YES
* Step 1: UnsatPaths YES
    + Considered Problem:
        Rules:
          0. evalfstart(A,B,C)    -> evalfentryin(A,B,C)    True                                            (1,1)
          1. evalfentryin(A,B,C)  -> evalfbb4in(B,A,C)      True                                            (?,1)
          2. evalfbb4in(A,B,C)    -> evalfbb2in(A,B,A)      [B >= 1]                                        (?,1)
          3. evalfbb4in(A,B,C)    -> evalfreturnin(A,B,C)   [0 >= B]                                        (?,1)
          4. evalfbb2in(A,B,C)    -> evalfbb1in(A,B,C)      [A + -1*C >= 0 && -1 + B >= 0 && C >= A]        (?,1)
          5. evalfbb2in(A,B,C)    -> evalfbb3in(A,B,C)      [A + -1*C >= 0 && -1 + B >= 0 && A >= 1 + C]    (?,1)
          6. evalfbb1in(A,B,C)    -> evalfbb2in(A,B,-1 + C) [A + -1*C >= 0 && -1*A + C >= 0 && -1 + B >= 0] (?,1)
          7. evalfbb3in(A,B,C)    -> evalfbb4in(A,-1 + B,C) [-1 + A + -1*C >= 0 && -1 + B >= 0]             (?,1)
          8. evalfreturnin(A,B,C) -> evalfstop(A,B,C)       [-1*B >= 0]                                     (?,1)
        Signature:
          {(evalfbb1in,3)
          ;(evalfbb2in,3)
          ;(evalfbb3in,3)
          ;(evalfbb4in,3)
          ;(evalfentryin,3)
          ;(evalfreturnin,3)
          ;(evalfstart,3)
          ;(evalfstop,3)}
        Flow Graph:
          [0->{1},1->{2,3},2->{4,5},3->{8},4->{6},5->{7},6->{4,5},7->{2,3},8->{}]
        
    + Applied Processor:
        UnsatPaths
    + Details:
        We remove following edges from the transition graph: [(2,5),(6,4)]
* Step 2: FromIts YES
    + Considered Problem:
        Rules:
          0. evalfstart(A,B,C)    -> evalfentryin(A,B,C)    True                                            (1,1)
          1. evalfentryin(A,B,C)  -> evalfbb4in(B,A,C)      True                                            (?,1)
          2. evalfbb4in(A,B,C)    -> evalfbb2in(A,B,A)      [B >= 1]                                        (?,1)
          3. evalfbb4in(A,B,C)    -> evalfreturnin(A,B,C)   [0 >= B]                                        (?,1)
          4. evalfbb2in(A,B,C)    -> evalfbb1in(A,B,C)      [A + -1*C >= 0 && -1 + B >= 0 && C >= A]        (?,1)
          5. evalfbb2in(A,B,C)    -> evalfbb3in(A,B,C)      [A + -1*C >= 0 && -1 + B >= 0 && A >= 1 + C]    (?,1)
          6. evalfbb1in(A,B,C)    -> evalfbb2in(A,B,-1 + C) [A + -1*C >= 0 && -1*A + C >= 0 && -1 + B >= 0] (?,1)
          7. evalfbb3in(A,B,C)    -> evalfbb4in(A,-1 + B,C) [-1 + A + -1*C >= 0 && -1 + B >= 0]             (?,1)
          8. evalfreturnin(A,B,C) -> evalfstop(A,B,C)       [-1*B >= 0]                                     (?,1)
        Signature:
          {(evalfbb1in,3)
          ;(evalfbb2in,3)
          ;(evalfbb3in,3)
          ;(evalfbb4in,3)
          ;(evalfentryin,3)
          ;(evalfreturnin,3)
          ;(evalfstart,3)
          ;(evalfstop,3)}
        Flow Graph:
          [0->{1},1->{2,3},2->{4},3->{8},4->{6},5->{7},6->{5},7->{2,3},8->{}]
        
