YES(?,O(1)) * Step 1: UnsatRules WORST_CASE(?,O(1)) + Considered Problem: Rules: 0. f0(A,B,C,D,E,F,G) -> f5(0,B,C,D,E,F,G) True (1,1) 1. f5(A,B,C,D,E,F,G) -> f5(1 + A,B,C,D,E,F,G) [99 >= A] (?,1) 2. f17(A,B,C,D,E,F,G) -> f17(A,B,C,D,E,F,G) True (?,1) 3. f17(A,B,C,D,E,F,G) -> f17(A,1 + B,C,D,E,F,G) [0 >= 1 + H] (?,1) 4. f17(A,B,C,D,E,F,G) -> f17(A,1 + B,C,D,E,F,G) True (?,1) 5. f32(A,B,C,D,E,F,G) -> f32(A,B,C,D,E,F,G) True (?,1) 6. f32(A,B,C,D,E,F,G) -> f32(A,B,1 + C,D,E,F,G) [0 >= 1 + H] (?,1) 7. f32(A,B,C,D,E,F,G) -> f32(A,B,1 + C,D,E,F,G) True (?,1) 8. f32(A,B,C,D,E,F,G) -> f13(A,B,C,C,C,F,G) True (?,1) 9. f17(A,B,C,D,E,F,G) -> f32(A,B,B,B,E,B,H) [0 >= 1 + I] (?,1) 10. f17(A,B,C,D,E,F,G) -> f32(A,B,B,B,E,B,H) True (?,1) 11. f17(A,B,C,D,E,F,G) -> f13(A,B,C,B,E,B,H) True (?,1) 12. f5(A,B,C,D,E,F,G) -> f13(A,B,C,-2 + A,E,F,G) [A >= 100] (?,1) 13. f5(A,B,C,D,E,F,G) -> f17(A,-2 + A,C,-2 + A,E,F,G) [0 >= 1 + A && A >= 100] (?,1) Signature: {(f0,7);(f13,7);(f17,7);(f32,7);(f5,7)} Flow Graph: [0->{1,12,13},1->{1,12,13},2->{2,3,4,9,10,11},3->{2,3,4,9,10,11},4->{2,3,4,9,10,11},5->{5,6,7,8},6->{5,6,7 ,8},7->{5,6,7,8},8->{},9->{5,6,7,8},10->{5,6,7,8},11->{},12->{},13->{2,3,4,9,10,11}] + Applied Processor: UnsatRules + Details: Following transitions have unsatisfiable constraints and are removed: [13] * Step 2: UnreachableRules WORST_CASE(?,O(1)) + Considered Problem: Rules: 0. f0(A,B,C,D,E,F,G) -> f5(0,B,C,D,E,F,G) True (1,1) 1. f5(A,B,C,D,E,F,G) -> f5(1 + A,B,C,D,E,F,G) [99 >= A] (?,1) 2. f17(A,B,C,D,E,F,G) -> f17(A,B,C,D,E,F,G) True (?,1) 3. f17(A,B,C,D,E,F,G) -> f17(A,1 + B,C,D,E,F,G) [0 >= 1 + H] (?,1) 4. f17(A,B,C,D,E,F,G) -> f17(A,1 + B,C,D,E,F,G) True (?,1) 5. f32(A,B,C,D,E,F,G) -> f32(A,B,C,D,E,F,G) True (?,1) 6. f32(A,B,C,D,E,F,G) -> f32(A,B,1 + C,D,E,F,G) [0 >= 1 + H] (?,1) 7. f32(A,B,C,D,E,F,G) -> f32(A,B,1 + C,D,E,F,G) True (?,1) 8. f32(A,B,C,D,E,F,G) -> f13(A,B,C,C,C,F,G) True (?,1) 9. f17(A,B,C,D,E,F,G) -> f32(A,B,B,B,E,B,H) [0 >= 1 + I] (?,1) 10. f17(A,B,C,D,E,F,G) -> f32(A,B,B,B,E,B,H) True (?,1) 11. f17(A,B,C,D,E,F,G) -> f13(A,B,C,B,E,B,H) True (?,1) 12. f5(A,B,C,D,E,F,G) -> f13(A,B,C,-2 + A,E,F,G) [A >= 100] (?,1) Signature: {(f0,7);(f13,7);(f17,7);(f32,7);(f5,7)} Flow Graph: [0->{1,12},1->{1,12},2->{2,3,4,9,10,11},3->{2,3,4,9,10,11},4->{2,3,4,9,10,11},5->{5,6,7,8},6->{5,6,7,8} ,7->{5,6,7,8},8->{},9->{5,6,7,8},10->{5,6,7,8},11->{},12->{}] + Applied