A,B)    [B >= 0 && A >= 0 && B >= 1 + A]               (?,1)
          4. f4(A,B) -> f14(A,B)    [B >= 0 && 0 >= 1 + A]                         (?,1)
          5. f4(A,B) -> f14(A,B)    [B >= 0 && A >= 0 && A >= B]                   (?,1)
          6. f4(A,B) -> f14(A,B)    [B >= 0 && 0 >= 1 + C && A >= 0 && B >= 1 + A] (?,1)
        Signature:
          {(f0,2);(f14,2);(f4,2)}
        Flow Graph:
          [0->{1,2,3,4,5,6},1->{1,2,3,4,5,6},2->{1,2,3,4,5,6},3->{},4->{},5->{},6->{}]
        
    + Applied Processor:
        UnsatPaths
    + Details:
        We remove following edges from the transition graph: [(0,3),(0,6)]
* Step 2: TrivialSCCs MAYBE
    + Considered Problem:
        Rules:
          0. f0(A,B) -> f4(C,0)     True                                           (1,1)
          1. f4(A,B) -> f4(A,1 + B) [B >= 0 && 0 >= 1 + C]                         (?,1)
          2. f4(A,B) -> f4(A,1 + B) [B >= 0]                                       (?,1)
          3. f4(A,B) -> f14(A,B)    [B >= 0 && A >= 0 && B >= 1 + A]               (?,1)
          4. f4(A,B) -> f14(A,B)    [B >= 0 && 0 >= 1 + A]                         (?,1)
          5. f4(A,B) -> f14(A,B)    [B >= 0 && A >= 0 && A >= B]                   (?,1)
          6. f4(A,B) -> f14(A,B)    [B >= 0 && 0 >= 1 + C && A >= 0 && B >= 1 + A] (?,1)
        Signature:
          {(f0,2);(f14,2);(f4,2)}
        Flow Graph:
          [0->{1,2,4,5},1->{1,2,3,4,5,6},2->{1,2,3,4,5,6},3->{},4->{},5->{},6->{}]
        
    + Applied Processor:
        TrivialSCCs
    + Details:
        All trivial SCCs of the transition graph admit timebound 1.
* Step 3: Failure MAYBE
  + Considered Problem:
      Rules:
        0. f0(A,B) -> f4(C,0)     True                                           (1,1)
        1. f4(A,B) -> f4(A,1 + B) [B >= 0 && 0 >= 1 + C]                         (?,1)
        2. f4(A,B) -> f4(A,1 + B) [B >= 0]                                       (?,1)
        3. f4(A,B) -> f14(A,B)    [B >= 0 && A >= 0 && B >= 1 + A]               (1,1)
        4. f4(A,B) -> f14(A,B)    [B >= 0 && 0 >= 1 + A]                         (1,1)
        5. f4(A,B) -> f14(A,B)    [B >= 0 && A >= 0 && A >= B]                   (1,1)
        6. f4(A,B) -> f14(A,B)    [B >= 0 && 0 >= 1 + C && A >= 0 && B >= 1 + A] (1,1)
      Signature:
        {(f0,2);(f14,2);(f4,2)}
      Flow Graph:
        [0->{1,2,4,5},1->{1,2,3,4,5,6},2->{1,2,3,4,5,6},3->{},4->{},5->{},6->{}]
      
  + Applied Processor:
      Failing "Open problems left."
  + Details:
      Open problems left.
MAYBE