    + Applied Processor:
        FromIts
    + Details:
        ()
* Step 3: Decompose YES
    + Considered Problem:
        Rules:
          evalfstart(A,B,C)    -> evalfentryin(A,B,C)     True
          evalfentryin(A,B,C)  -> evalfbb4in(B,A,C)       True
          evalfbb4in(A,B,C)    -> evalfbb2in(A,B,A)       [B >= 1]
          evalfbb4in(A,B,C)    -> evalfreturnin(A,B,C)    [0 >= B]
          evalfbb2in(A,B,C)    -> evalfbb1in(A,B,C)       [A + -1*C >= 0 && -1 + B >= 0 && C >= A]
          evalfbb2in(A,B,C)    -> evalfbb3in(A,B,C)       [A + -1*C >= 0 && -1 + B >= 0 && A >= 1 + C]
          evalfbb1in(A,B,C)    -> evalfbb2in(A,B,-1 + C)  [A + -1*C >= 0 && -1*A + C >= 0 && -1 + B >= 0]
          evalfbb3in(A,B,C)    -> evalfbb4in(A,-1 + B,C)  [-1 + A + -1*C >= 0 && -1 + B >= 0]
          evalfreturnin(A,B,C) -> evalfstop(A,B,C)        [-1*B >= 0]
        Signature:
          {(evalfbb1in,3)
          ;(evalfbb2in,3)
          ;(evalfbb3in,3)
          ;(evalfbb4in,3)
          ;(evalfentryin,3)
          ;(evalfreturnin,3)
          ;(evalfstart,3)
          ;(evalfstop,3)}
        Rule Graph:
          [0->{1},1->{2,3},2->{4},3->{8},4->{6},5->{7},6->{5},7->{2,3},8->{}]
    + Applied Processor:
        Decompose NoGreedy
    + Details:
        We construct a looptree:
          P: [0,1,2,3,4,5,6,7,8]
          |
          `- p:[2,7,5,6,4] c: [2,4,5,6,7]
* Step 4: CloseWith YES
    + Considered Problem:
        (Rules:
          evalfstart(A,B,C)    -> evalfentryin(A,B,C)     True
          evalfentryin(A,B,C)  -> evalfbb4in(B,A,C)       True
          evalfbb4in(A,B,C)    -> evalfbb2in(A,B,A)       [B >= 1]
          evalfbb4in(A,B,C)    -> evalfreturnin(A,B,C)    [0 >= B]
          evalfbb2in(A,B,C)    -> evalfbb1in(A,B,C)       [A + -1*C >= 0 && -1 + B >= 0 && C >= A]
          evalfbb2in(A,B,C)    -> evalfbb3in(A,B,C)       [A + -1*C >= 0 && -1 + B >= 0 && A >= 1 + C]
          evalfbb1in(A,B,C)    -> evalfbb2in(A,B,-1 + C)  [A + -1*C >= 0 && -1*A + C >= 0 && -1 + B >= 0]
          evalfbb3in(A,B,C)    -> evalfbb4in(A,-1 + B,C)  [-1 + A + -1*C >= 0 && -1 + B >= 0]
          evalfreturnin(A,B,C) -> evalfstop(A,B,C)        [-1*B >= 0]
        Signature:
          {(evalfbb1in,3)
          ;(evalfbb2in,3)
          ;(evalfbb3in,3)
          ;(evalfbb4in,3)
          ;(evalfentryin,3)
          ;(evalfreturnin,3)
          ;(evalfstart,3)
          ;(evalfstop,3)}
        Rule Graph:
          [0->{1},1->{2,3},2->{4},3->{8},4->{6},5->{7},6->{5},7->{2,3},8->{}]
        ,We construct a looptree:
          P: [0,1,2,3,4,5,6,7,8]
          |
          `- p:[2,7,5,6,4] c: [2,4,5,6,7])
    + Applied Processor:
        CloseWith True
    + Details:
        ()

YES