YES(?,O(1))
* Step 1: UnsatPaths WORST_CASE(?,O(1))
    + Considered Problem:
        Rules:
          0. f0(A) -> f5(0)     True                             (1,1)
          1. f5(A) -> f5(1 + A) [A >= 0 && 1 >= A]               (?,1)
          2. f5(A) -> f13(A)    [A >= 0 && A >= 2 && 0 >= 1 + B] (?,1)
          3. f5(A) -> f13(A)    [A >= 0 && A >= 2]               (?,1)
        Signature:
          {(f0,1);(f13,1);(f5,1)}
        Flow Graph:
          [0->{1,2,3},1->{1,2,3},2->{},3->{}]
        
    + Applied Processor:
        UnsatPaths
    + Details:
        We remove following edges from the transition graph: [(0,2),(0,3)]
* Step 2: FromIts WORST_CASE(?,O(1))
    + Considered Problem:
        Rules:
          0. f0(A) -> f5(0)     True                             (1,1)
          1. f5(A) -> f5(1 + A) [A >= 0 && 1 >= A]               (?,1)
          2. f5(A) -> f13(A)    [A >= 0 && A >= 2 && 0 >= 1 + B] (?,1)
          3. f5(A) -> f13(A)    [A >= 0 && A >= 2]               (?,1)
        Signature:
          {(f0,1);(f13,1);(f5,1)}
        Flow Graph:
          [0->{1},1->{1,2,3},2->{},3->{}]
        
    + Applied Processor:
        FromIts
    + Details:
        ()
* Step 3: AddSinks WORST_CASE(?,O(1))
    + Considered Problem:
        Rules:
          f0(A) -> f5(0)      True
          f5(A) -> f5(1 + A)  [A >= 0 && 1 >= A]
          f5(A) -> f13(A)     [A >= 0 && A >= 2 && 0 >= 1 + B]
          f5(A) -> f13(A)     [A >= 0 && A >= 2]
        Signature:
          {(f0,1);(f13,1);(f5,1)}
        Rule Graph:
          [0->{1},1->{1,2,3},2->{},3->{}]
    + Applied Processor:
        AddSinks
    + Details:
        ()
* Step 4: Decompose WORST_CASE(?,O(1))
    + Considered Problem:
        Rules:
          f0(A)  -> f5(0)         True
          f5(A)  -> f5(1 + A)     [A >= 0 && 1 >= A]
          f5(A)  -> f13(A)        [A >= 0 && A >= 2 && 0 >= 1 + B]
          f5(A)  -> f13(A)        [A >= 0 && A >= 2]
          f13(A) -> exitus616(A)  True
          f13(A) -> exitus616(A)  True
        Signature:
          {(exitus616,1);(f0,1);(f13,1);(f5,1)}
        Rule Graph:
          [0->{1},1->{1,2,3},2->{5},3->{4}]
    + Applied Processor:
        Decompose Greedy
    + Details:
        We construct a looptree:
          P: [0,1,2,3,4,5]
          |
          `- p:[1] c: [1]
* Step 5: AbstractSize WORST_CASE(?,O(1))
    + Considered Problem:
        (Rules:
          f0(A)  -> f5(0)         True
          f5(A)  -> f5(1 + A)     [A >= 0 && 1 >= A]
          f5(A)  -> f13(A)        [A >= 0 && A >= 2 && 0 >= 1 + B]
          f5(A)  -> f13(A)        [A >= 0 && A >= 2]
          f13(A) -> exitus616(A)  True
          f13(A) -> exitus616(A)  True
        Signature:
          {(exitus616,1);(f0,1);(f13,1);(f5,1)}
        Rule Graph:
          [0->{1},1->{1,2,3},2->{5},3->{4}]
        ,We construct a looptree:
          P: [0,1,2,3,4,5]
          |
          `- p:[1] c: [1])
    + Applied Processor:
        AbstractSize Minimize
    + Details:
        ()
* Step 6: AbstractFlow WORST_CASE(?,O(1))
    + Considered Problem:
        Program:
          Domain: [A,0.0]
           f0   ~>  f5          [A <= 0*K]
           f5   ~>  f5          [A <= 2*K]
           f5   ~>  f13         [A <= A]
           f5   ~>  f13         [A <= A]
           f13  ~>  exitus616   [A <= A]
           f13  ~>  exitus616   [A <= A]
          + Loop: [0.0 <= K + A]
               f5  ~>  f5   [A <= 2*K]
    + Applied Processor:
        AbstractFlow
    + Details:
        ()
* Step 7: Lare WORST_CASE(?,O(1))
    + Considered Problem:
        Program:
          Domain: [tick,huge,K,A,0.0]
           f0   ~>  f5          [K ~=> A]
           f5   ~>  f5          [K ~=> A]
           f5   ~>  f13         []
           f5   ~>  f13         []
           f13  ~>  exitus616   []
           f13  ~>  exitus616   []
          + Loop: [A ~+> 0.0,K ~+> 0.0]
               f5  ~>  f5   [K ~=> A]
    + Applied Processor:
        Lare
    + Details:
         f0  ~>  exitus616   [K ~=> A,tick ~+> tick,K ~+> 0.0,K ~+> tick,K ~*> 0.0,K ~*> tick]
        + <f5  ~>  f5>  [K ~=> A,A ~+> 0.0,A ~+> tick,tick ~+> tick,K ~+> 0.0,K ~+> tick]

YES(?,O(1))