YES * Step 1: UnsatRules YES + Considered Problem: Rules: 0. start(A,B,C,D,E,F,G,H) -> stop(A,B,C,D,0,F,D,H) [0 >= A && B = C && D = A && E = F && G = H] (?,1) 1. start(A,B,C,D,E,F,G,H) -> cut(A,B,C,D,0,F,-1 + D,H) [A >= 2 && B = C && D = A && E = F && G = H] (?,1) 2. start(A,B,C,D,E,F,G,H) -> stop(A,B,C,D,0,F,-1 + D,H) [D = 1 && B = C && A = 1 && E = F && G = H] (?,1) 3. start(A,B,C,D,E,F,G,H) -> cut(A,0,C,D,1,F,-1 + D,H) [A >= 2 && B = C && D = A && E = F && G = H] (?,1) 4. start(A,B,C,D,E,F,G,H) -> stop(A,0,C,D,0,F,-1 + D,H) [D = 1 && B = C && A = 1 && E = F && G = H] (?,1) 5. cut(A,B,C,D,E,F,G,H) -> cut(A,B,C,D,-1 + E,F,-1 + G,H) [G >= 2 && E >= 2 && G >= 1 && E >= 0 && A >= 1 + G && A >= E + G && D = A] (?,1) 6. cut(A,B,C,D,E,F,G,H) -> stop(A,B,C,D,-1 + E,F,-1 + G,H) [E >= 2 && E >= 0 && A >= 2 && A >= 1 + E && G = 1 && D = A] (?,1) 7. cut(A,B,C,D,E,F,G,H) -> cut(A,B,C,D,0,F,-1 + G,H) [G >= 2 && 1 >= E && G >= 1 && E >= 0 && A >= 1 + G && A >= E + G && D = A] (?,1) 8. cut(A,B,C,D,E,F,G,H) -> stop(A,B,C,D,0,F,-1 + G,H) [1 >= E && E >= 0 && A >= 2 && A >= 1 + E && G = 1 && D = A] (?,1) 9. cut(A,B,C,D,E,F,G,H) -> cut(A,E,C,D,1 + E,F,-1 + G,H) [G >= 2 && A >= 2 + E && G >= 1 && E >= 0 && A >= 1 + G && A >= E + G && D = A] (?,1) 10. cut(A,B,C,D,E,F,G,H) -> stop(A,E,C,D,1 + E,F,-1 + G,H) [A >= 2 + E && E >= 0 && A >= 2 && A >= 1 + E && G = 1 && D = A] (?,1) 11. cut(A,B,C,D,E,F,G,H) -> cut(A,E,C,D,0,F,-1 + G,H) [G >= 2 && 1 + E >= A && G >= 1 && E >= 0 && A >= 1 + G && A >= E + G && D = A] (?,1) 12. cut(A,B,C,D,E,F,G,H) -> stop(A,E,C,D,0,F,-1 + G,H) [A >= 1 && A >= 2 && G = 1 && 1 + E = A && D = A] (?,1) 13. start0(A,B,C,D,E,F,G,H) -> start(A,C,C,A,F,F,H,H) True (1,1) Signature: {(cut,8);(start,8);(start0,8);(stop,8)} Flow Graph: [0->{},1->{5,6,7,8,9,10,11,12},2->{},3->{5,6,7,8,9,10,11,12},4->{},5->{5,6,7,8,9,10,11,12},6->{},7->{5,6,7 ,8,9,10,11,12},8->{},9->{5,6,7,8,9,10,11,12},10->{},11->{5,6,7,8,9,10,11,12},12->{},13->{0,1,2,3,4}] + Applied Processor: UnsatRules + Details: Following transitions have unsatisfiable constraints and are removed: [11] * Step 2: UnsatPaths YES + Considered Problem: Rules: 0. start(A,B,C,D,E,F,G,H) -> stop(A,B,C,D,0,F,D,H) [0 >= A && B = C && D = A && E = F && G = H] (?,1) 1. start(A,B,C,D,E,F,G,H) -> cut(A,B,C,D,0,F,-1 + D,H) [A >= 2 && B = C && D = A && E = F && G = H] (?,1) 