NO
* Step 1: FromIts NO
    + Considered Problem:
        Rules:
          0. f0(A,B,C,D,E,F,G) -> f2(H,B,I,D,E,F,G) [A >= B]                   (?,1)
          1. f0(A,B,C,D,E,F,G) -> f0(H,B,C,I,0,F,G) [B >= 1 + A]               (?,1)
          2. f0(A,B,C,D,E,F,G) -> f0(H,B,C,I,J,K,G) [0 >= 1 + J && B >= 1 + A] (?,1)
          3. f0(A,B,C,D,E,F,G) -> f0(H,B,C,I,J,K,G) [J >= 1 && B >= 1 + A]     (?,1)
          4. f1(A,B,C,D,E,F,G) -> f0(A,B,C,D,E,F,H) True                       (1,1)
        Signature:
          {(f0,7);(f1,7);(f2,7)}
        Flow Graph:
          [0->{},1->{0,1,2,3},2->{0,1,2,3},3->{0,1,2,3},4->{0,1,2,3}]
        
    + Applied Processor:
        FromIts
    + Details:
        ()
* Step 2: CloseWith NO
    + Considered Problem:
        Rules:
          f0(A,B,C,D,E,F,G) -> f2(H,B,I,D,E,F,G)  [A >= B]
          f0(A,B,C,D,E,F,G) -> f0(H,B,C,I,0,F,G)  [B >= 1 + A]
          f0(A,B,C,D,E,F,G) -> f0(H,B,C,I,J,K,G)  [0 >= 1 + J && B >= 1 + A]
          f0(A,B,C,D,E,F,G) -> f0(H,B,C,I,J,K,G)  [J >= 1 && B >= 1 + A]
          f1(A,B,C,D,E,F,G) -> f0(A,B,C,D,E,F,H)  True
        Signature:
          {(f0,7);(f1,7);(f2,7)}
        Rule Graph:
          [0->{},1->{0,1,2,3},2->{0,1,2,3},3->{0,1,2,3},4->{0,1,2,3}]
    + Applied Processor:
        CloseWith False
    + Details:
        ()

NO