MAYBE
* Step 1: FromIts MAYBE
    + Considered Problem:
        Rules:
          0. f3(A,B) -> f0(1,1)     True                                                                              (1,1)
          1. f0(A,B) -> f0(1 + A,B) [1 + -1*B >= 0 && A + -1*B >= 0 && -1 + B >= 0 && -2 + A + B >= 0 && -1 + A >= 0] (?,1)
        Signature:
          {(f0,2);(f3,2)}
        Flow Graph:
          [0->{1},1->{1}]
        
    + Applied Processor:
        FromIts
    + Details:
        ()
* Step 2: AddSinks MAYBE
    + Considered Problem:
        Rules:
          f3(A,B) -> f0(1,1)      True
          f0(A,B) -> f0(1 + A,B)  [1 + -1*B >= 0 && A + -1*B >= 0 && -1 + B >= 0 && -2 + A + B >= 0 && -1 + A >= 0]
        Signature:
          {(f0,2);(f3,2)}
        Rule Graph:
          [0->{1},1->{1}]
    + Applied Processor:
        AddSinks
    + Details:
        ()
* Step 3: Failure MAYBE
  + Considered Problem:
      Rules:
        f3(A,B) -> f0(1,1)         True
        f0(A,B) -> f0(1 + A,B)     [1 + -1*B >= 0 && A + -1*B >= 0 && -1 + B >= 0 && -2 + A + B >= 0 && -1 + A >= 0]
        f0(A,B) -> exitus616(A,B)  True
      Signature:
        {(exitus616,2);(f0,2);(f3,2)}
      Rule Graph:
        [0->{1},1->{1,2}]
  + Applied Processor:
      Decompose Greedy
  + Details:
      We construct a looptree:
        P: [0,1,2]
        |
        `- p:[1] c: []
MAYBE