YES
* Step 1: FromIts YES
    + Considered Problem:
        Rules:
          0. evalSimpleSinglestart(A,B)    -> evalSimpleSingleentryin(A,B)   True                                                             (1,1)
          1. evalSimpleSingleentryin(A,B)  -> evalSimpleSinglebb3in(0,B)     True                                                             (?,1)
          2. evalSimpleSinglebb3in(A,B)    -> evalSimpleSinglebbin(A,B)      [A >= 0 && B >= 1 + A]                                           (?,1)
          3. evalSimpleSinglebb3in(A,B)    -> evalSimpleSinglereturnin(A,B)  [A >= 0 && A >= B]                                               (?,1)
          4. evalSimpleSinglebbin(A,B)     -> evalSimpleSinglebb3in(1 + A,B) [-1 + B >= 0 && -1 + A + B >= 0 && -1 + -1*A + B >= 0 && A >= 0] (?,1)
          5. evalSimpleSinglereturnin(A,B) -> evalSimpleSinglestop(A,B)      [A + -1*B >= 0 && A >= 0]                                        (?,1)
        Signature:
          {(evalSimpleSinglebb3in,2)
          ;(evalSimpleSinglebbin,2)
          ;(evalSimpleSingleentryin,2)
          ;(evalSimpleSinglereturnin,2)
          ;(evalSimpleSinglestart,2)
          ;(evalSimpleSinglestop,2)}
        Flow Graph:
          [0->{1},1->{2,3},2->{4},3->{5},4->{2,3},5->{}]
        
    + Applied Processor:
        FromIts
    + Details:
        ()
* Step 2: Decompose YES
    + Considered Problem:
        Rules:
          evalSimpleSinglestart(A,B)    -> evalSimpleSingleentryin(A,B)    True
          evalSimpleSingleentryin(A,B)  -> evalSimpleSinglebb3in(0,B)      True
          evalSimpleSinglebb3in(A,B)    -> evalSimpleSinglebbin(A,B)       [A >= 0 && B >= 1 + A]
          evalSimpleSinglebb3in(A,B)    -> evalSimpleSinglereturnin(A,B)   [A >= 0 && A >= B]
          evalSimpleSinglebbin(A,B)     -> evalSimpleSinglebb3in(1 + A,B)  [-1 + B >= 0
                                                                            && -1 + A + B >= 0
                                                                            && -1 + -1*A + B >= 0
                                                                            && A >= 0]
          evalSimpleSinglereturnin(A,B) -> evalSimpleSinglestop(A,B)       [A + -1*B >= 0 && A >= 0]
        Signature:
          {(evalSimpleSinglebb3in,2)
          ;(evalSimpleSinglebbin,2)
          ;(evalSimpleSingleentryin,2)
          ;(evalSimpleSinglereturnin,2)
          ;(evalSimpleSinglestart,2)
          ;(evalSimpleSinglestop,2)}
        Rule Graph:
          [0->{1},1->{2,3},2->{4},3->{5},4->{2,3},5->{}]
    + Applied Processor:
        Decompose NoGreedy
    + Details:
        We construct a looptree:
          P: [0,1,2,3,4,5]
          |
          `- p:[2,4] c: [2,4]
* Step 3: CloseWith YES
    + Considered Problem:
        (Rules:
          evalSimpleSinglestart(A,B)    -> evalSimpleSingleentryin(A,B)    True
          evalSimpleSingleentryin(A,B)  -> evalSimpleSinglebb3in(0,B)      True
          evalSimpleSinglebb3in(A,B)    -> evalSimpleSinglebbin(A,B)       [A >= 0 && B >= 1 + A]
          evalSimpleSinglebb3in(A,B)    -> evalSimpleSinglereturnin(A,B)   [A >= 0 && A >= B]
          evalSimpleSinglebbin(A,B)     -> evalSimpleSinglebb3in(1 + A,B)  [-1 + B >= 0
                                                                            && -1 + A + B >= 0
                                                                            && -1 + -1*A + B >= 0
                                                                            && A >= 0]
          evalSimpleSinglereturnin(A,B) -> evalSimpleSinglestop(A,B)       [A + -1*B >= 0 && A >= 0]
        Signature:
          {(evalSimpleSinglebb3in,2)
          ;(evalSimpleSinglebbin,2)
          ;(evalSimpleSingleentryin,2)
          ;(evalSimpleSinglereturnin,2)
          ;(evalSimpleSinglestart,2)
          ;(evalSimpleSinglestop,2)}
        Rule Graph:
          [0->{1},1->{2,3},2->{4},3->{5},4->{2,3},5->{}]
        ,We construct a looptree:
          P: [0,1,2,3,4,5]
          |
          `- p:[2,4] c: [2,4])
    + Applied Processor:
        CloseWith True
    + Details:
        ()

YES