YES
* Step 1: UnsatPaths YES
    + Considered Problem:
        Rules:
          0. f2(A,B,C) -> f2(1 + A,1 + B,C) [1 >= A]           (?,1)
          1. f2(A,B,C) -> f2(1 + A,1 + B,C) [2 >= B && A >= 2] (?,1)
          2. f2(A,B,C) -> f300(A,B,D)       [B >= 3 && A >= 2] (?,1)
          3. f1(A,B,C) -> f2(A,B,C)         True               (1,1)
        Signature:
          {(f1,3);(f2,3);(f300,3)}
        Flow Graph:
          [0->{0,1,2},1->{0,1,2},2->{},3->{0,1,2}]
        
    + Applied Processor:
        UnsatPaths
    + Details:
        We remove following edges from the transition graph: [(1,0)]
* Step 2: FromIts YES
    + Considered Problem:
        Rules:
          0. f2(A,B,C) -> f2(1 + A,1 + B,C) [1 >= A]           (?,1)
          1. f2(A,B,C) -> f2(1 + A,1 + B,C) [2 >= B && A >= 2] (?,1)
          2. f2(A,B,C) -> f300(A,B,D)       [B >= 3 && A >= 2] (?,1)
          3. f1(A,B,C) -> f2(A,B,C)         True               (1,1)
        Signature:
          {(f1,3);(f2,3);(f300,3)}
        Flow Graph:
          [0->{0,1,2},1->{1,2},2->{},3->{0,1,2}]
        
    + Applied Processor:
        FromIts
    + Details:
        ()
* Step 3: Decompose YES
    + Considered Problem:
        Rules:
          f2(A,B,C) -> f2(1 + A,1 + B,C)  [1 >= A]
          f2(A,B,C) -> f2(1 + A,1 + B,C)  [2 >= B && A >= 2]
          f2(A,B,C) -> f300(A,B,D)        [B >= 3 && A >= 2]
          f1(A,B,C) -> f2(A,B,C)          True
        Signature:
          {(f1,3);(f2,3);(f300,3)}
        Rule Graph:
          [0->{0,1,2},1->{1,2},2->{},3->{0,1,2}]
    + Applied Processor:
        Decompose NoGreedy
    + Details:
        We construct a looptree:
          P: [0,1,2,3]
          |
          +- p:[0] c: [0]
          |
          `- p:[1] c: [1]
* Step 4: CloseWith YES
    + Considered Problem:
        (Rules:
          f2(A,B,C) -> f2(1 + A,1 + B,C)  [1 >= A]
          f2(A,B,C) -> f2(1 + A,1 + B,C)  [2 >= B && A >= 2]
          f2(A,B,C) -> f300(A,B,D)        [B >= 3 && A >= 2]
          f1(A,B,C) -> f2(A,B,C)          True
        Signature:
          {(f1,3);(f2,3);(f300,3)}
        Rule Graph:
          [0->{0,1,2},1->{1,2},2->{},3->{0,1,2}]
        ,We construct a looptree:
          P: [0,1,2,3]
          |
          +- p:[0] c: [0]
          |
          `- p:[1] c: [1])
    + Applied Processor:
        CloseWith True
    + Details:
        ()

YES