NO * Step 1: FromIts NO + Considered Problem: Rules: 0. eval(A) -> eval(B) [A >= 0 && 2*A + B >= 10 && 10 >= 2*A + B] (?,1) 1. start(A) -> eval(A) True (1,1) Signature: {(eval,1);(start,1)} Flow Graph: [0->{0},1->{0}] + Applied Processor: FromIts + Details: () * Step 2: CloseWith NO + Considered Problem: Rules: eval(A) -> eval(B) [A >= 0 && 2*A + B >= 10 && 10 >= 2*A + B] start(A) -> eval(A) True Signature: {(eval,1);(start,1)} Rule Graph: [0->{0},1->{0}] + Applied Processor: CloseWith False + Details: () NO