YES(?,O(n^1))
* Step 1: PolyRank WORST_CASE(?,O(n^1))
    + Considered Problem:
        Rules:
          0. start(A,B,C) -> eval(A,B,C)     True               (1,1)
          1. eval(A,B,C)  -> eval(A,B + C,C) [A >= B && C >= 1] (?,1)
        Signature:
          {(eval,3);(start,3)}
        Flow Graph:
          [0->{1},1->{1}]
        
    + Applied Processor:
        PolyRank {useFarkas = True, withSizebounds = [], shape = Linear}
    + Details:
        We apply a polynomial interpretation of shape linear:
           p(eval) = 1 + x1 + -1*x2
          p(start) = 1 + x1 + -1*x2
        
        Following rules are strictly oriented:
        [A >= B && C >= 1] ==>                    
               eval(A,B,C)   = 1 + A + -1*B       
                             > 1 + A + -1*B + -1*C
                             = eval(A,B + C,C)    
        
        
        Following rules are weakly oriented:
                  True ==>             
          start(A,B,C)   = 1 + A + -1*B
                        >= 1 + A + -1*B
                         = eval(A,B,C) 
        
        
* Step 2: KnowledgePropagation WORST_CASE(?,O(n^1))
    + Considered Problem:
        Rules:
          0. start(A,B,C) -> eval(A,B,C)     True               (1,1)        
          1. eval(A,B,C)  -> eval(A,B + C,C) [A >= B && C >= 1] (1 + A + B,1)
        Signature:
          {(eval,3);(start,3)}
        Flow Graph:
          [0->{1},1->{1}]
        
    + Applied Processor:
        KnowledgePropagation
    + Details:
        The problem is already solved.

YES(?,O(n^1))