Processor: UnreachableRules + Details: Following transitions are not reachable from the starting states and are revomed: [2,3,4,5,6,7,8,9,10,11] * Step 3: UnsatPaths WORST_CASE(?,O(1)) + Considered Problem: Rules: 0. f0(A,B,C,D,E,F,G) -> f5(0,B,C,D,E,F,G) True (1,1) 1. f5(A,B,C,D,E,F,G) -> f5(1 + A,B,C,D,E,F,G) [99 >= A] (?,1) 12. f5(A,B,C,D,E,F,G) -> f13(A,B,C,-2 + A,E,F,G) [A >= 100] (?,1) Signature: {(f0,7);(f13,7);(f17,7);(f32,7);(f5,7)} Flow Graph: [0->{1,12},1->{1,12},12->{}] + Applied Processor: UnsatPaths + Details: We remove following edges from the transition graph: [(0,12)] * Step 4: TrivialSCCs WORST_CASE(?,O(1)) + Considered Problem: Rules: 0. f0(A,B,C,D,E,F,G) -> f5(0,B,C,D,E,F,G) True (1,1) 1. f5(A,B,C,D,E,F,G) -> f5(1 + A,B,C,D,E,F,G) [99 >= A] (?,1) 12. f5(A,B,C,D,E,F,G) -> f13(A,B,C,-2 + A,E,F,G) [A >= 100] (?,1) Signature: {(f0,7);(f13,7);(f17,7);(f32,7);(f5,7)} Flow Graph: [0->{1},1->{1,12},12->{}] + Applied Processor: TrivialSCCs + Details: All trivial SCCs of the transition graph admit timebound 1. * Step 5: PolyRank WORST_CASE(?,O(1)) + Considered Problem: Rules: 0. f0(A,B,C,D,E,F,G) -> f5(0,B,C,D,E,F,G) True (1,1) 1. f5(A,B,C,D,E,F,G) -> f5(1 + A,B,C,D,E,F,G) [99 >= A] (?,1) 12. f5(A,B,C,D,E,F,G) -> f13(A,B,C,-2 + A,E,F,G) [A >= 100] (1,1) Signature: {(f0,7);(f13,7);(f17,7);(f32,7);(f5,7)} Flow Graph: [0->{1},1->{1,12},12->{}] + Applied Processor: PolyRank {useFarkas = True, withSizebounds = [], shape = Linear} + Details: We apply a polynomial interpretation of shape linear: p(f0) = 100 p(f13) = 100 + -1*x1 p(f5) = 100 + -1*x1 Following rules are strictly oriented: [99 >= A] ==> f5(A,B,C,D,E,F,G) = 100 + -1*A > 99 + -1*A = f5(1 + A,B,C,D,E,F,G) Following rules are weakly oriented: True ==> f0(A,B,C,D,E,F,G) = 100 >= 100 = f5(0,B,C,D,E,F,G) [A >= 100] ==> f5(A,B,C,D,E,F,G) = 100 + -1*A >= 100 + -1*A = f13(A,B,C,-2 + A,E,F,G) * Step 6: KnowledgePropagation WORST_CASE(?,O(1)) + Considered Problem: Rules: 0. f0(A,B,C,D,E,F,G) -> f5(0,B,C,D,E,F,G) True (1,1) 1. f5(A,B,C,D,E,F,G) -> f5(1 + A,B,C,D,E,F,G) [99 >= A] (100,1) 12. f5(A,B,C,D,E,F,G) -> f13(A,B,C,-2 + A,E,F,G) [A >= 100] (1,1) Signature: {(f0,7);(f13,7);(f17,7);(f32,7);(f5,7)} Flow Graph: [0->{1},1->{1,12},12->{}] + Applied Processor: KnowledgePropagation + Details: The problem is already solved. YES(?,O(1))