YES * Step 1: UnsatPaths YES + Considered Problem: Rules: 0. f0(A,B,C) -> f1(A,B,2) [A >= 0 && 3 >= A && 3 >= B && B >= 0] (1,1) 1. f1(A,B,C) -> f1(A,1 + B,C) [A + C >= 1 + 2*B] (?,1) 2. f1(A,B,C) -> f1(A,-1 + B,C) [2*B >= 2 + A + C] (?,1) Signature: {(f0,3);(f1,3)} Flow Graph: [0->{1,2},1->{1,2},2->{1,2}] + Applied Processor: UnsatPaths + Details: We remove following edges from the transition graph: [(1,2),(2,1)] * Step 2: FromIts YES + Considered Problem: Rules: 0. f0(A,B,C) -> f1(A,B,2) [A >= 0 && 3 >= A && 3 >= B && B >= 0] (1,1) 1. f1(A,B,C) -> f1(A,1 + B,C) [A + C >= 1 + 2*B] (?,1) 2. f1(A,B,C) -> f1(A,-1 + B,C) [2*B >= 2 + A + C] (?,1) Signature: {(f0,3);(f1,3)} Flow Graph: [0->{1,2},1->{1},2->{2}] + Applied Processor: FromIts + Details: () * Step 3: Decompose YES + Considered Problem: Rules: f0(A,B,C) -> f1(A,B,2) [A >= 0 && 3 >= A && 3 >= B && B >= 0] f1(A,B,C) -> f1(A,1 + B,C) [A + C >= 1 + 2*B] f1(A,B,C) -> f1(A,-1 + B,C) [2*B >= 2 + A + C] Signature: {(f0,3);(f1,3)} Rule Graph: [0->{1,2},1->{1},2->{2}] + Applied Processor: Decompose NoGreedy + Details: We construct a looptree: P: [0,1,2] | +- p:[2] c: [2] | `- p:[1] c: [1] * Step 4: CloseWith YES + Considered Problem: (Rules: f0(A,B,C) -> f1(A,B,2) [A >= 0 && 3 >= A && 3 >= B && B >= 0] f1(A,B,C) -> f1(A,1 + B,C) [A + C >= 1 + 2*B] f1(A,B,C) -> f1(A,-1 + B,C) [2*B >= 2 + A + C] Signature: {(f0,3);(f1,3)} Rule Graph: [0->{1,2},1->{1},2->{2}] ,We construct a looptree: P: [0,1,2] | +- p:[2] c: [2] | `- p:[1] c: [1]) + Applied Processor: CloseWith True + Details: () YES