YES
* Step 1: UnsatRules YES
    + Considered Problem:
        Rules:
          0. start(A,B,C,D,E,F)  -> lbl71(A,B,1,D,0,F)     [A >= 2 && B = A && C = D && E = F]                                   (?,1)
          1. start(A,B,C,D,E,F)  -> stop(A,B,0,D,1,F)      [1 >= A && B = A && C = D && E = F]                                   (?,1)
          2. lbl71(A,B,C,D,E,F)  -> lbl71(A,B,1 + C,D,E,F) [A >= 2 + C && A >= 1 + C && A >= 2 + E && C >= 1 && E >= 0 && B = A] (?,1)
          3. lbl71(A,B,C,D,E,F)  -> cut(A,B,C,D,1 + E,F)   [A >= 3 + E && A >= 2 + E && A >= 2 && E >= 0 && 1 + C = A && B = A]  (?,1)
          4. lbl71(A,B,C,D,E,F)  -> stop(A,B,C,D,1 + E,F)  [A >= 2 && 2 + E = A && 1 + C = A && B = A]                           (?,1)
          5. cut(A,B,C,D,E,F)    -> lbl71(A,B,1,D,E,F)     [A >= 2 && A >= 2 + E && E >= 1 && 1 + C = A && B = A]                (?,1)
          6. cut(A,B,C,D,E,F)    -> cut(A,B,0,D,1 + E,F)   [1 >= A && A >= 3 + E && A >= 2 + E && E >= 1 && 1 + C = A && B = A]  (?,1)
          7. cut(A,B,C,D,E,F)    -> stop(A,B,0,D,1 + E,F)  [1 >= A && A >= 3 && 1 + C = A && 2 + E = A && B = A]                 (?,1)
          8. start0(A,B,C,D,E,F) -> start(A,A,D,D,F,F)     True                                                                  (1,1)
        Signature:
          {(cut,6);(lbl71,6);(start,6);(start0,6);(stop,6)}
        Flow Graph:
          [0->{2,3,4},1->{},2->{2,3,4},3->{5,6,7},4->{},5->{2,3,4},6->{5,6,7},7->{},8->{0,1}]
        
    + Applied Processor:
        UnsatRules
    + Details:
        Following transitions have unsatisfiable constraints and are removed:  [6,7]
* Step 2: UnsatPaths YES
    + Considered Problem:
        Rules:
          0. start(A,B,C,D,E,F)  -> lbl71(A,B,1,D,0,F)     [A >= 2 && B = A && C = D && E = F]                                   (?,1)
          1. start(A,B,C,D,E,F)  -> stop(A,B,0,D,1,F)      [1 >= A && B = A && C = D && E = F]                                   (?,1)
          2. lbl71(A,B,C,D,E,F)  -> lbl71(A,B,1 + C,D,E,F) [A >= 2 + C && A >= 1 + C && A >= 2 + E && C >= 1 && E >= 0 && B = A] (?,1)
          3. lbl71(A,B,C,D,E,F)  -> cut(A,B,C,D,1 + E,F)   [A >= 3 + E && A >= 2 + E && A >= 2 && E >= 0 && 1 + C = A && B = A]  (?,1)
          4. lbl71(A,B,C,D,E,F)  -> stop(A,B,C,D,1 + E,F)  [A >= 2 && 2 + E = A && 1 + C = A && B = A]                           (?,1)
          5. cut(A,B,C,D,E,F)    -> lbl71(A,B,1,D,E,F)     [A >= 2 && A >= 2 + E && E >= 1 && 1 + C = A && B = A]                (?,1)
          8. start0(A,B,C,D,E,F) -> start(A,A,D,D,F,F)     True                                                                  (1,1)
        Signature:
          {(cut,6);(lbl71,6);(start,6);(start0,6);(stop,6)}
        Flow Graph:
          [0->{2,3,4},1->{},2->{2,3,4},3->{5},4->{},5->{2,3,4},8->{0,1}]
        
