YES
* Step 1: FromIts YES
    + Considered Problem:
        Rules:
          0. start(A,B,C,D)  -> stop1(A,B,C,D)      [A >= 0 && B >= 0 && C >= 0 && D = 0]                      (?,1)
          1. start(A,B,C,D)  -> cont1(A,B,C,D)      [D >= 1 && A >= 0 && B >= 0 && C >= 0 && D >= 0 && A >= D] (?,1)
          2. cont1(A,B,C,D)  -> stop2(A,B,1,-1 + D) [D >= 1 && B >= 0 && A >= D && C = 0]                      (?,1)
          3. cont1(A,B,C,D)  -> a(A,B,-1 + C,D)     [C >= 1 && D >= 1 && C >= 0 && B >= 0 && A >= D]           (?,1)
          4. a(A,B,C,D)      -> b(A,B,E,-1 + D)     [A >= D && B >= 0 && C >= 0 && D >= 1]                     (?,1)
          5. b(A,B,C,D)      -> start(A,B,C,D)      [C >= 0 && D >= 0 && B >= 0 && A >= 1 + D]                 (?,1)
          6. b(A,B,C,D)      -> stop3(A,B,C,D)      [0 >= 1 + C && D >= 0 && B >= 0 && A >= 1 + D]             (?,1)
          7. start0(A,B,C,D) -> start(A,B,B,A)      [A >= 0 && B >= 0]                                         (1,1)
        Signature:
          {(a,4);(b,4);(cont1,4);(start,4);(start0,4);(stop1,4);(stop2,4);(stop3,4)}
        Flow Graph:
          [0->{},1->{2,3},2->{},3->{4},4->{5,6},5->{0,1},6->{},7->{0,1}]
        
    + Applied Processor:
        FromIts
    + Details:
        ()
* Step 2: Decompose YES
    + Considered Problem:
        Rules:
          start(A,B,C,D)  -> stop1(A,B,C,D)       [A >= 0 && B >= 0 && C >= 0 && D = 0]
          start(A,B,C,D)  -> cont1(A,B,C,D)       [D >= 1 && A >= 0 && B >= 0 && C >= 0 && D >= 0 && A >= D]
          cont1(A,B,C,D)  -> stop2(A,B,1,-1 + D)  [D >= 1 && B >= 0 && A >= D && C = 0]
          cont1(A,B,C,D)  -> a(A,B,-1 + C,D)      [C >= 1 && D >= 1 && C >= 0 && B >= 0 && A >= D]
          a(A,B,C,D)      -> b(A,B,E,-1 + D)      [A >= D && B >= 0 && C >= 0 && D >= 1]
          b(A,B,C,D)      -> start(A,B,C,D)       [C >= 0 && D >= 0 && B >= 0 && A >= 1 + D]
          b(A,B,C,D)      -> stop3(A,B,C,D)       [0 >= 1 + C && D >= 0 && B >= 0 && A >= 1 + D]
          start0(A,B,C,D) -> start(A,B,B,A)       [A >= 0 && B >= 0]
        Signature:
          {(a,4);(b,4);(cont1,4);(start,4);(start0,4);(stop1,4);(stop2,4);(stop3,4)}
        Rule Graph:
          [0->{},1->{2,3},2->{},3->{4},4->{5,6},5->{0,1},6->{},7->{0,1}]
    + Applied Processor:
        Decompose NoGreedy
    + Details:
        We construct a looptree:
          P: [0,1,2,3,4,5,6,7]
          |
          `- p:[1,5,4,3] c: [1,3,4,5]
* Step 3: CloseWith YES
    + Considered Problem:
        (Rules:
          start(A,B,C,D)  -> stop1(A,B,C,D)       [A >= 0 && B >= 0 && C >= 0 && D = 0]
          start(A,B,C,D)  -> cont1(A,B,C,D)       [D >= 1 && A >= 0 && B >= 0 && C >= 0 && D >= 0 && A >= D]
          cont1(A,B,C,D)  -> stop2(A,B,1,-1 + D)  [D >= 1 && B >= 0 && A >= D && C = 0]
          cont1(A,B,C,D)  -> a(A,B,-1 + C,D)      [C >= 1 && D >= 1 && C >= 0 && B >= 0 && A >= D]
          a(A,B,C,D)      -> b(A,B,E,-1 + D)      [A >= D && B >= 0 && C >= 0 && D >= 1]
          b(A,B,C,D)      -> start(A,B,C,D)       [C >= 0 && D >= 0 && B >= 0 && A >= 1 + D]
          b(A,B,C,D)      -> stop3(A,B,C,D)       [0 >= 1 + C && D >= 0 && B >= 0 && A >= 1 + D]
          start0(A,B,C,D) -> start(A,B,B,A)       [A >= 0 && B >= 0]
        Signature:
          {(a,4);(b,4);(cont1,4);(start,4);(start0,4);(stop1,4);(stop2,4);(stop3,4)}
        Rule Graph:
          [0->{},1->{2,3},2->{},3->{4},4->{5,6},5->{0,1},6->{},7->{0,1}]
        ,We construct a looptree:
          P: [0,1,2,3,4,5,6,7]
          |
          `- p:[1,5,4,3] c: [1,3,4,5])
    + Applied Processor:
        CloseWith True
    + Details:
        ()

YES