YES
* Step 1: UnsatPaths YES
    + Considered Problem:
        Rules:
          0. div(A,B)   -> end(A,B)        [0 >= A]               (?,1)
          1. div(A,B)   -> end(A,B)        [A >= B]               (?,1)
          2. div(A,B)   -> div(A,-1*A + B) [B >= 1 + A && A >= 1] (?,1)
          3. start(A,B) -> div(A,B)        True                   (1,1)
        Signature:
          {(div,2);(end,2);(start,2)}
        Flow Graph:
          [0->{},1->{},2->{0,1,2},3->{0,1,2}]
        
    + Applied Processor:
        UnsatPaths
    + Details:
        We remove following edges from the transition graph: [(2,0)]
* Step 2: FromIts YES
    + Considered Problem:
        Rules:
          0. div(A,B)   -> end(A,B)        [0 >= A]               (?,1)
          1. div(A,B)   -> end(A,B)        [A >= B]               (?,1)
          2. div(A,B)   -> div(A,-1*A + B) [B >= 1 + A && A >= 1] (?,1)
          3. start(A,B) -> div(A,B)        True                   (1,1)
        Signature:
          {(div,2);(end,2);(start,2)}
        Flow Graph:
          [0->{},1->{},2->{1,2},3->{0,1,2}]
        
    + Applied Processor:
        FromIts
    + Details:
        ()
* Step 3: Decompose YES
    + Considered Problem:
        Rules:
          div(A,B)   -> end(A,B)         [0 >= A]
          div(A,B)   -> end(A,B)         [A >= B]
          div(A,B)   -> div(A,-1*A + B)  [B >= 1 + A && A >= 1]
          start(A,B) -> div(A,B)         True
        Signature:
          {(div,2);(end,2);(start,2)}
        Rule Graph:
          [0->{},1->{},2->{1,2},3->{0,1,2}]
    + Applied Processor:
        Decompose NoGreedy
    + Details:
        We construct a looptree:
          P: [0,1,2,3]
          |
          `- p:[2] c: [2]
* Step 4: CloseWith YES
    + Considered Problem:
        (Rules:
          div(A,B)   -> end(A,B)         [0 >= A]
          div(A,B)   -> end(A,B)         [A >= B]
          div(A,B)   -> div(A,-1*A + B)  [B >= 1 + A && A >= 1]
          start(A,B) -> div(A,B)         True
        Signature:
          {(div,2);(end,2);(start,2)}
        Rule Graph:
          [0->{},1->{},2->{1,2},3->{0,1,2}]
        ,We construct a looptree:
          P: [0,1,2,3]
          |
          `- p:[2] c: [2])
    + Applied Processor:
        CloseWith True
    + Details:
        ()

YES