MAYBE
* Step 1: Failure MAYBE
  + Considered Problem:
      Rules:
        0. f1(A,B,C) -> f1(E,F,B) [A >= 1 && D >= 1 && B = 0] (?,1)
        1. f0(A,B,C) -> f1(A,B,C) True                        (1,1)
      Signature:
        {(f0,3);(f1,3)}
      Flow Graph:
        [0->{0},1->{0}]
      
  + Applied Processor:
      Failing "Open problems left."
  + Details:
      Open problems left.
MAYBE