YES
* Step 1: UnsatPaths YES
    + Considered Problem:
        Rules:
          0. evalfstart(A,B,C)    -> evalfentryin(A,B,C)   True         (1,1)
          1. evalfentryin(A,B,C)  -> evalfbb4in(1,B,C)     True         (?,1)
          2. evalfbb4in(A,B,C)    -> evalfbb2in(A,B,A)     [B >= A]     (?,1)
          3. evalfbb4in(A,B,C)    -> evalfreturnin(A,B,C)  [A >= 1 + B] (?,1)
          4. evalfbb2in(A,B,C)    -> evalfbb1in(A,B,C)     [B >= C]     (?,1)
          5. evalfbb2in(A,B,C)    -> evalfbb3in(A,B,C)     [C >= 1 + B] (?,1)
          6. evalfbb1in(A,B,C)    -> evalfbb2in(A,B,1 + C) True         (?,1)
          7. evalfbb3in(A,B,C)    -> evalfbb4in(1 + A,B,C) True         (?,1)
          8. evalfreturnin(A,B,C) -> evalfstop(A,B,C)      True         (?,1)
        Signature:
          {(evalfbb1in,3)
          ;(evalfbb2in,3)
          ;(evalfbb3in,3)
          ;(evalfbb4in,3)
          ;(evalfentryin,3)
          ;(evalfreturnin,3)
          ;(evalfstart,3)
          ;(evalfstop,3)}
        Flow Graph:
          [0->{1},1->{2,3},2->{4,5},3->{8},4->{6},5->{7},6->{4,5},7->{2,3},8->{}]
        
    + Applied Processor:
        UnsatPaths
    + Details:
        We remove following edges from the transition graph: [(2,5)]
* Step 2: FromIts YES
    + Considered Problem:
        Rules:
          0. evalfstart(A,B,C)    -> evalfentryin(A,B,C)   True         (1,1)
          1. evalfentryin(A,B,C)  -> evalfbb4in(1,B,C)     True         (?,1)
          2. evalfbb4in(A,B,C)    -> evalfbb2in(A,B,A)     [B >= A]     (?,1)
          3. evalfbb4in(A,B,C)    -> evalfreturnin(A,B,C)  [A >= 1 + B] (?,1)
          4. evalfbb2in(A,B,C)    -> evalfbb1in(A,B,C)     [B >= C]     (?,1)
          5. evalfbb2in(A,B,C)    -> evalfbb3in(A,B,C)     [C >= 1 + B] (?,1)
          6. evalfbb1in(A,B,C)    -> evalfbb2in(A,B,1 + C) True         (?,1)
          7. evalfbb3in(A,B,C)    -> evalfbb4in(1 + A,B,C) True         (?,1)
          8. evalfreturnin(A,B,C) -> evalfstop(A,B,C)      True         (?,1)
        Signature:
          {(evalfbb1in,3)
          ;(evalfbb2in,3)
          ;(evalfbb3in,3)
          ;(evalfbb4in,3)
          ;(evalfentryin,3)
          ;(evalfreturnin,3)
          ;(evalfstart,3)
          ;(evalfstop,3)}
        Flow Graph:
          [0->{1},1->{2,3},2->{4},3->{8},4->{6},5->{7},6->{4,5},7->{2,3},8->{}]
        
    + Applied Processor:
        FromIts
    + Details:
        ()
* Step 3: Decompose YES
    + Considered Problem:
        Rules:
          evalfstart(A,B,C)    -> evalfentryin(A,B,C)    True
          evalfentryin(A,B,C)  -> evalfbb4in(1,B,C)      True
          evalfbb4in(A,B,C)    -> evalfbb2in(A,B,A)      [B >= A]
          evalfbb4in(A,B,C)    -> evalfreturnin(A,B,C)   [A >= 1 + B]
          evalfbb2in(A,B,C)    -> evalfbb1in(A,B,C)      [B >= C]
          evalfbb2in(A,B,C)    -> evalfbb3in(A,B,C)      [C >= 1 + B]
          evalfbb1in(A,B,C)    -> evalfbb2in(A,B,1 + C)  True
          evalfbb3in(A,B,C)    -> evalfbb4in(1 + A,B,C)  True
          evalfreturnin(A,B,C) -> evalfstop(A,B,C)       True
        Signature:
          {(evalfbb1in,3)
          ;(evalfbb2in,3)
          ;(evalfbb3in,3)
          ;(evalfbb4in,3)
          ;(evalfentryin,3)
          ;(evalfreturnin,3)
          ;(evalfstart,3)
          ;(evalfstop,3)}
        Rule Graph:
          [0->{1},1->{2,3},2->{4},3->{8},4->{6},5->{7},6->{4,5},7->{2,3},8->{}]
    + Applied Processor:
        Decompose NoGreedy
    + Details:
        We construct a looptree:
          P: [0,1,2,3,4,5,6,7,8]
          |
          `- p:[2,7,5,6,4] c: [2,5,7]
             |
             `- p:[4,6] c: [4,6]
* Step 4: CloseWith YES
    + Considered Problem:
        (Rules:
          evalfstart(A,B,C)    -> evalfentryin(A,B,C)    True
          evalfentryin(A,B,C)  -> evalfbb4in(1,B,C)      True
          evalfbb4in(A,B,C)    -> evalfbb2in(A,B,A)      [B >= A]
          evalfbb4in(A,B,C)    -> evalfreturnin(A,B,C)   [A >= 1 + B]
          evalfbb2in(A,B,C)    -> evalfbb1in(A,B,C)      [B >= C]
          evalfbb2in(A,B,C)    -> evalfbb3in(A,B,C)      [C >= 1 + B]
          evalfbb1in(A,B,C)    -> evalfbb2in(A,B,1 + C)  True
          evalfbb3in(A,B,C)    -> evalfbb4in(1 + A,B,C)  True
          evalfreturnin(A,B,C) -> evalfstop(A,B,C)       True
        Signature:
          {(evalfbb1in,3)
          ;(evalfbb2in,3)
          ;(evalfbb3in,3)
          ;(evalfbb4in,3)
          ;(evalfentryin,3)
          ;(evalfreturnin,3)
          ;(evalfstart,3)
          ;(evalfstop,3)}
        Rule Graph:
          [0->{1},1->{2,3},2->{4},3->{8},4->{6},5->{7},6->{4,5},7->{2,3},8->{}]
        ,We construct a looptree:
          P: [0,1,2,3,4,5,6,7,8]
          |
          `- p:[2,7,5,6,4] c: [2,5,7]
             |
             `- p:[4,6] c: [4,6])
    + Applied Processor:
        CloseWith True
    + Details:
        ()

YES