YES
* Step 1: UnsatPaths YES
    + Considered Problem:
        Rules:
          0. f0(A,B,C,D) -> f8(0,B,C,D)         True                   (1,1)
          1. f8(A,B,C,D) -> f8(1 + A,B,C,D)     [3 >= A]               (?,1)
          2. f8(A,B,C,D) -> f8(1 + A,A,1 + A,E) [3 >= A]               (?,1)
          3. f8(A,B,C,D) -> f23(A,B,C,D)        [A >= 4 && 0 >= 1 + E] (?,1)
          4. f8(A,B,C,D) -> f23(A,B,C,D)        [A >= 4]               (?,1)
        Signature:
          {(f0,4);(f23,4);(f8,4)}
        Flow Graph:
          [0->{1,2,3,4},1->{1,2,3,4},2->{1,2,3,4},3->{},4->{}]
        
    + Applied Processor:
        UnsatPaths
    + Details:
        We remove following edges from the transition graph: [(0,3),(0,4)]
* Step 2: FromIts YES
    + Considered Problem:
        Rules:
          0. f0(A,B,C,D) -> f8(0,B,C,D)         True                   (1,1)
          1. f8(A,B,C,D) -> f8(1 + A,B,C,D)     [3 >= A]               (?,1)
          2. f8(A,B,C,D) -> f8(1 + A,A,1 + A,E) [3 >= A]               (?,1)
          3. f8(A,B,C,D) -> f23(A,B,C,D)        [A >= 4 && 0 >= 1 + E] (?,1)
          4. f8(A,B,C,D) -> f23(A,B,C,D)        [A >= 4]               (?,1)
        Signature:
          {(f0,4);(f23,4);(f8,4)}
        Flow Graph:
          [0->{1,2},1->{1,2,3,4},2->{1,2,3,4},3->{},4->{}]
        
    + Applied Processor:
        FromIts
    + Details:
        ()
* Step 3: Decompose YES
    + Considered Problem:
        Rules:
          f0(A,B,C,D) -> f8(0,B,C,D)          True
          f8(A,B,C,D) -> f8(1 + A,B,C,D)      [3 >= A]
          f8(A,B,C,D) -> f8(1 + A,A,1 + A,E)  [3 >= A]
          f8(A,B,C,D) -> f23(A,B,C,D)         [A >= 4 && 0 >= 1 + E]
          f8(A,B,C,D) -> f23(A,B,C,D)         [A >= 4]
        Signature:
          {(f0,4);(f23,4);(f8,4)}
        Rule Graph:
          [0->{1,2},1->{1,2,3,4},2->{1,2,3,4},3->{},4->{}]
    + Applied Processor:
        Decompose NoGreedy
    + Details:
        We construct a looptree:
          P: [0,1,2,3,4]
          |
          `- p:[1,2] c: [2]
             |
             `- p:[1] c: [1]
* Step 4: CloseWith YES
    + Considered Problem:
        (Rules:
          f0(A,B,C,D) -> f8(0,B,C,D)          True
          f8(A,B,C,D) -> f8(1 + A,B,C,D)      [3 >= A]
          f8(A,B,C,D) -> f8(1 + A,A,1 + A,E)  [3 >= A]
          f8(A,B,C,D) -> f23(A,B,C,D)         [A >= 4 && 0 >= 1 + E]
          f8(A,B,C,D) -> f23(A,B,C,D)         [A >= 4]
        Signature:
          {(f0,4);(f23,4);(f8,4)}
        Rule Graph:
          [0->{1,2},1->{1,2,3,4},2->{1,2,3,4},3->{},4->{}]
        ,We construct a looptree:
          P: [0,1,2,3,4]
          |
          `- p:[1,2] c: [2]
             |
             `- p:[1] c: [1])
    + Applied Processor:
        CloseWith True
    + Details:
        ()

YES