YES(?,O(n^1)) * Step 1: FromIts WORST_CASE(?,O(n^1)) + Considered Problem: Rules: 0. sqrt(A,B,C,D) -> f(0,1,1,D) True (1,1) 1. f(A,B,C,D) -> f(1 + A,2 + B,2 + B + C,D) [-1 + C >= 0 (?,1) && -2 + B + C >= 0 && -1*B + C >= 0 && -1 + A + C >= 0 && -1 + -1*A + C >= 0 && -1 + B >= 0 && -1 + A + B >= 0 && -1 + -1*A + B >= 0 && A >= 0 && D >= C && B >= 0] 2. f(A,B,C,D) -> end(A,B,C,D) [-1 + C >= 0 (?,1) && -2 + B + C >= 0 && -1*B + C >= 0 && -1 + A + C >= 0 && -1 + -1*A + C >= 0 && -1 + B >= 0 && -1 + A + B >= 0 && -1 + -1*A + B >= 0 && A >= 0 && C >= 1 + D] Signature: {(end,4);(f,4);(sqrt,4)} Flow Graph: [0->{1,2},1->{1,2},2->{}] + Applied Processor: FromIts + Details: () * Step 2: AddSinks WORST_CASE(?,O(n^1)) + Considered Problem: Rules: sqrt(A,B,C,D) -> f(0,1,1,D) True f(A,B,C,D) -> f(1 + A,2 + B,2 + B + C,D) [-1 + C >= 0 && -2 + B + C >= 0 && -1*B + C >= 0 && -1 + A + C >= 0 && -1 + -1*A + C >= 0 && -1 + B >= 0 && -1 + A + B >= 0 && -1 + -1*A + B >= 0 && A >= 0 && D >= C && B >= 0] f(A,B,C,D) -> end(A,B,C,D) [-1 + C >= 0 && -2 + B + C >= 0 && -1*B + C >= 0 && -1 + A + C >= 0 && -1 + -1*A + C >= 0 && -1 + B >= 0 && -1 + A + B >= 0 && -1 + -1*A + B >= 0 && A >= 0 && C >= 1 + D] Signature: {(end,4);(f,4);(sqrt,4)} Rule Graph: [0->{1,2},1->{1,2},2->{}] + Applied Processor: AddSinks + Details: () * Step 3: Decompose WORST_CASE(?,O(n^1)) + Considered Problem: Rules: sqrt(A,B,C,D) -> f(0,1,1,D) True f(A,B,C,D) -> f(1 + A,2 + B,2 + B + C,D) [-1 + C >= 0 && -2 + B + C >= 0 && -1*B + C >= 0 && -1 + A + C >= 0 && -1 + -1*A + C >= 0 && -1 + B >= 0 && -1 + A + B >= 0 && -1 + -1*A + B >= 0 && A >= 0 && D >= C && B >= 0] f(A,B,C,D) -> end(A,B,C,D) [-1 + C >= 0 && -2 + B + C >= 0 && -1*B + C >= 0 && -1 + A + C >= 0 && -1 + -1*A + C >= 0 && -1 + B >= 0 && -1 + A + B >= 0 && -1 + -1*A + B >= 0 && A >= 0 && C >= 1 + D] end(A,B,C,D) -> exitus616(A,B,C,D) True Signature: {(end,4);(exitus616,4);(f,4);(sqrt,4)} Rule Graph: [0->{1,2},1->{1,2},2->{3}] + Applied Processor: Decompose Greedy + Details: We construct a looptree: P: [0,1,2,3] | `- p:[1] c: [1] * Step 4: AbstractSize WORST_CASE(?,O(n^1)) + Considered Problem: (Rules: sqrt(A,B,C,D) -> f(0,1,1,D) True f(A,B,C,D) -> f(1 + A,2 + B,2 + B + C,D) [-1 + C >= 0 && -2 + B + C >= 0 && -1*B + C >= 0 && -1 + A + C >= 0 && -1 + -1*A + C >= 0 && -1 + B >= 0 && -1 + A + B >= 0 && -1 + -1*A + B >= 0 && A >= 0 && D >= C && B >= 0] f(A,B,C,D) -> end(A,B,C,D) [-1 + C >= 0 && -2 + B + C >= 0 && -1*B + C >= 0 && -1 + A + C >= 0 && -1 + -1*A + C >= 0 && -1 + B >= 0 && -1 + A + B >= 0 && -1 + -1*A + B >= 0 && A >= 0 && C >= 1 + D] end(A,B,C,D) -> exitus616(A,B,C,D) True Signature: {(end,4);(exitus616,4);(f,4);(sqrt,4)} Rule Graph: [0->{1,2},1->{1,2},2->{3}] ,We construct a looptree: P: [0,1,2,3] | `- p:[1] c: [1]) + Applied Processor: AbstractSize Minimize + Details: () * Step 5: AbstractFlow WORST_CASE(?,O(n^1)) + Considered Problem: Program: Domain: [A,B,C,D,0.0] sqrt ~> f [A <= 0*K, B <= K, C <= K, D <= D] f ~> f [A <= D, B <= B + C + D, C <= 2*K + B + C, D <= D] f ~> end [A <= A, B <= B, C <= C, D <= D] end ~> exitus616 [A <= A, B <= B, C <= C, D <= D] + Loop: [0.0 <= K + A + B + C + D] f ~> f [A <= D, B <= B + C + D, C <= 2*K + B + C, D <= D] + Applied Processor: AbstractFlow + Details: () * Step 6: Lare WORST_CASE(?,O(n^1)) + Considered Problem: Program: Domain: [tick,huge,K,A,B,C,D,0.0] sqrt ~> f [K ~=> A,K ~=> B,K ~=> C] f ~> f [D ~=> A,B ~+> B,B ~+> C,C ~+> B,C ~+> C,D ~+> B,K ~*> C] f ~> end [] end ~> exitus616 [] + Loop: [A ~+> 0.0,B ~+> 0.0,C ~+> 0.0,D ~+> 0.0,K ~+> 0.0] f ~> f [D ~=> A,B ~+> B,B ~+> C,C ~+> B,C ~+> C,D ~+> B,K ~*> C] + Applied Processor: Lare + Details: sqrt ~> exitus616 [D ~=> A ,K ~=> A ,K ~=> B ,K ~=> C ,D ~+> B ,D ~+> C ,D ~+> 0.0 ,D ~+> tick ,tick ~+> tick ,K ~+> B ,K ~+> C ,K ~+> 0.0 ,K ~+> tick ,D ~*> B ,D ~*> C ,K ~*> B ,K ~*> C ,K ~*> 0.0 ,K ~*> tick ,D ~^> B ,D ~^> C ,K ~^> B ,K ~^> C] + f> [D ~=> A ,A ~+> 0.0 ,A ~+> tick ,B ~+> B ,B ~+> C ,B ~+> 0.0 ,B ~+> tick ,C ~+> B ,C ~+> C ,C ~+> 0.0 ,C ~+> tick ,D ~+> B ,D ~+> C ,D ~+> 0.0 ,D ~+> tick ,tick ~+> tick ,K ~+> 0.0 ,K ~+> tick ,A ~*> B ,A ~*> C ,B ~*> B ,B ~*> C ,C ~*> B ,C ~*> C ,D ~*> B ,D ~*> C ,K ~*> B ,K ~*> C ,A ~^> B ,A ~^> C ,B ~^> B ,B ~^> C ,C ~^> B ,C ~^> C ,D ~^> B ,D ~^> C ,K ~^> B ,K ~^> C] YES(?,O(n^1))