YES
* Step 1: UnsatPaths YES
    + Considered Problem:
        Rules:
          0. eval(A,B,C,D,E)  -> eval(A,1 + B,C,D,1 + E) [A >= 1 + B && C >= 1 + D] (?,1)
          1. eval(A,B,C,D,E)  -> eval(A,B,C,1 + D,1 + E) [A >= 1 + B && C >= 1 + D] (?,1)
          2. eval(A,B,C,D,E)  -> eval(A,B,C,1 + D,1 + E) [B >= A && C >= 1 + D]     (?,1)
          3. eval(A,B,C,D,E)  -> eval(A,1 + B,C,D,1 + E) [A >= 1 + B && D >= C]     (?,1)
          4. start(A,B,C,D,E) -> eval(A,B,C,D,E)         True                       (1,1)
        Signature:
          {(eval,5);(start,5)}
        Flow Graph:
          [0->{0,1,2,3},1->{0,1,2,3},2->{0,1,2,3},3->{0,1,2,3},4->{0,1,2,3}]
        
    + Applied Processor:
        UnsatPaths
    + Details:
        We remove following edges from the transition graph: [(0,3),(1,2),(2,0),(2,1),(2,3),(3,0),(3,1),(3,2)]
* Step 2: FromIts YES
    + Considered Problem:
        Rules:
          0. eval(A,B,C,D,E)  -> eval(A,1 + B,C,D,1 + E) [A >= 1 + B && C >= 1 + D] (?,1)
          1. eval(A,B,C,D,E)  -> eval(A,B,C,1 + D,1 + E) [A >= 1 + B && C >= 1 + D] (?,1)
          2. eval(A,B,C,D,E)  -> eval(A,B,C,1 + D,1 + E) [B >= A && C >= 1 + D]     (?,1)
          3. eval(A,B,C,D,E)  -> eval(A,1 + B,C,D,1 + E) [A >= 1 + B && D >= C]     (?,1)
          4. start(A,B,C,D,E) -> eval(A,B,C,D,E)         True                       (1,1)
        Signature:
          {(eval,5);(start,5)}
        Flow Graph:
          [0->{0,1,2},1->{0,1,3},2->{2},3->{3},4->{0,1,2,3}]
        
    + Applied Processor:
        FromIts
    + Details:
        ()
* Step 3: Decompose YES
    + Considered Problem:
        Rules:
          eval(A,B,C,D,E)  -> eval(A,1 + B,C,D,1 + E)  [A >= 1 + B && C >= 1 + D]
          eval(A,B,C,D,E)  -> eval(A,B,C,1 + D,1 + E)  [A >= 1 + B && C >= 1 + D]
          eval(A,B,C,D,E)  -> eval(A,B,C,1 + D,1 + E)  [B >= A && C >= 1 + D]
          eval(A,B,C,D,E)  -> eval(A,1 + B,C,D,1 + E)  [A >= 1 + B && D >= C]
          start(A,B,C,D,E) -> eval(A,B,C,D,E)          True
        Signature:
          {(eval,5);(start,5)}
        Rule Graph:
          [0->{0,1,2},1->{0,1,3},2->{2},3->{3},4->{0,1,2,3}]
    + Applied Processor:
        Decompose NoGreedy
    + Details:
        We construct a looptree:
          P: [0,1,2,3,4]
          |
          +- p:[0,1] c: [1]
          |  |
          |  `- p:[0] c: [0]
          |
          +- p:[2] c: [2]
          |
          `- p:[3] c: [3]
* Step 4: CloseWith YES
    + Considered Problem:
        (Rules:
          eval(A,B,C,D,E)  -> eval(A,1 + B,C,D,1 + E)  [A >= 1 + B && C >= 1 + D]
          eval(A,B,C,D,E)  -> eval(A,B,C,1 + D,1 + E)  [A >= 1 + B && C >= 1 + D]
          eval(A,B,C,D,E)  -> eval(A,B,C,1 + D,1 + E)  [B >= A && C >= 1 + D]
          eval(A,B,C,D,E)  -> eval(A,1 + B,C,D,1 + E)  [A >= 1 + B && D >= C]
          start(A,B,C,D,E) -> eval(A,B,C,D,E)          True
        Signature:
          {(eval,5);(start,5)}
        Rule Graph:
          [0->{0,1,2},1->{0,1,3},2->{2},3->{3},4->{0,1,2,3}]
        ,We construct a looptree:
          P: [0,1,2,3,4]
          |
          +- p:[0,1] c: [1]
          |  |
          |  `- p:[0] c: [0]
          |
          +- p:[2] c: [2]
          |
          `- p:[3] c: [3])
    + Applied Processor:
        CloseWith True
    + Details:
        ()

YES