2. start(A,B,C,D,E,F,G,H) -> stop(A,B,C,D,0,F,-1 + D,H) [D = 1 && B = C && A = 1 && E = F && G = H] (?,1) 3. start(A,B,C,D,E,F,G,H) -> cut(A,0,C,D,1,F,-1 + D,H) [A >= 2 && B = C && D = A && E = F && G = H] (?,1) 4. start(A,B,C,D,E,F,G,H) -> stop(A,0,C,D,0,F,-1 + D,H) [D = 1 && B = C && A = 1 && E = F && G = H] (?,1) 5. cut(A,B,C,D,E,F,G,H) -> cut(A,B,C,D,-1 + E,F,-1 + G,H) [G >= 2 && E >= 2 && G >= 1 && E >= 0 && A >= 1 + G && A >= E + G && D = A] (?,1) 6. cut(A,B,C,D,E,F,G,H) -> stop(A,B,C,D,-1 + E,F,-1 + G,H) [E >= 2 && E >= 0 && A >= 2 && A >= 1 + E && G = 1 && D = A] (?,1) 7. cut(A,B,C,D,E,F,G,H) -> cut(A,B,C,D,0,F,-1 + G,H) [G >= 2 && 1 >= E && G >= 1 && E >= 0 && A >= 1 + G && A >= E + G && D = A] (?,1) 8. cut(A,B,C,D,E,F,G,H) -> stop(A,B,C,D,0,F,-1 + G,H) [1 >= E && E >= 0 && A >= 2 && A >= 1 + E && G = 1 && D = A] (?,1) 9. cut(A,B,C,D,E,F,G,H) -> cut(A,E,C,D,1 + E,F,-1 + G,H) [G >= 2 && A >= 2 + E && G >= 1 && E >= 0 && A >= 1 + G && A >= E + G && D = A] (?,1) 10. cut(A,B,C,D,E,F,G,H) -> stop(A,E,C,D,1 + E,F,-1 + G,H) [A >= 2 + E && E >= 0 && A >= 2 && A >= 1 + E && G = 1 && D = A] (?,1) 12. cut(A,B,C,D,E,F,G,H) -> stop(A,E,C,D,0,F,-1 + G,H) [A >= 1 && A >= 2 && G = 1 && 1 + E = A && D = A] (?,1) 13. start0(A,B,C,D,E,F,G,H) -> start(A,C,C,A,F,F,H,H) True (1,1) Signature: {(cut,8);(start,8);(start0,8);(stop,8)} Flow Graph: [0->{},1->{5,6,7,8,9,10,12},2->{},3->{5,6,7,8,9,10,12},4->{},5->{5,6,7,8,9,10,12},6->{},7->{5,6,7,8,9,10 ,12},8->{},9->{5,6,7,8,9,10,12},10->{},12->{},13->{0,1,2,3,4}] + Applied Processor: UnsatPaths + Details: We remove following edges from the transition graph: [(1,5) ,(1,6) ,(1,12) ,(3,5) ,(3,6) ,(3,10) ,(5,12) ,(7,5) ,(7,6) ,(7,12)] * Step 3: FromIts YES + Considered Problem: Rules: 0. start(A,B,C,D,E,F,G,H) -> stop(A,B,C,D,0,F,D,H) [0 >= A && B = C && D = A && E = F && G = H] (?,1) 1. start(A,B,C,D,E,F,G,H) -> cut(A,B,C,D,0,F,-1 + D,H) [A >= 2 && B = C && D = A && E = F && G = H] (?,1) 2. start(A,B,C,D,E,F,G,H) -> stop(A,B,C,D,0,F,-1 + D,H) [D = 1 && B = C && A = 1 && E = F && G = H] (?,1) 3. start(A,B,C,D,E,F,G,H) -> cut(A,0,C,D,1,F,-1 + D,H) [A >= 2 && B = C && D = A && E = F && G = H] (?,1) 4. start(A,B,C,D,E,F,G,H) -> stop(A,0,C,D,0,F,-1 + D,H) [D = 1 && B = C && A = 1 && E = F && G = H] (?,1) 5. cut(A,B,C,D,E,F,G,H) -> cut(A,B,C,D,-1 + E,F,-1 + G,H) [G >= 2 && E >= 2 && G >= 1 && E >= 0 && A >= 1 + G && A >= E + G && D = A] (?,1) 6. cut(A,B,C,D,E,F,G,H) -> stop(A,B,C,D,-1 + E,F,-1 + G,H) [E >= 2 && E >= 0 && A >= 2 && A >= 1 + E && G = 1 && D = A] (?,1) 7. cut(A,B,C,D,E,F,G,H) -> cut(A,B,C,D,0,F,-1 + G,H) [G >= 2 && 1 >= E && G >= 1 && E >= 0 && A >= 1 + G && A >= E + G && D = A] (?,1) 8. cut(A,B,C,D,E,F,G,H) -> stop(A,B,C,D,0,F,-1 + G,H) [1 >= E && E >= 0 && A >= 2 && A >= 1 + E && G = 1 && D = A] (?,1) 9. cut(A,B,C,D,E,F,G,H) -> cut(A,E,C,D,1 + E,F,-1 + G,H) [G >= 2 && A >= 2 + E && G >= 1 && E >= 0 && A >= 1 + G && A >= E + G && D = A] (?,1) 10. cut(A,B,C,D,E,F,G,H) -> stop(A,E,C,D,1 + E,F,-1 + G,H) [A >= 2 + E && E >= 0 && A >= 2 && A >= 1 + E && G = 1 && D = A] (?,1) 12. cut(A,B,C,D,E,F,G,H) -> stop(A,E,C,D,0,F,-1 + G,H) [A >= 1 && A >= 2 && G = 1 && 1 + E = A && D = A] (?,1) 13. start0(A,B,C,D,E,F,G,H) -> start(A,C,C,A,F,F,H,H) True (1,1) Signature: {(cut,8);(start,8);(start0,8);(stop,8)} Flow Graph: [0->{},1->{7,8,9,10},2->{},3->{7,8,9,12},4->{},5->{5,6,7,8,9,10},6->{},7->{7,8,9,10},8->{},9->{5,6,7,8,9 ,10,12},10->{},12->{},13->{0,1,2,3,4}] + Applied Processor: FromIts + Details: () * Step 4: Decompose YES + Considered Problem: Rules: start(A,B,C,D,E,F,G,H) -> stop(A,B,C,D,0,F,D,H) [0 >= A && B = C && D = A && E = F && G = H] start(A,B,C,D,E,F,G,H) -> cut(A,B,C,D,0,F,-1 + D,H) [A >= 2 && B = C && D = A && E = F && G = H] start(A,B,C,D,E,F,G,H) -> stop(A,B,C,D,0,F,-1 + D,H) [D = 1 && B = C && A = 1 && E = F && G = H] start(A,B,C,D,E,F,G,H) -> cut(A,0,C,D,1,F,-1 + D,H) [A >= 2 && B = C && D = A && E = F && G = H] start(A,B,C,D,E,F,G,H) -> stop(A,0,C,D,0,F,-1 + D,H) [D = 1 && B = C && A = 1 && E = F && G = H] cut(A,B,C,D,E,F,G,H) -> cut(A,B,C,D,-1 + E,F,-1 + G,H) [G >= 2 && E >= 2 && G >= 1 && E >= 0 && A >= 1 + G && A >= E + G && D = A] cut(A,B,C,D,E,F,G,H) -> stop(A,B,C,D,-1 + E,F,-1 + G,H) [E >= 2 && E >= 0 && A >= 2 && A >= 1 + E && G = 1 && D = A] cut(A,B,C,D,E,F,G,H) -> cut(A,B,C,D,0,F,-1 + G,H) [G >= 2 && 1 >= E && G >= 1 && E >= 0 && A >= 1 + G && A >= E + G && D = A] cut(A,B,C,D,E,F,G,H) -> stop(A,B,C,D,0,F,-1 + G,H) [1 >= E && E >= 0 && A >= 2 && A >= 1 + E && G = 1 && D = A] cut(A,B,C,D,E,F,G,H) -> cut(A,E,C,D,1 + E,F,-1 + G,H) [G >= 2 && A >= 2 + E && G >= 1 && E >= 0 && A >= 1 + G && A >= E + G && D = A] cut(A,B,C,D,E,F,G,H) -> stop(A,E,C,D,1 + E,F,-1 + G,H) [A >= 2 + E && E >= 0 && A >= 2 && A >= 1 + E && G = 1 && D = A] cut(A,B,C,D,E,F,G,H) -> stop(A,E,C,D,0,F,-1 + G,H) [A >= 1 && A >= 2 && G = 1 && 1 + E = A && D = A] start0(A,B,C,D,E,F,G,H) -> start(A,C,C,A,F,F,H,H) True Signature: {(cut,8);(start,8);(start0,8);(stop,8)} Rule Graph: [0->{},1->{7,8,9,10},2->{},3->{7,8,9,12},4->{},5->{5,6,7,8,9,10},6->{},7->{7,8,9,10},8->{},9->{5,6,7,8,9 ,10,12},10->{},12->{},13->{0,1,2,3,4}] + Applied Processor: Decompose NoGreedy + Details: We construct a looptree: P: [0,1,2,3,4,5,6,7,8,9,10,12,13] | `- p:[7,5,9] c: [9] | +- p:[5] c: [5] | `- p:[7] c: [7] * Step 5: CloseWith YES + Considered Problem: (Rules: start(A,B,C,D,E,F,G,H) -> stop(A,B,C,D,0,F,D,H) [0 >= A && B = C && D = A && E = F && G = H] start(A,B,C,D,E,F,G,H) -> cut(A,B,C,D,0,F,-1 + D,H) [A >= 2 && B = C && D = A && E = F && G = H] start(A,B,C,D,E,F,G,H) -> stop(A,B,C,D,0,F,-1 + D,H) [D = 1 && B = C && A = 1 && E = F && G = H] start(A,B,C,D,E,F,G,H) -> cut(A,0,C,D,1,F,-1 + D,H) [A >= 2 && B = C && D = A && E = F && G = H] start(A,B,C,D,E,F,G,H) -> stop(A,0,C,D,0,F,-1 + D,H) [D = 1 && B = C && A = 1 && E = F && G = H] cut(A,B,C,D,E,F,G,H) -> cut(A,B,C,D,-1 + E,F,-1 + G,H) [G >= 2 && E >= 2 && G >= 1 && E >= 0 && A >= 1 + G && A >= E + G && D = A] cut(A,B,C,D,E,F,G,H) -> stop(A,B,C,D,-1 + E,F,-1 + G,H) [E >= 2 && E >= 0 && A >= 2 && A >= 1 + E && G = 1 && D = A] cut(A,B,C,D,E,F,G,H) -> cut(A,B,C,D,0,F,-1 + G,H) [G >= 2 && 1 >= E && G >= 1 && E >= 0 && A >= 1 + G && A >= E + G && D = A] cut(A,B,C,D,E,F,G,H) -> stop(A,B,C,D,0,F,-1 + G,H) [1 >= E && E >= 0 && A >= 2 && A >= 1 + E && G = 1 && D = A] cut(A,B,C,D,E,F,G,H) -> cut(A,E,C,D,1 + E,F,-1 + G,H) [G >= 2 && A >= 2 + E && G >= 1 && E >= 0 && A >= 1 + G && A >= E + G && D = A] cut(A,B,C,D,E,F,G,H) -> stop(A,E,C,D,1 + E,F,-1 + G,H) [A >= 2 + E && E >= 0 && A >= 2 && A >= 1 + E && G = 1 && D = A] cut(A,B,C,D,E,F,G,H) -> stop(A,E,C,D,0,F,-1 + G,H) [A >= 1 && A >= 2 && G = 1 && 1 + E = A && D = A] start0(A,B,C,D,E,F,G,H) -> start(A,C,C,A,F,F,H,H) True Signature: {(cut,8);(start,8);(start0,8);(stop,8)} Rule Graph: [0->{},1->{7,8,9,10},2->{},3->{7,8,9,12},4->{},5->{5,6,7,8,9,10},6->{},7->{7,8,9,10},8->{},9->{5,6,7,8,9 ,10,12},10->{},12->{},13->{0,1,2,3,4}] ,We construct a looptree: P: [0,1,2,3,4,5,6,7,8,9,10,12,13] | `- p:[7,5,9] c: [9] | +- p:[5] c: [5] | `- p:[7] c: [7]) + Applied Processor: CloseWith True + Details: () YES