    + Applied Processor:
        UnsatPaths
    + Details:
        We remove following edges from the transition graph: [(0,3),(5,3),(5,4)]
* Step 3: FromIts YES
    + Considered Problem:
        Rules:
          0. start(A,B,C,D,E,F)  -> lbl71(A,B,1,D,0,F)     [A >= 2 && B = A && C = D && E = F]                                   (?,1)
          1. start(A,B,C,D,E,F)  -> stop(A,B,0,D,1,F)      [1 >= A && B = A && C = D && E = F]                                   (?,1)
          2. lbl71(A,B,C,D,E,F)  -> lbl71(A,B,1 + C,D,E,F) [A >= 2 + C && A >= 1 + C && A >= 2 + E && C >= 1 && E >= 0 && B = A] (?,1)
          3. lbl71(A,B,C,D,E,F)  -> cut(A,B,C,D,1 + E,F)   [A >= 3 + E && A >= 2 + E && A >= 2 && E >= 0 && 1 + C = A && B = A]  (?,1)
          4. lbl71(A,B,C,D,E,F)  -> stop(A,B,C,D,1 + E,F)  [A >= 2 && 2 + E = A && 1 + C = A && B = A]                           (?,1)
          5. cut(A,B,C,D,E,F)    -> lbl71(A,B,1,D,E,F)     [A >= 2 && A >= 2 + E && E >= 1 && 1 + C = A && B = A]                (?,1)
          8. start0(A,B,C,D,E,F) -> start(A,A,D,D,F,F)     True                                                                  (1,1)
        Signature:
          {(cut,6);(lbl71,6);(start,6);(start0,6);(stop,6)}
        Flow Graph:
          [0->{2,4},1->{},2->{2,3,4},3->{5},4->{},5->{2},8->{0,1}]
        
    + Applied Processor:
        FromIts
    + Details:
        ()
* Step 4: Decompose YES
    + Considered Problem:
        Rules:
          start(A,B,C,D,E,F)  -> lbl71(A,B,1,D,0,F)      [A >= 2 && B = A && C = D && E = F]
          start(A,B,C,D,E,F)  -> stop(A,B,0,D,1,F)       [1 >= A && B = A && C = D && E = F]
          lbl71(A,B,C,D,E,F)  -> lbl71(A,B,1 + C,D,E,F)  [A >= 2 + C
                                                          && A >= 1 + C
                                                          && A >= 2 + E
                                                          && C >= 1
                                                          && E >= 0
                                                          && B = A]
          lbl71(A,B,C,D,E,F)  -> cut(A,B,C,D,1 + E,F)    [A >= 3 + E
                                                          && A >= 2 + E
                                                          && A >= 2
                                                          && E >= 0
                                                          && 1 + C = A
                                                          && B = A]
          lbl71(A,B,C,D,E,F)  -> stop(A,B,C,D,1 + E,F)   [A >= 2 && 2 + E = A && 1 + C = A && B = A]
          cut(A,B,C,D,E,F)    -> lbl71(A,B,1,D,E,F)      [A >= 2 && A >= 2 + E && E >= 1 && 1 + C = A && B = A]
          start0(A,B,C,D,E,F) -> start(A,A,D,D,F,F)      True
        Signature:
          {(cut,6);(lbl71,6);(start,6);(start0,6);(stop,6)}
        Rule Graph:
          [0->{2,4},1->{},2->{2,3,4},3->{5},4->{},5->{2},8->{0,1}]
    + Applied Processor:
        Decompose NoGreedy
    + Details:
        We construct a looptree:
          P: [0,1,2,3,4,5,8]
          |
          `- p:[2,5,3] c: [3,5]
             |
             `- p:[2] c: [2]
* Step 5: CloseWith YES
    + Considered Problem:
        (Rules:
          start(A,B,C,D,E,F)  -> lbl71(A,B,1,D,0,F)      [A >= 2 && B = A && C = D && E = F]
          start(A,B,C,D,E,F)  -> stop(A,B,0,D,1,F)       [1 >= A && B = A && C = D && E = F]
          lbl71(A,B,C,D,E,F)  -> lbl71(A,B,1 + C,D,E,F)  [A >= 2 + C
                                                          && A >= 1 + C
                                                          && A >= 2 + E
                                                          && C >= 1
                                                          && E >= 0
                                                          && B = A]
          lbl71(A,B,C,D,E,F)  -> cut(A,B,C,D,1 + E,F)    [A >= 3 + E
                                                          && A >= 2 + E
                                                          && A >= 2
                                                          && E >= 0
                                                          && 1 + C = A
                                                          && B = A]
          lbl71(A,B,C,D,E,F)  -> stop(A,B,C,D,1 + E,F)   [A >= 2 && 2 + E = A && 1 + C = A && B = A]
          cut(A,B,C,D,E,F)    -> lbl71(A,B,1,D,E,F)      [A >= 2 && A >= 2 + E && E >= 1 && 1 + C = A && B = A]
          start0(A,B,C,D,E,F) -> start(A,A,D,D,F,F)      True
        Signature:
          {(cut,6);(lbl71,6);(start,6);(start0,6);(stop,6)}
        Rule Graph:
          [0->{2,4},1->{},2->{2,3,4},3->{5},4->{},5->{2},8->{0,1}]
        ,We construct a looptree:
          P: [0,1,2,3,4,5,8]
          |
          `- p:[2,5,3] c: [3,5]
             |
             `- p:[2] c: [2])
    + Applied Processor:
        CloseWith True
    + Details:
        ()

YES