YES * Step 1: UnsatPaths YES + Considered Problem: Rules: 0. f0(A,B,C) -> f10(1,B,C) True (1,1) 1. f10(A,B,C) -> f13(A,1,C) [5 >= A] (?,1) 2. f13(A,B,C) -> f13(A,1 + B,C) [5 >= B] (?,1) 3. f21(A,B,C) -> f24(A,1,C) [5 >= A] (?,1) 4. f24(A,B,C) -> f27(A,B,1) [5 >= B] (?,1) 5. f27(A,B,C) -> f27(A,B,1 + C) [5 >= C] (?,1) 6. f27(A,B,C) -> f24(A,1 + B,C) [C >= 6] (?,1) 7. f24(A,B,C) -> f21(1 + A,B,C) [B >= 6] (?,1) 8. f21(A,B,C) -> f39(A,B,C) [A >= 6] (?,1) 9. f13(A,B,C) -> f10(1 + A,B,C) [B >= 6] (?,1) 10. f10(A,B,C) -> f21(1,B,C) [A >= 6] (?,1) Signature: {(f0,3);(f10,3);(f13,3);(f21,3);(f24,3);(f27,3);(f39,3)} Flow Graph: [0->{1,10},1->{2,9},2->{2,9},3->{4,7},4->{5,6},5->{5,6},6->{4,7},7->{3,8},8->{},9->{1,10},10->{3,8}] + Applied Processor: UnsatPaths + Details: We remove following edges from the transition graph: [(0,10),(1,9),(3,7),(4,6),(10,8)] * Step 2: FromIts YES + Considered Problem: Rules: 0. f0(A,B,C) -> f10(1,B,C) True (1,1) 1. f10(A,B,C) -> f13(A,1,C) [5 >= A] (?,1) 2. f13(A,B,C) -> f13(A,1 + B,C) [5 >= B] (?,1) 3. f21(A,B,C) -> f24(A,1,C) [5 >= A] (?,1) 4. f24(A,B,C) -> f27(A,B,1) [5 >= B] (?,1) 5. f27(A,B,C) -> f27(A,B,1 + C) [5 >= C] (?,1) 6. f27(A,B,C) -> f24(A,1 + B,C) [C >= 6] (?,1) 7. f24(A,B,C) -> f21(1 + A,B,C) [B >= 6] (?,1) 8. f21(A,B,C) -> f39(A,B,C) [A >= 6] (?,1) 9. f13(A,B,C) -> f10(1 + A,B,C) [B >= 6] (?,1) 10. f10(A,B,C) -> f21(1,B,C) [A >= 6] (?,1) Signature: {(f0,3);(f10,3);(f13,3);(f21,3);(f24,3);(f27,3);(f39,3)} Flow Graph: [0->{1},1->{2},2->{2,9},3->{4},4->{5},5->{5,6},6->{4,7},7->{3,8},8->{},9->{1,10},10->{3}] + Applied Processor: FromIts + Details: () * Step 3: Decompose YES + Considered Problem: Rules: f0(A,B,C) -> f10(1,B,C) True f10(A,B,C) -> f13(A,1,C) [5 >= A] f13(A,B,C) -> f13(A,1 + B,C) [5 >= B] f21(A,B,C) -> f24(A,1,C) [5 >= A] f24(A,B,C) -> f27(A,B,1) [5 >= B] f27(A,B,C) -> f27(A,B,1 + C) [5 >= C] f27(A,B,C) -> f24(A,1 + B,C) [C >= 6] f24(A,B,C) -> f21(1 + A,B,C) [B >= 6] f21(A,B,C) -> f39(A,B,C) [A >= 6] f13(A,B,C) -> f10(1 + A,B,C) [B >= 6] f10(A,B,C) -> f21(1,B,C) [A >= 6] Signature: {(f0,3);(f10,3);(f13,3);(f21,3);(f24,3);(f27,3);(f39,3)} Rule Graph: [0->{1},1->{2},2->{2,9},3->{4},4->{5},5->{5,6},6->{4,7},7->{3,8},8->{},9->{1,10},10->{3}] + Applied Processor: Decompose NoGreedy + Details: We construct a looptree: P: [0,1,2,3,4,5,6,7,8,9,10] | +- p:[1,9,2] c: [1,9] | | | `- p:[2] c: [2] | `- p:[3,7,6,5,4] c: [3,7] | `- p:[4,6,5] c: [4,6] | `- p:[5] c: [5] * Step 4: CloseWith YES + Considered Problem: (Rules: f0(A,B,C) -> f10(1,B,C) True f10(A,B,C) -> f13(A,1,C) [5 >= A] f13(A,B,C) -> f13(A,1 + B,C) [5 >= B] f21(A,B,C) -> f24(A,1,C) [5 >= A] f24(A,B,C) -> f27(A,B,1) [5 >= B] f27(A,B,C) -> f27(A,B,1 + C) [5 >= C] f27(A,B,C) -> f24(A,1 + B,C) [C >= 6] f24(A,B,C) -> f21(1 + A,B,C) [B >= 6] f21(A,B,C) -> f39(A,B,C) [A >= 6] f13(A,B,C) -> f10(1 + A,B,C) [B >= 6] f10(A,B,C) -> f21(1,B,C) [A >= 6] Signature: {(f0,3);(f10,3);(f13,3);(f21,3);(f24,3);(f27,3);(f39,3)} Rule Graph: [0->{1},1->{2},2->{2,9},3->{4},4->{5},5->{5,6},6->{4,7},7->{3,8},8->{},9->{1,10},10->{3}] ,We construct a looptree: P: [0,1,2,3,4,5,6,7,8,9,10] | +- p:[1,9,2] c: [1,9] | | | `- p:[2] c: [2] | `- p:[3,7,6,5,4] c: [3,7] | `- p:[4,6,5] c: [4,6] | `- p:[5] c: [5]) + Applied Processor: CloseWith True + Details: () YES